Explanation Given info: The bone density test score follows the standard normal distribution with mean 0 and standard deviation 1. Also, the bone density test scores are 1.23 and 2.37. Calculation: The probability of bone density scores between 1.23 and 2.37 represents the area to the right of 1.23 and area to the left of 2.37. Shade the region between z = 1.23 and z = 2.37 as shown below in Figure (1). Figure (1) The shaded region represents the probability of the bone density test score between 1.23 and 2.37. The probability of bone density scores between 1.23 and 2.37 is obtained by finding the difference between the areas to the left of 1.23 and the left of 2.37. Use Table A-2: Standard normal ( z ) distribution to find the area of shaded region. Procedure: For z at 1.23, Locate 1.2 in the left column of the table. Obtain the value in the corresponding row below 0.03. That is, P ( z < 1

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ISBN: 9780321837936

Author: Mario F. Triola

Publisher: PEARSON

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Features Features Normal distribution is characterized by two parameters, mean (µ) and standard deviation (σ). When graphed, the mean represents the center of the bell curve and the graph is perfectly symmetric about the center. The mean, median, and mode are all equal for a normal distribution. The standard deviation measures the data's spread from the center. The higher the standard deviation, the more the data is spread out and the flatter the bell curve looks. Variance is another commonly used measure of the spread of the distribution and is equal to the square of the standard deviation.

Chapter 6.2, Problem 26BSC

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To obtain: The probability of the bone density test score between 1.23 and 2.37.

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Chapter 6.2, Problem 25BSC

Chapter 6.2, Problem 27BSC

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To obtain: The probability of the bone density test score between 1.23 and 2.37.

Solution Summary: The author explains that the probability of the bone density test score between 1.23 and 2.37 is 0.1004.

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To obtain: The probability of the bone density test score between 1.23 and 2.37.

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