Chapter 6.4, Problem 17E

To determine

To state: the amplitude of the function and then graph that function.

Answer to Problem 17E

2

Explanation of Solution

Given information:

  $y=2sin\theta$

Calculation:

The equation of sine function is as follows:

  $y=A\sin k\theta$..........(1)

Here $A$ is an amplitude which is an absolute value of the coefficient and $k=\frac{2\pi }{\text{Period}}$ .

Compare the given equation with equation (1) to get,

  $\begin{array}{c}\text{Amplitude}=\left|A\right|\\ =\left|2\right|\\ =2\end{array}$

Thus the amplitude of the function is 2.

Since $k=1$ , so the period will be evaluated as follows:

  $\begin{array}{c}\text{Period}=\frac{2\pi }{k}\\ =\frac{2\pi }{1}\left[\text{Put the value of }k\right]\\ =2\pi \end{array}$

Thus the period is $2\pi$ .

The graph of the function for the given amplitude and period is as follows: