Calculate Δ H for the reaction N 2 H 4 ( l ) + O 2 ( g ) → N 2 ( g ) + 2H 2 O( l ) given the following data: 2 NH 3 ( g ) + 3 N 2 O ( g ) → 4 N 2 ( g ) + 3 H 2 O ( l ) Δ H = − 1010. kJ N 2 O ( g ) + 3 H 2 ( g ) → N 2 H 4 ( l ) + H 2 O ( l ) Δ H = − 317 kJ 2 NH 3 ( g ) + 1 2 O 2 ( g ) → N 2 H 4 ( l ) + H 2 O ( l ) Δ H = − 143 kJ H 2 ( g ) + 1 2 O 2 ( g ) → H 2 O ( l ) Δ H = − 286 kJ
Calculate Δ H for the reaction N 2 H 4 ( l ) + O 2 ( g ) → N 2 ( g ) + 2H 2 O( l ) given the following data: 2 NH 3 ( g ) + 3 N 2 O ( g ) → 4 N 2 ( g ) + 3 H 2 O ( l ) Δ H = − 1010. kJ N 2 O ( g ) + 3 H 2 ( g ) → N 2 H 4 ( l ) + H 2 O ( l ) Δ H = − 317 kJ 2 NH 3 ( g ) + 1 2 O 2 ( g ) → N 2 H 4 ( l ) + H 2 O ( l ) Δ H = − 143 kJ H 2 ( g ) + 1 2 O 2 ( g ) → H 2 O ( l ) Δ H = − 286 kJ
Solution Summary: The author explains that the enthalpy change of a reaction is self-determining of the route by which the chemical reaction take place.
2
NH
3
(
g
)
+
3
N
2
O
(
g
)
→
4
N
2
(
g
)
+
3
H
2
O
(
l
)
Δ
H
=
−
1010.
kJ
N
2
O
(
g
)
+
3
H
2
(
g
)
→
N
2
H
4
(
l
)
+
H
2
O
(
l
)
Δ
H
=
−
317
kJ
2
NH
3
(
g
)
+
1
2
O
2
(
g
)
→
N
2
H
4
(
l
)
+
H
2
O
(
l
)
Δ
H
=
−
143
kJ
H
2
(
g
)
+
1
2
O
2
(
g
)
→
H
2
O
(
l
)
Δ
H
=
−
286
kJ
need help please and thanks dont understand only need help with C-F
Learning Goal:
As discussed during the lecture, the enzyme HIV-1 reverse transcriptae (HIV-RT) plays a significant role for the HIV virus and is an important drug target. Assume a concentration [E] of 2.00 µM (i.e. 2.00 x 10-6 mol/l) for HIV-RT. Two potential drug molecules, D1 and D2, were identified, which form stable complexes with the HIV-RT.
The dissociation constant of the complex ED1 formed by HIV-RT and the drug D1 is 1.00 nM (i.e. 1.00 x 10-9). The dissociation constant of the complex ED2 formed by HIV-RT and the drug D2 is 100 nM (i.e. 1.00 x 10-7).
Part A - Difference in binding free eenergies
Compute the difference in binding free energy (at a physiological temperature T=310 K) for the complexes. Provide the difference as a positive numerical expression with three significant figures in kJ/mol.
The margin of error is 2%.
Part B - Compare difference in free energy to the thermal…
Please correct answer and don't used hand raiting
need help please and thanks dont understand a-b
Learning Goal:
As discussed during the lecture, the enzyme HIV-1 reverse transcriptae (HIV-RT) plays a significant role for the HIV virus and is an important drug target. Assume a concentration [E] of 2.00 µM (i.e. 2.00 x 10-6 mol/l) for HIV-RT. Two potential drug molecules, D1 and D2, were identified, which form stable complexes with the HIV-RT.
The dissociation constant of the complex ED1 formed by HIV-RT and the drug D1 is 1.00 nM (i.e. 1.00 x 10-9). The dissociation constant of the complex ED2 formed by HIV-RT and the drug D2 is 100 nM (i.e. 1.00 x 10-7).
Part A - Difference in binding free eenergies
Compute the difference in binding free energy (at a physiological temperature T=310 K) for the complexes. Provide the difference as a positive numerical expression with three significant figures in kJ/mol.
The margin of error is 2%.
Part B - Compare difference in free energy to the thermal energy
Divide the…
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