Expand the triple product for a = ω × ( ω × r ) given in the discussion of Figure 3.8. If r is perpendicular to ω (Problem 16), show thata = − ω 2 r , and so find the elementary result that the acceleration is toward the center of the circle and of magnitude v 2 / r .
Expand the triple product for a = ω × ( ω × r ) given in the discussion of Figure 3.8. If r is perpendicular to ω (Problem 16), show thata = − ω 2 r , and so find the elementary result that the acceleration is toward the center of the circle and of magnitude v 2 / r .
Expand the triple product for
a
=
ω
×
(
ω
×
r
)
given in the discussion of Figure 3.8. If
r
is perpendicular to
ω
(Problem 16), show thata
=
−
ω
2
r
,
and so find the elementary result that the acceleration is toward the center of the circle and of magnitude
v
2
/
r
.
(2) Solve the following as systematically as possible. Show your complete solutions.
A hollow steel ball weighing 4 pounds is suspended from a spring. This stretches the spring feet. The ball is
started in motion from the equilibrium position with a downward velocity of 3 feet per second. The air resistance (in
pounds) of the moving ball numerically equals 4 times its velocity (in feet per second).
Suppose that after t seconds the ball is y feet below its rest position. Find y in terms of t. (Note that the positive direction
is down.)
Take as the gravitational acceleration 32 feet per second per second.
y =
Hint:
e^(-16t)(((1/(2sqrt(2))*e^(8sqrt(2)t)-(1/(2sqrt(2))*e^(-8sqrt(2)t))
Using and Understanding Mathematics: A Quantitative Reasoning Approach (6th Edition)
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