Chapter 6.11, Problem 6.18CP

Explanation of Solution

Output of the Program:

The given program has been added with comments and line number.

/* Include required variables */

#include <iostream> //Line 1

using namespace std; //Line 2

/* Function prototype */

void showVar(); //Line 3

/* Main function */

int main()//Line 4

{ //Line 5

/* Loop till "count" variable is less than "10" */

for (int count = 0; count < 10; count++) //Line 6

/*Call the function "showVar()"*/

showVar(); //Line 7

/*Return the value 0*/

return 0; //Line 8

}//Line 9

/*Function definition*/

void showVar() //Line 10

{//Line 11

/* Variable "var" is declared as static "int" and assign "10" to it */

static int var = 10; //Line 12

/*Print the value "var"*/

cout << var << endl; //Line 13

/*Increment the variable "var"*/

var++; //Line 14

} //Line 15

Explanation:

The above program explains the scope of the local variable when it is declared as “static”.

“main()” function:

• In line 6, it uses the “for” loop for iterating the “count” variable equals to less than 10.
  • When the value of “count” is “0”, the function “showVar()” has been called, which prints the value 10.
  • When the value of “count” is “1”, the function “showVar()” has been called, which prints the value 11.
  • When the value of “count” is “2”, the function “showVar()” has been called, which prints the value 12...