Stating the optimal solution:

The LINDO output is considered for the diet problem:

min z= 50BR+20IC+30CLA+80PC

Subject to constraint:

400BR+200IC+150CLA+500PC≥500

3BR+2IC≥6

2BR+2IC+4CLA+4PC≥10

2BR+4IC+CLA+5PC≥8

End

LP optimum is found at step 5

Objective function value: 90.000000

Variable Value Reduced cost
BR 0.000000 27.500000
IC 3.000000 0.000000
CLA 1.000000 0.000000
PC 0.000000 50.000000

Row Slack or Surplus Dual prices
2 250.000000 0.000000
3 0.000000 -2.500000
4 0.000000 -7.500000
5 5.000000 0.000000

Number of iterations= 5

The ranges in which the basis is unchanged:

Variable Current coefficient OBJ coefficient ranges allowable increase Allowable decrease
BR 50

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Chapter 6.3, Problem 9P

Chapter 6.4, Problem 2P

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OPERATIONS RESEARCH >INTERNATIONAL EDITI

Ch. 6.1 - Prob. 1P Ch. 6.1 - Prob. 2P Ch. 6.1 - Prob. 3P Ch. 6.1 - Prob. 4P Ch. 6.1 - Prob. 5P Ch. 6.2 - Prob. 1P Ch. 6.2 - Prob. 2P Ch. 6.3 - Prob. 1P Ch. 6.3 - Prob. 2P Ch. 6.3 - Prob. 3P

Ch. 6.3 - Prob. 4P Ch. 6.3 - Prob. 5P Ch. 6.3 - Prob. 6P Ch. 6.3 - Prob. 7P Ch. 6.3 - Prob. 8P Ch. 6.3 - Prob. 9P Ch. 6.4 - Prob. 1P Ch. 6.4 - Prob. 2P Ch. 6.4 - Prob. 3P Ch. 6.4 - Prob. 4P Ch. 6.4 - Prob. 5P Ch. 6.4 - Prob. 6P Ch. 6.4 - Prob. 7P Ch. 6.4 - Prob. 8P Ch. 6.4 - Prob. 9P Ch. 6.4 - Prob. 10P Ch. 6.4 - Prob. 11P Ch. 6.4 - Prob. 12P Ch. 6.4 - Prob. 13P Ch. 6.5 - Prob. 1P Ch. 6.5 - Find the duals of the following LPs: Ch. 6.5 - Prob. 3P Ch. 6.5 - Prob. 4P Ch. 6.5 - Prob. 5P Ch. 6.5 - Prob. 6P Ch. 6.6 - Prob. 1P Ch. 6.6 - Prob. 2P Ch. 6.7 - Prob. 1P Ch. 6.7 - Prob. 2P Ch. 6.7 - Prob. 3P Ch. 6.7 - Prob. 4P Ch. 6.7 - Prob. 5P Ch. 6.7 - Prob. 6P Ch. 6.7 - Prob. 7P Ch. 6.7 - Prob. 8P Ch. 6.7 - Prob. 9P Ch. 6.8 - Prob. 1P Ch. 6.8 - Prob. 2P Ch. 6.8 - Prob. 3P Ch. 6.8 - Prob. 4P Ch. 6.8 - Prob. 5P Ch. 6.8 - Prob. 6P Ch. 6.8 - Prob. 8P Ch. 6.8 - Prob. 9P Ch. 6.8 - Prob. 10P Ch. 6.8 - Prob. 11P Ch. 6.9 - Prob. 1P Ch. 6.9 - Prob. 2P Ch. 6.9 - Prob. 3P Ch. 6.10 - Prob. 1P Ch. 6.10 - Prob. 2P Ch. 6.10 - Prob. 3P Ch. 6.11 - Prob. 1P Ch. 6.11 - Prob. 3P Ch. 6.11 - Prob. 4P Ch. 6.12 - Prob. 5P Ch. 6.12 - Prob. 6P Ch. 6.12 - Prob. 7P Ch. 6 - Prob. 1RP Ch. 6 - Prob. 2RP Ch. 6 - Prob. 3RP Ch. 6 - Prob. 4RP Ch. 6 - Prob. 5RP Ch. 6 - Prob. 6RP Ch. 6 - Prob. 7RP Ch. 6 - Prob. 8RP Ch. 6 - Prob. 9RP Ch. 6 - Prob. 10RP Ch. 6 - Prob. 11RP Ch. 6 - Prob. 13RP Ch. 6 - Prob. 14RP Ch. 6 - Prob. 15RP Ch. 6 - Prob. 17RP Ch. 6 - Prob. 18RP Ch. 6 - Prob. 19RP Ch. 6 - Prob. 20RP Ch. 6 - Prob. 21RP Ch. 6 - Prob. 22RP Ch. 6 - Prob. 25RP Ch. 6 - Prob. 29RP Ch. 6 - Prob. 33RP Ch. 6 - Prob. 34RP Ch. 6 - Prob. 35RP Ch. 6 - Prob. 36RP Ch. 6 - Prob. 37RP

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Variable	Current coefficient	OBJ coefficient ranges allowable increase	Allowable decrease
BR	50

Variable	Value	Reduced cost
BR	0.000000	27.500000
IC	3.000000	0.000000
CLA	1.000000	0.000000
PC	0.000000	50.000000

Row	Slack or Surplus	Dual prices
2	250.000000	0.000000
3	0.000000	-2.500000
4	0.000000	-7.500000
5	5.000000	0.000000

Solution Summary: The author states that the LINDO output is considered for the diet problem: min z = 50BR+20IC+30CLA+80PC

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