For the following exercises, use a graphing calculator to approximate the solutions of the equation. Round to the nearest thousandth.
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- For each of the following exercises, solve for y in terms of x, putting the equation in slope-intercept form. 4. 2x5y=7arrow_forwardFor each of the following exercises, solve for y in terms of x, putting the equation in slope-intercept form. 3. 5x=3y12arrow_forwardFor each of the following exercises, construct a table and graph the equation by plotting at least three points. 35.y=13x+2arrow_forward
- A rock was slung from a sling shot off the top of a building. The height of the rock, relative to the amount of time since leaving the sling shot, can be modeled by a function r (t) where r (t) represents the height of the rock in the feet above ground, and t is the number of seconds since the rock left the sling shot. The following equivalent equations represent r (t) in three different forms. r (t) =- 16(t 1.75) + 289 r(t) D-16 (t- 6) (t + 2.5) r (t) =-16t + 56t + 240 Check all of the statements that are true. O the rock hit the ground6 seconds after leaving the sling shot. O the rock hit the ground 2.5 seconds after leaving the sling shot. O The shape of the graph is concave up. O The rock's initial height was 289 feet. O The rock reached its highest point 1.75 seconds after leaving the sling.arrow_forwardThe position of a particle moving in a straight line is given by s() =- 8² + 28r, where s(t) represents the number of metres the particle is from a fixed point after t seconds a. What is the velocity of the particle at t= 1? b. What is the velocity of the particle at t = 9? C. At what time(s) is the particle not moving? %3Darrow_forwardA ball is launched straight up in the air from a height of 6 feet. Its velocity (feet/second) t seconds after launch is given by f(t) = - 34t + 288. Find its height 7 seconds after launch. The height of the ball 7 seconds after launch is feet. (Round answer to nearest tenth.) wse Enter your answer in the answer box.arrow_forward
- The temperature T(t), in degrees Fahrenheit, during the day can be modeled by the equation T(t) = −0.7t2 + 9.3t + 58.8, where t is the number of hours after 6 a.m. (a) How many hours after 6 a.m. is the temperature a maximum? Round to the nearest tenth of an hour.? hr (b)What is the maximum temperature (in degrees Fahrenheit)? Round to the nearest degree.°F Note: no handwrittenarrow_forwardThe height h(t) in feet of an object t seconds after it is propelled straight up from the ground with an initial velocity of 60 feet per second is modeled by the equation h(t) = - 16t +60t. At what times will the object be at a height of 56 ft? karrow_forwardSolve for x the equation : (1/2)x2 + mx - 2 = 0.arrow_forward
- c= 5(f-32)/9 to find the Celisius temperature reading if the Fahrenheit reading is 50 degreesarrow_forwardThe height h(t), in meters, above the ground of a certain soccer ball kick t seconds after the ball is kicked can be approximated by h(t) = −4.9t2 + 11.8t. Determine the time (in seconds) for which the ball is in the air. Round to the nearest tenth of a second.arrow_forward
- Glencoe Algebra 1, Student Edition, 9780079039897...AlgebraISBN:9780079039897Author:CarterPublisher:McGraw HillAlgebra & Trigonometry with Analytic GeometryAlgebraISBN:9781133382119Author:SwokowskiPublisher:Cengage