Explanation Procedure used: “Factoring a x 2 + b x + c , a ≠ 1 using trial and error: Step 1: If there are common factors, then factor out the GCF and obtain the trinomial. Step 2: List the possibilities for the first terms of each binomial whose product is a x 2 . Step 2: List the possibilities for the last terms of each binomial. Step 3: Write all the combinations of factors found in step 1 and step 2. Multiply the binomials until a product that equals the trinomial is found.” Step 4: Check whether the factors satisfies the given polynomial or not.” Calculation: Obtain the factor of the trinomial 2 m 2 − 3 m n − 2 n 2 as follows. It is observed that there are no common factors in the trinomial, 2 m 2 − 3 m n − 2 n 2 . There is only one possibility for the first term 2 m 2 of the trinomial that is, ( 2 m + _ _ n ) ( m + _ _ n ) . List the possibilities for the last terms of each binomial factor whose product should be − 2 as shown below in Table 1. Factors of − 2 1 , − 2 − 1 , 2 Table 1 Factorize 2 m 2 − 3 m n − 2 n 2 using the binomial factor ( 2 m + _ _ n ) ( m + _ _ n ) and integer pairs 1 , − 2 and 1 , − 2

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ISBN: 9780321880116

Author: Michael Sullivan III, Katherine R. Struve, Janet Mazzarella

Publisher: PEARSON

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Chapter 6.3, Problem 65E

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The factor of the trinomial 2m2−3mn−2n2 by using trial and error.

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Chapter 6.3, Problem 64E

Chapter 6.3, Problem 66E

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Elementary & Intermediate Algebra

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The factor of the trinomial 2 m 2 − 3 m n − 2 n 2 by using trial and error.

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