
Concept explainers
(a)
To Find:The equation relating the cost c to the number of yards n for each material.
(a)

Answer to Problem 37PPS
Explanation of Solution
Given:The below table show price of difference materials.
For material Ribbon $2.67 for 3 yards.
Rate of Ribbon per yards
Therefore, the function is
For material Fleece $9.50 for 2 yards.
Rate of Fleece per yards
Therefore, the function is
For material Quilting Fabric $11.96 for 4 yards.
Rate of Quilting Fabric per yards
Therefore, the function is
For material Satin Fabric $10.35 for 3 yards.
Rate of Satin Fabric per yards
Therefore, the function is
(b)
To describe: The golden ratio of each objects.
(b)

Answer to Problem 37PPS
The material cost least per yard is ribbon.
The material cost most per yard is Fleece.
Explanation of Solution
Given:The table shown rate of each material.
Using table to graph each material on same coordinate plane.
The material cost least per yard is ribbon.
The material cost most per yard is Fleece.
The rate is maximum shown most cost per yard.
(c)
To find: The cost to buy 18 inches of ribbon and 10 meters of fleece.
(c)

Answer to Problem 37PPS
Ribbon cost = $0.45
Fleece cost = $51.97
Explanation of Solution
Given:The table shown rate of each material.
The cost function of ribbon is
Where, n represents in yards. So, first change 18 inches to yard.
Therefore,
Cost of 18 inches ribbon
Hence, cost of 18 inches ribbon is $0.45
The cost function of fleece is
Where, n represents in yards. So, first change 10 meters to yard.
Therefore,
Cost of 10 metersfleece
Hence, cost of 10 metersfleece is $51.97
Chapter 6 Solutions
Pre-Algebra, Student Edition
Additional Math Textbook Solutions
Thinking Mathematically (6th Edition)
University Calculus: Early Transcendentals (4th Edition)
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