How is the multiplication or division property of equality used in the elimination method? Are the properties always needed? Explain.
![Check Mark](/static/check-mark.png)
To define:The multiplication or division property of equality used in the elimination method.
Answer to Problem 31P
Multiplication or division property of equality are used in the elimination method and
these properties are not always needed if the coefficient of the variables is same.
Explanation of Solution
If we multiply or divide both sides of the equation by the same numbers, the side will always be equal.
When solving a mathematical system using elimination, we need some variables to have different coefficients that will cancel. Usually we need to multiply one or both numbers by a number to make this happen.
Here,
None of these have opposite coefficients. So, we can multiply the bottom equation by -3 to get the x to cancel out or -4 to get the y to cancel out. Thus, we take -3.
Now,
Therefore, multiplication or division property of equality is used in the elimination method.
These properties are not always needed if the coefficient is same.
Chapter 6 Solutions
ALGEBRA 1:COMMON CORE
Additional Math Textbook Solutions
Introductory Statistics
Elementary Statistics: Picturing the World (7th Edition)
Pre-Algebra Student Edition
A First Course in Probability (10th Edition)
Elementary Statistics
University Calculus: Early Transcendentals (4th Edition)
- The only problems I need help with ae the last 8 ones, Thanksarrow_forwardGraph without using the calculator y-1 = | x+4 |arrow_forward9:43 AS く Akbar © Printed in the United States 15) Scale: 1 cmal unit on both axes .ill 64% The graph above shows a straight line QT intersecting the y-axis at T. i State the co-ordinates of T. ii Calculate the gradient of QT 16) iii Determine the equation of QT. A (-1, 9) ||| i L Г (5 marks)arrow_forward
- Pls help.arrow_forwardSolve the system of equation for y using Cramer's rule. Hint: The determinant of the coefficient matrix is -23. - 5x + y − z = −7 2x-y-2z = 6 3x+2z-7arrow_forwarderic pez Xte in z= Therefore, we have (x, y, z)=(3.0000, 83.6.1 Exercise Gauss-Seidel iteration with Start with (x, y, z) = (0, 0, 0). Use the convergent Jacobi i Tol=10 to solve the following systems: 1. 5x-y+z = 10 2x-8y-z=11 -x+y+4z=3 iteration (x Assi 2 Assi 3. 4. x-5y-z=-8 4x-y- z=13 2x - y-6z=-2 4x y + z = 7 4x-8y + z = -21 -2x+ y +5z = 15 4x + y - z=13 2x - y-6z=-2 x-5y- z=-8 realme Shot on realme C30 2025.01.31 22:35 farrow_forward
- Algebra and Trigonometry (6th Edition)AlgebraISBN:9780134463216Author:Robert F. BlitzerPublisher:PEARSONContemporary Abstract AlgebraAlgebraISBN:9781305657960Author:Joseph GallianPublisher:Cengage LearningLinear Algebra: A Modern IntroductionAlgebraISBN:9781285463247Author:David PoolePublisher:Cengage Learning
- Algebra And Trigonometry (11th Edition)AlgebraISBN:9780135163078Author:Michael SullivanPublisher:PEARSONIntroduction to Linear Algebra, Fifth EditionAlgebraISBN:9780980232776Author:Gilbert StrangPublisher:Wellesley-Cambridge PressCollege Algebra (Collegiate Math)AlgebraISBN:9780077836344Author:Julie Miller, Donna GerkenPublisher:McGraw-Hill Education
![Text book image](https://www.bartleby.com/isbn_cover_images/9780134463216/9780134463216_smallCoverImage.gif)
![Text book image](https://www.bartleby.com/isbn_cover_images/9781305657960/9781305657960_smallCoverImage.gif)
![Text book image](https://www.bartleby.com/isbn_cover_images/9781285463247/9781285463247_smallCoverImage.gif)
![Text book image](https://www.bartleby.com/isbn_cover_images/9780135163078/9780135163078_smallCoverImage.gif)
![Text book image](https://www.bartleby.com/isbn_cover_images/9780980232776/9780980232776_smallCoverImage.gif)
![Text book image](https://www.bartleby.com/isbn_cover_images/9780077836344/9780077836344_smallCoverImage.gif)