Explanation Procedure used: “ Factoring a x 2 + b x + c , a ≠ 1 using trial and error, where a, band c have no common factors: Step 1: List the possibilities for the first terms of each binomial whose product is a x 2 . Step 2: List the possibilities for the last terms of each binomial. Step 3: Write all the combinations of factors found in step 1 and step 2. Multiply the binomials until a product that equals the trinomial is found.” Calculation: The given trinomial is 10 z 2 + 9 z − 9 . The first term of the trinomial can be factorized as, ( 2 z + _ _ _ ) ( 5 z + _ _ _ ) . The product of the second term of the factor, ( 2 z + _ _ _ ) ( 5 z + _ _ _ ) should be –9. List the possibilities for the last terms of each binomial whose product is –9 as shown below in table 1. Factors of –9 1, –9 3, –3 Table 1 Write all the combinations of factors found in above steps. Multiply the binomials until a product that equals the trinomial is found. The second term of each factor ( 2 z + _ _ _ ) ( 5 z + _ _ _ ) has the following possibilities and the product is shown in Table 2

3rd Edition

ISBN: 9780321880116

Author: Michael Sullivan III, Katherine R. Struve, Janet Mazzarella

Publisher: PEARSON

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Chapter 6, Problem 70RE

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To factorize: The polynomial 10z2+9z−9.

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Chapter 6, Problem 69RE

Chapter 6, Problem 71RE

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Chapter 6 Solutions

Elementary & Intermediate Algebra

Ch. 6.1 - The largest polynomial that divides evenly into a...Ch. 6.1 - Prob. 2E Ch. 6.1 - Prob. 3E Ch. 6.1 - Prob. 4E Ch. 6.1 - Prob. 5E Ch. 6.1 - Prob. 6E Ch. 6.1 - Prob. 7E Ch. 6.1 - Prob. 8E Ch. 6.1 - Prob. 9E Ch. 6.1 - Prob. 10E

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To factorize: The polynomial 10 z 2 + 9 z − 9 .

Solution Summary: The author explains how to factorize the polynomial 10z2+9z-9 using trial and error.

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To factorize: The polynomial 10z2+9z−9.

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Chapter 6 Solutions