Explanation The given equation is, x 2 + 3 b x − 4 b 2 x − b = x + 4 b A . Reduce the numerator of the fraction on the left hand side of the equation as follows. x 2 + 4 b x − b x − 4 b 2 x − b = x + 4 b A ( Factorize the numerator on the left ) x ( x + 4 b ) − b ( x + 4 b ) x − b = x + 4 b A ( Take x and − b as common ) ( x + 4 b ) ( x − b ) x − b = x + 4 b A ( Take x + 4 b as common ) Cancel the like terms in each numerator of the equation in order to find the value of A

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Author: Allyn Washington, Richard Evans

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Chapter 6.4, Problem 25E

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The value of A such that the fractions in x2+3bx−4b2x−b=x+4bA are equivalent.

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Chapter 6.4, Problem 24E

Chapter 6.4, Problem 26E

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Chapter 6 Solutions

Pearson eText for Basic Technical Mathematics with Calculus -- Instant Access (Pearson+)

Ch. 6.1 - Prob. 1PE Ch. 6.1 - Prob. 2PE Ch. 6.1 - Prob. 3PE Ch. 6.1 - Prob. 4PE Ch. 6.1 - Prob. 1E Ch. 6.1 - Prob. 2E Ch. 6.1 - Prob. 3E Ch. 6.1 - Prob. 4E Ch. 6.1 - Prob. 5E Ch. 6.1 - Prob. 6E

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The value of A such that the fractions in x 2 + 3 b x − 4 b 2 x − b = x + 4 b A are equivalent.

Solution Summary: The author explains that the value of A is equivalent to the tions in x2+3bx-4b2.

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The value of A such that the fractions in x2+3bx−4b2x−b=x+4bA are equivalent.

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Chapter 6 Solutions