Explanation Given: The solutions of polynomial 2 x 4 − 17 x 3 + 51 x 2 − 63 x + 27 = 0 are 3 and 1. Procedure used: Synthetic division method: “To divide a polynomial by ( x − a ) : 1. Arrange the coefficients in descending powers of x , with a 0 for any missing power. Place a from ( x − a ) to the left of the coefficients. 2. Bring down the first coefficient to the third line. Multiply the last number in the third line by a and write the product in the second line under the next term. 3. Add the last number in the second line to the number above it in the first line. Continue this process until all numbers in the first line are used. 4. The third line represents the coefficients of the quotient, with the last number the remainder. The quotient is a polynomial of degree one less than the dividend. If the remainder is 0, x − a is a factor of the polynomial, and the polynomial can be written as the product of the divisor x − a and the quotient.” Calculation: Consider the polynomial p ( x ) = 2 x 4 − 17 x 3 + 51 x 2 − 63 x + 27 . If the solution of the polynomial are 3 and 1 , then ( x − 1 ) and ( x − 3 ) are the factor of the polynomial. Obtain the factor of polynomial other than ( x − 1 ) and ( x − 3 ) . Divide the polynomial p ( x ) = 2 x 4 − 17 x 3 + 51 x 2 − 63 x + 27 by x − 1 . Use step 1 and set the coefficients in descending powers of x , 2 − 17 51 − 63 27 Set 1 for x − 1 to the left of the coefficients. 1 2 − 17 51 − 63 27 Use step 2 and 3 mentioned in Synthetic division method and bring 2 to the last entry (that is, last from the right end) of third line and multiply 2 by a , which is 1 and write the product 2 in second line under next term and add the number 2 in the second line and the number above it, that is, − 17 in first line. Continue this process and obtain the result as follows, 1 2 − 17 51 − 63 27 2 − 15 36 − 27 2 − 15 3 6 − 27 0 ¯ The third line represents the coefficient of quotient and last number is a remainder. The quotient is the polynomial of degree one less than the dividend polynomial. That is, the quotient is 2 x 3 − 15 x 2 + 36 x − 27 with remainder 0. Since x − 1 is a factor of the polynomial, the polynomial can be written as a product of quotient and the factor x − 1 . 2 x 4 − 17 x 3 + 51 x 2 − 63 x + 27 = ( x − 1 ) ( 2 x 3 − 15 x 2 + 36 x − 27 ) Need to find the factor of polynomial 2 x 3 − 15 x 2 + 36 x − 27

College Algebra in Context with Integrated Review and Worksheets Plus MyLab Math with Pearson eText-- Access Card Package

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ISBN: 9780134380155

Author: Ronald J. Harshbarger, Lisa S. Yocco

Publisher: PEARSON

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Chapter 6.4, Problem 12E

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To find: The remaining solutions to the polynomial equation 2x4−17x3+51x2−63x+27=0 by using the synthetic division.

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Chapter 6.4, Problem 11E

Chapter 6.4, Problem 13E

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College Algebra in Context with Integrated Review and Worksheets Plus MyLab Math with Pearson eText-- Access Card Package

Ch. 6.1 - Graph the function h(x) = 3x3 + 5x2 x 10 on the...Ch. 6.1 - Graph the function f(x) = 2x3 3x2 6x on the...Ch. 6.1 - Prob. 3E Ch. 6.1 - Prob. 4E Ch. 6.1 - Prob. 5E Ch. 6.1 - Prob. 6E Ch. 6.1 - Prob. 7E Ch. 6.1 - Prob. 8E Ch. 6.1 - Prob. 9E Ch. 6.1 - Prob. 10E

Ch. 6.1 - Prob. 11E Ch. 6.1 - Prob. 12E Ch. 6.1 - Prob. 13E Ch. 6.1 - Prob. 14E Ch. 6.1 - Prob. 15E Ch. 6.1 - For Exercises 1116, match the polynomial function...Ch. 6.1 - For Exercises 1720, use the equation of the...Ch. 6.1 - Prob. 18E Ch. 6.1 - Prob. 19E Ch. 6.1 - Prob. 20E Ch. 6.1 - Prob. 21E Ch. 6.1 - Prob. 22E Ch. 6.1 - Prob. 23E Ch. 6.1 - Prob. 24E Ch. 6.1 - Prob. 25E Ch. 6.1 - Prob. 26E Ch. 6.1 - Prob. 27E Ch. 6.1 - Prob. 28E Ch. 6.1 - Prob. 29E Ch. 6.1 - Prob. 30E Ch. 6.1 - Prob. 31E Ch. 6.1 - Sketch a graph of any cubic polynomial function...Ch. 6.1 - Prob. 33E Ch. 6.1 - Prob. 34E Ch. 6.1 - Prob. 35E Ch. 6.1 - Prob. 36E Ch. 6.1 - Prob. 37E Ch. 6.1 - Prob. 38E Ch. 6.1 - Daily Revenue The daily revenue in dollars from...Ch. 6.1 - Prob. 40E Ch. 6.1 - Prob. 41E Ch. 6.1 - Prob. 42E Ch. 6.1 - Starbucks Using data from 2005 and projected to...Ch. 6.1 - Prob. 44E Ch. 6.1 - Prob. 45E Ch. 6.1 - Prob. 46E Ch. 6.1 - Prob. 47E Ch. 6.1 - Salaries The median salary for male workers, in...Ch. 6.1 - Prob. 49E Ch. 6.1 - Prob. 50E Ch. 6.2 - Find the cubic function that models the data in...Ch. 6.2 - Find the cubic function that is the best fit for...Ch. 6.2 - Prob. 3E Ch. 6.2 - Find the quartic function that is the best fit for...Ch. 6.2 - Prob. 5E Ch. 6.2 - a. Make a scatter plot of the data in the table...Ch. 6.2 - Prob. 7E Ch. 6.2 - a. Find a cubic function that models the data in...Ch. 6.2 - Prob. 9E Ch. 6.2 - a. Graph each of the functions found in Exercise 9...Ch. 6.2 - Prob. 11E Ch. 6.2 - Prob. 12E Ch. 6.2 - Prob. 13E Ch. 6.2 - Prob. 14E Ch. 6.2 - Prob. 15E Ch. 6.2 - Find the cubic function that is the best fit for...Ch. 6.2 - Use unrounded models for graphing and calculations...Ch. 6.2 - Use unrounded models for graphing and calculations...Ch. 6.2 - Prob. 19E Ch. 6.2 - Prob. 20E Ch. 6.2 - Median Age at First Marriage (Source: U.S. Census...Ch. 6.2 - Prob. 22E Ch. 6.2 - Prob. 23E Ch. 6.2 - Inflation Rate The annual changes in the consumer...Ch. 6.2 - Elderly Men in the Workforce The table below gives...Ch. 6.2 - Prob. 26E Ch. 6.2 - Prob. 27E Ch. 6.2 - Consumer Prices The data in the table give the...Ch. 6.2 - Federal Tax Per Capita The table gives the amount...Ch. 6.2 - Japanese Economy The economy of Japan is the third...Ch. 6.2 - Women in the Workforce The following table gives...Ch. 6.2 - Homicide Rates The table gives the U.S. homicide...Ch. 6.2 - Prob. 33E Ch. 6.2 - Prob. 34E Ch. 6.2 - 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Prob. 18E Ch. 6.6 - Prob. 19E Ch. 6.6 - Prob. 20E Ch. 6.6 - Prob. 21E Ch. 6.6 - Prob. 22E Ch. 6.6 - Prob. 23E Ch. 6.6 - Prob. 24E Ch. 6.6 - Prob. 25E Ch. 6.6 - Combine factoring with graphical and/or numerical...Ch. 6.6 - Prob. 27E Ch. 6.6 - 28. Average Cost The average cost per set for the...Ch. 6.6 - Prob. 29E Ch. 6.6 - Prob. 30E Ch. 6.6 - Prob. 31E Ch. 6.6 - Prob. 32E Ch. 6.6 - Prob. 33E Ch. 6.6 - Prob. 34E Ch. 6.6 - Population Suppose the number of employees of a...Ch. 6 - For Exercises 14, (a) give the degree of the...Ch. 6 - For Exercises 14, (a) give the degree of the...Ch. 6 - Prob. 3TE Ch. 6 - Prob. 4TE Ch. 6 - Prob. 5TE Ch. 6 - Prob. 6TE Ch. 6 - Prob. 7TE Ch. 6 - Prob. 8TE Ch. 6 - Prob. 9TE Ch. 6 - Prob. 10TE Ch. 6 - Prob. 11TE Ch. 6 - Prob. 12TE Ch. 6 - Prob. 13TE Ch. 6 - Prob. 14TE Ch. 6 - In Exercises 1116, simplify each rational...Ch. 6 - Prob. 16TE Ch. 6 - Prob. 17TE Ch. 6 - Prob. 18TE Ch. 6 - Prob. 19TE Ch. 6 - Prob. 20TE Ch. 6 - Prob. 21TE Ch. 6 - Prob. 22TE Ch. 6 - Prob. 23TE Ch. 6 - Prob. 24TE Ch. 6 - Prob. 25TE Ch. 6 - Prob. 26TE Ch. 6 - Prob. 27TE Ch. 6 - Prob. 28TE Ch. 6 - Prob. 29TE Ch. 6 - Prob. 30TE Ch. 6 - Prob. 31TE Ch. 6 - Prob. 32TE Ch. 6 - Prob. 33TE Ch. 6 - Prob. 34TE Ch. 6 - Prob. 35TE Ch. 6 - Prob. 36TE Ch. 6 - Prob. 37TE Ch. 6 - Prob. 38TE Ch. 6 - Prob. 39TE Ch. 6 - Prob. 40TE Ch. 6 - In Exercises 3841, perform the long division. 41....Ch. 6 - Prob. 1RE Ch. 6 - Prob. 2RE Ch. 6 - Prob. 3RE Ch. 6 - Prob. 4RE Ch. 6 - Prob. 5RE Ch. 6 - Prob. 6RE Ch. 6 - Prob. 7RE Ch. 6 - Prob. 8RE Ch. 6 - Solve x4 x3 20x2 = 0.Ch. 6 - Prob. 10RE Ch. 6 - Prob. 11RE Ch. 6 - Prob. 12RE Ch. 6 - Prob. 13RE Ch. 6 - Prob. 14RE Ch. 6 - Prob. 15RE Ch. 6 - Prob. 16RE Ch. 6 - Prob. 17RE Ch. 6 - Prob. 18RE Ch. 6 - Find one solution of 3x3 x2 12x + 4 = 0...Ch. 6 - Find one solution of 2x3 + 5x2 4x 3 = 0...Ch. 6 - Prob. 21RE Ch. 6 - Prob. 22RE Ch. 6 - Prob. 23RE Ch. 6 - Prob. 24RE Ch. 6 - Prob. 25RE Ch. 6 - Prob. 26RE Ch. 6 - Prob. 27RE Ch. 6 - Prob. 28RE Ch. 6 - Prob. 29RE Ch. 6 - Prob. 30RE Ch. 6 - Prob. 31RE Ch. 6 - Prob. 32RE Ch. 6 - Prob. 33RE Ch. 6 - Revenue The monthly revenue for a product is given...Ch. 6 - Prob. 35RE Ch. 6 - Prob. 36RE Ch. 6 - Prob. 37RE Ch. 6 - Prob. 38RE Ch. 6 - Foreign Born Population The table on the following...Ch. 6 - Prob. 40RE Ch. 6 - Prob. 41RE Ch. 6 - Break-Even The daily profit in dollars for a...Ch. 6 - Starbucks The table gives the total number of...Ch. 6 - Drugs in the Bloodstream The concentration of a...Ch. 6 - Prob. 45RE Ch. 6 - Prob. 46RE Ch. 6 - Prob. 47RE Ch. 6 - Prob. 48RE Ch. 6 - Prob. 49RE Ch. 6 - Prob. 50RE Ch. 6 - Prob. 51RE Ch. 6 - Prob. 52RE Ch. 6 - Prob. 53RE Ch. 6 - Cost-Benefit The percent p of particulate...

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The remaining solutions to the polynomial equation 2 x 4 − 17 x 3 + 51 x 2 − 63 x + 27 = 0 by using the synthetic division.

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To find: The remaining solutions to the polynomial equation 2x4−17x3+51x2−63x+27=0 by using the synthetic division.

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Chapter 6 Solutions