The cross product in ℝ n . Consider the vectors v → 2 , v → 3 , ... , v → n in ℝ n . The transformation T ( x → ) = det [ | | | | x → v → 2 v → 3 ⋯ v → n | | | | ] is linear. Therefore, there exists a unique vector u → in ℝ n such that T ( x → ) = x → ⋅ u → for all x → in ℝ n . Compare this with Exercise 2.1 .43c. This vector u → is called the cross product of v → 2 , v → 3 , ... , v → n , written as u → = v → 2 × v → 3 × ⋯ × v → n . In other words, the cross product is defined by the fact that x → ⋅ ( v → 2 × v → 3 × ⋯ × v → n ) = det [ | | | | x → v → 2 v → 3 ⋯ v → n | | | | ] , for all x → in ℝ n . Note that the cross product in ℝ n is defined for n − 1 vectors only. (For example, you can not form the cross product of just two vectors in ℝ 4 .) Since the ith component of a vector w → is e → ⋅ i w → . we can find the cross product by components as follows: ith component of v → 2 × v → 3 × ⋯ × v → n = e → i ⋅ ( v → 2 × ⋯ × v → n ) = det [ | | | | e → i v → 2 v → 3 ⋯ v → n | | | | ] a. When is v → 2 × v → 3 × ⋯ × v → n = 0 → ? Give your answer in terms of linear independence. b. Find e → 2 × e → 3 × ⋯ × e → n . c. Show that v → 2 × v → 3 × ⋯ × v → n is orthogonal to all the vectors v → i , for i = 2 , ... , n . d. What is the relationship between v → 2 × v → 3 × ⋯ × v → n and v → 3 × v → 2 × ⋯ × v → n ?(We swap the first two factors.) e. Express det [ v → 2 × v → 3 × ⋯ × v → n v → 2 × v → 3 × ⋯ × v → n ] in terms of ‖ v → 2 × v → 3 × ⋯ × v → n ‖ . f. How do we know that the cross product of two vectors in ℝ 3 , as defined here. is the same as the standard cross product in ℝ 3 ? See Definition A.9 of the Appendix.
The cross product in ℝ n . Consider the vectors v → 2 , v → 3 , ... , v → n in ℝ n . The transformation T ( x → ) = det [ | | | | x → v → 2 v → 3 ⋯ v → n | | | | ] is linear. Therefore, there exists a unique vector u → in ℝ n such that T ( x → ) = x → ⋅ u → for all x → in ℝ n . Compare this with Exercise 2.1 .43c. This vector u → is called the cross product of v → 2 , v → 3 , ... , v → n , written as u → = v → 2 × v → 3 × ⋯ × v → n . In other words, the cross product is defined by the fact that x → ⋅ ( v → 2 × v → 3 × ⋯ × v → n ) = det [ | | | | x → v → 2 v → 3 ⋯ v → n | | | | ] , for all x → in ℝ n . Note that the cross product in ℝ n is defined for n − 1 vectors only. (For example, you can not form the cross product of just two vectors in ℝ 4 .) Since the ith component of a vector w → is e → ⋅ i w → . we can find the cross product by components as follows: ith component of v → 2 × v → 3 × ⋯ × v → n = e → i ⋅ ( v → 2 × ⋯ × v → n ) = det [ | | | | e → i v → 2 v → 3 ⋯ v → n | | | | ] a. When is v → 2 × v → 3 × ⋯ × v → n = 0 → ? Give your answer in terms of linear independence. b. Find e → 2 × e → 3 × ⋯ × e → n . c. Show that v → 2 × v → 3 × ⋯ × v → n is orthogonal to all the vectors v → i , for i = 2 , ... , n . d. What is the relationship between v → 2 × v → 3 × ⋯ × v → n and v → 3 × v → 2 × ⋯ × v → n ?(We swap the first two factors.) e. Express det [ v → 2 × v → 3 × ⋯ × v → n v → 2 × v → 3 × ⋯ × v → n ] in terms of ‖ v → 2 × v → 3 × ⋯ × v → n ‖ . f. How do we know that the cross product of two vectors in ℝ 3 , as defined here. is the same as the standard cross product in ℝ 3 ? See Definition A.9 of the Appendix.
Solution Summary: The author illustrates how linearly independent vectors are based on the given determinant.
The cross product in
ℝ
n
. Consider the vectors
v
→
2
,
v
→
3
,
...
,
v
→
n
in
ℝ
n
. The transformation
T
(
x
→
)
=
det
[
|
|
|
|
x
→
v
→
2
v
→
3
⋯
v
→
n
|
|
|
|
]
is linear. Therefore, there exists a unique vector
u
→
in
ℝ
n
such that
T
(
x
→
)
=
x
→
⋅
u
→
for all
x
→
in
ℝ
n
. Compare this with Exercise 2.1 .43c. This vector
u
→
is called the cross product of
v
→
2
,
v
→
3
,
...
,
v
→
n
, written as
u
→
=
v
→
2
×
v
→
3
×
⋯
×
v
→
n
. In other words, the cross product is defined by the fact that
x
→
⋅
(
v
→
2
×
v
→
3
×
⋯
×
v
→
n
)
=
det
[
|
|
|
|
x
→
v
→
2
v
→
3
⋯
v
→
n
|
|
|
|
]
,
for all
x
→
in
ℝ
n
. Note that the cross product in
ℝ
n
is defined for
n
−
1
vectors only. (For example, you can not form the cross product of just two vectors in
ℝ
4
.) Since the ith component of a vector
w
→
is
e
→
⋅
i
w
→
. we can find the cross product by components as follows: ith component of
v
→
2
×
v
→
3
×
⋯
×
v
→
n
=
e
→
i
⋅
(
v
→
2
×
⋯
×
v
→
n
)
=
det
[
|
|
|
|
e
→
i
v
→
2
v
→
3
⋯
v
→
n
|
|
|
|
]
a. When is
v
→
2
×
v
→
3
×
⋯
×
v
→
n
=
0
→
? Give your answer in terms of linear independence. b. Find
e
→
2
×
e
→
3
×
⋯
×
e
→
n
. c. Show that
v
→
2
×
v
→
3
×
⋯
×
v
→
n
is orthogonal to all the vectors
v
→
i
, for
i
=
2
,
...
,
n
. d. What is the relationship between
v
→
2
×
v
→
3
×
⋯
×
v
→
n
and
v
→
3
×
v
→
2
×
⋯
×
v
→
n
?(We swap the first two factors.) e. Express
det
[
v
→
2
×
v
→
3
×
⋯
×
v
→
n
v
→
2
×
v
→
3
×
⋯
×
v
→
n
]
in terms of
‖
v
→
2
×
v
→
3
×
⋯
×
v
→
n
‖
. f. How do we know that the cross product of two vectors in
ℝ
3
, as defined here. is the same as the standard cross product in
ℝ
3
? See Definition A.9 of the Appendix.
Quantities that have magnitude and direction but not position. Some examples of vectors are velocity, displacement, acceleration, and force. They are sometimes called Euclidean or spatial vectors.
Can we have an exponential equation using logarithm however i want to show that one mistake is involved in solving it. Showing the mistake and how to be fixed. Thanks.
Is it possible to show me how to come up with an exponential equation by showing all the steps work and including at least one mistake that me as a person can make. Like a calculation mistake and high light what the mistake is. Thanks so much.
Consider the weighted voting system [16: 15, 8, 3, 1]Find the Banzhaf power distribution of this weighted voting system.List the power for each player as a fraction:
P1:
P2:
P3:
P4:
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Linear Equation | Solving Linear Equations | What is Linear Equation in one variable ?; Author: Najam Academy;https://www.youtube.com/watch?v=tHm3X_Ta_iE;License: Standard YouTube License, CC-BY