Chapter 6, Problem 8RE

Explanation of Solution

Enhanced “for” loops:

a. Print all elements of the array in a single line, separated by spaces:

Consider the below enhanced “for” loop to print all elements of the array in a single line, separated by spaces:

/* for loop to print all elements of the array */

for (int element : value...

Explanation of Solution

Enhanced “for” loops:

b. Computing the product of all elements in an array:

Consider the below enhanced “for” loop to compute the product of all elements in an array “values”:

/* declare a int type variable and initialize it with 1 */

  int product = 1;

/* for loop to multiply all elements in the values array   */      

          for (double element : values)

          {

  ...

Explanation of Solution

Enhanced “for” loops:

c. Counting how many elements in an array are negative:

Consider the below enhanced “for” loop to count how many elements in an array are negative:

/*Declare and initialize a variable to store the number of negative count */

int noofnegative = 0;

  //Loop to count the number of negative elements in an array

  for (int num: values)

  {

            //Check whether the element is negative or not      

         if (num < 0)

          {

              ;&#...