Explanation Determine the total rate of heat rejected by the refrigerator. Q ˙ L = Q ˙ outside + Q ˙ inside (I) Here, the rate of the heat gained through the wall is Q ˙ outside and the heat generation from people and lights and appliances is Q ˙ inside . Determine power input to the refrigerator. W ˙ net,in = Q ˙ L COP R,max (II) Here, the rate of heat absorb by the refrigerator is Q ˙ L . Conclusion: Substitute 20000 kJ / h for Q ˙ outside and 8000 kJ / h for Q ˙ inside in Equation (I)

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Chapter 6.11, Problem 127RP

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Chapter 6.11, Problem 126RP

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THERMODYNAMICS: ENG APPROACH LOOSELEAF

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The power input required for the air-conditioning system.

Solution Summary: The author explains the power input required for the air-conditioning system. Determine the rate of heat rejected by the refrigerator.

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