Chapter 6.1, Problem 36E

a.

To determine

To calculate: The ratio of the tadpole’s length and the adult frog’s length.

Answer to Problem 36E

The ratio of tadpole’s length and the adult frog’s length is $4:1$

Explanation of Solution

Given:

The tadpole is $24$ cm long and the frog is $6$ cm long.

Calculation:

To find the ratio of tadpole’s length and the adult frog’s length, the tadpole’s length is divided by the frog’s length and reduced to the simplest form.

  $\begin{array}{l}\frac{\text{tadpole's length}}{\text{frog's length}}\\ \Rightarrow \frac{24\text{ cm}}{6\text{ cm}} \left[\text{Divide out common factor and unit}\right]\\ \Rightarrow \frac{4}{1}\end{array}$

The ratio can be expressed in the form $a:b$ as- $4:1$ .

Therefore, the ratio of tadpole’s length and the adult frog’s length is $4:1$

b.

To determine

To describe: What is paradoxical about the frog.

Answer to Problem 36E

The frog is called paradoxical as it is larger as a tadpole than as an adult.

Explanation of Solution

Given:

Something is called paradoxical if it seems impossible.

A paradoxical frog is a species of frog which is also called a ‘shrinking frog’ as it shrinks during metamorphosis. As a tadpole, it is quite long and during metamorphosis it shrinks into an ordinary-sized frog. The ratio of the tadpole’s length to the frog’s length is obtained as $4:1$ . This means that the length of the tadpole is four times the length of the frog.