Explanation Procedure used: Factoring general trinomials by grouping : In a trinomial of the form a x 2 + b x + c , a ≠ 1 , split up the x -term into two terms using the method described below. “Step 1: Find the product a c . Step 2: Find two numbers whose product is a c and whose sums is b . Step 3: Replace the middle term bx with two x -terms having these numbers as coefficients. That is, a x 2 + b x + c = a x 2 + m x + n x + c . Step 4: Complete the factorization by grouping”. Calculation: Factor the given expression w x 4 − 5 w L x 3 + 6 w L 2 x 2 as follows. Rewrite the expression as, w x 4 − 5 w L x 3 + 6 w L 2 x 2 = w x 2 ( x 2 − 5 L x + 6 L 2 ) (1) Consider the expression x 2 − 5 L x + 6 L 2 . It is observed that, the coefficients are a = 1 , b = − 5 L and c = 6 L 2 . Step 1: Find the value of a c . Obtain the value of a c as, a c = 1 ( 6 L 2 ) = 6 L 2 Thus, the value of a c is 6 L 2 . Step 2: Find the two number, e and f, whose product is a c = 6 L 2 and whose sum is b = − 5 L . Obtain the list of integer factors of 6 L 2 such that product is 6 L 2 and sum is − 5 L as shown below in Table 1. Integers whose product is 6 L 2 6 L , L − 6 L , − L 2 L , 3 L − 2 L , − 3 L Sum 7 L − 7 L 5 L − 5 L Table 1 From Table 1, it is observed that the numbers whose product is 6 L 2 and sum is − 5 L are − 2 L and − 5 L

Pearson eText for Basic Technical Mathematics with Calculus -- Instant Access (Pearson+)

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ISBN: 9780137554843

Author: Allyn Washington, Richard Evans

Publisher: PEARSON+

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Chapter 6.2, Problem 63E

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To factor: The expression wx4−5wLx3+6wL2x2 completely.

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Chapter 6.2, Problem 62E

Chapter 6.2, Problem 64E

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The following ordered data list shows the data speeds for cell phones used by a telephone company at an airport: A. Calculate the Measures of Central Tendency from the ungrouped data list. B. Group the data in an appropriate frequency table. C. Calculate the Measures of Central Tendency using the table in point B. 0.8 1.4 1.8 1.9 3.2 3.6 4.5 4.5 4.6 6.2 6.5 7.7 7.9 9.9 10.2 10.3 10.9 11.1 11.1 11.6 11.8 12.0 13.1 13.5 13.7 14.1 14.2 14.7 15.0 15.1 15.5 15.8 16.0 17.5 18.2 20.2 21.1 21.5 22.2 22.4 23.1 24.5 25.7 28.5 34.6 38.5 43.0 55.6 71.3 77.8

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Pearson eText for Basic Technical Mathematics with Calculus -- Instant Access (Pearson+)

Ch. 6.1 - Prob. 1PE Ch. 6.1 - Prob. 2PE Ch. 6.1 - Prob. 3PE Ch. 6.1 - Prob. 4PE Ch. 6.1 - Prob. 1E Ch. 6.1 - Prob. 2E Ch. 6.1 - Prob. 3E Ch. 6.1 - Prob. 4E Ch. 6.1 - Prob. 5E Ch. 6.1 - Prob. 6E

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To factor: The expression w x 4 − 5 w L x 3 + 6 w L 2 x 2 completely.

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To factor: The expression wx4−5wLx3+6wL2x2 completely.

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Chapter 6 Solutions