Chapter 6, Problem 73AP

Interpretation Introduction

(a)

Interpretation:

To balance the given chemical equation.

Concept Introduction:

Balancing a chemical equation is important to make the equation follow the conservation mass of law. The atoms in the chemical reaction from the reactant side is equal to the atoms in the product side.

Answer to Problem 73AP

${\text{Cl}}_2\text{+2KBr}\to \text{B}{\text{r}}_2+2\text{K}\text{C}\text{l}$ is the balanced equation.

Explanation of Solution

The given equation is,

${\text{Cl}}_2\text{+KBr}\to \text{B}{\text{r}}_2+\text{K}\text{C}\text{l}$

The equation is not balanced as there are two chlorine atoms in the reactant side and product has only one. The reactant side has one bromine and the product side has two bromine. This unbalanced equation is balanced by multiplying two to the potassium bromide on the reactant side and 2 on the product side of potassium chloride.

The balanced equation is given as,

${\text{Cl}}_2\text{+2KBr}\to \text{B}{\text{r}}_2+2\text{K}\text{C}\text{l}$.

Interpretation Introduction

(b)

Interpretation:

To balance the given chemical equation.

Concept Introduction:

Balancing a chemical equation is important to make the equation follow the conservation mass of law. The atoms in the chemical reaction from the reactant side is equal to the atoms in the product side.

Answer to Problem 73AP

The balanced equation is $4\text{C}\text{r}(s)+3{\text{O}}_2(g)\to 2\text{C}{\text{r}}_2{\text{O}}_3(s)$.

Explanation of Solution

The given equation is,

$\text{C}\text{r}(s)+{\text{O}}_2(g)\to \text{C}{\text{r}}_2{\text{O}}_3(s)$

The equation is unbalanced with 2 oxygen atoms on the reactant and three on the product. To balance 4 is multiplied to the chromium and three with oxygen on the reactant side. On the product side two is multiplied to chromium oxide.

The balanced equation is

$4\text{C}\text{r}(s)+3{\text{O}}_2(g)\to 2\text{C}{\text{r}}_2{\text{O}}_3(s)$.

Interpretation Introduction

(c)

Interpretation:

To balance the given chemical equation.

Concept Introduction:

Balancing a chemical equation is important to make the equation follow the conservation mass of law. The atoms in the chemical reaction from the reactant side is equal to the atoms in the product side.

Answer to Problem 73AP

${\text{P}}_4(s)+6{\text{H}}_2(g)\to 4\text{P}{\text{H}}_3(g)$.

Explanation of Solution

The given equation is,

${\text{P}}_4(s)+{\text{H}}_2(g)\to \text{P}{\text{H}}_3(g)$

The unbalanced side has two hydrogen and four phosphorous that is giving one molecule of phosphorous and three hydrogen. In order to balance the equation, 6 is multiplied by hydrogen on the reactant and four is multiplied on the product side.

The balanced equation is,

${\text{P}}_4(s)+6{\text{H}}_2(g)\to 4\text{P}{\text{H}}_3(g)$.

Interpretation Introduction

(d)

Interpretation:

To balance the given chemical equation.

Concept Introduction:

Balancing a chemical equation is important to make the equation follow the conservation mass of law. The atoms in the chemical reaction from the reactant side is equal to the atoms in the product side.

Answer to Problem 73AP

$2\text{A}\text{l}(s)+3{\text{H}}_2\text{S}{\text{O}}_4(aq)\to \text{A}{\text{l}}_2{(\text{S}{\text{O}}_4)}_3(aq)+3{\text{H}}_2(g)$.

Explanation of Solution

The given equation is,

$\text{A}\text{l}(s)+{\text{H}}_2\text{S}{\text{O}}_4(aq)\to \text{A}{\text{l}}_2{(\text{S}{\text{O}}_4)}_3(aq)+{\text{H}}_2(g)$

The unbalance equation has 1 aluminum and 4 molecules of oxygen on the reactant and has 12 molecules of oxygen on the product side. To balance 2 is multiplied to the aluminum and 3 is multiplied to the sulphuric acid on the reactant and 3 is multiplied to the hydrogen on the reactant side.

The balanced equation is,

$2\text{A}\text{l}(s)+3{\text{H}}_2\text{S}{\text{O}}_4(aq)\to \text{A}{\text{l}}_2{(\text{S}{\text{O}}_4)}_3(aq)+3{\text{H}}_2(g)$.

Interpretation Introduction

(e)

Interpretation:

To balance the given chemical equation.

Concept Introduction:

Balancing a chemical equation is important to make the equation follow the conservation mass of law. The atoms in the chemical reaction from the reactant side is equal to the atoms in the product side.

Answer to Problem 73AP

$\text{P}\text{C}{\text{l}}_3+3{\text{H}}_2\text{O}\to {\text{H}}_3\text{P}{\text{O}}_3+3\text{H}\text{C}\text{l}$.

Explanation of Solution

The given equation is,

$\text{P}\text{C}{\text{l}}_3+{\text{H}}_2\text{O}\to {\text{H}}_3\text{P}{\text{O}}_3+\text{H}\text{C}\text{l}$

The unbalance equation has 3 molecules of chlorine and two molecules of hydrogen on the reactant side and 4 molecules of hydrogen, three molecules of oxygen on the product side. To balance the equation 3 is multiplied to the water molecules on the reactant side and three is multiplied to the hydrogen chloride on the product side.

The balanced equation is,

$\text{P}\text{C}{\text{l}}_3+3{\text{H}}_2\text{O}\to {\text{H}}_3\text{P}{\text{O}}_3+3\text{H}\text{C}\text{l}$.

Interpretation Introduction

(f)

Interpretation:

To balance the given chemical equation.

Concept Introduction:

Balancing a chemical equation is important to make the equation follow the conservation mass of law. The atoms in the chemical reaction from the reactant side is equal to the atoms in the product side.

Answer to Problem 73AP

$2\text{S}{\text{O}}_2(g)+{\text{O}}_2(g)\to 2\text{S}{\text{O}}_3(g)$.

Explanation of Solution

The given equation is,

$\text{S}{\text{O}}_2(g)+{\text{O}}_2(g)\to \text{S}{\text{O}}_3(g)$

The unbalanced equation is balanced by multiplying two on both the product and the reactant side of sulphur dioxide and sulphur trioxide.

The balanced equation is,

$2\text{S}{\text{O}}_2(g)+{\text{O}}_2(g)\to 2\text{S}{\text{O}}_3(g)$.

Interpretation Introduction

(g)

Interpretation:

To balance the given chemical equation.

Concept Introduction:

Balancing a chemical equation is important to make the equation follow the conservation mass of law. The atoms in the chemical reaction from the reactant side is equal to the atoms in the product side.

Answer to Problem 73AP

${\text{C}}_7{\text{H}}_{16}+11{\text{O}}_2\to 7\text{C}{\text{O}}_2+8{\text{H}}_2\text{O}$.

Explanation of Solution

The given equation is,

${\text{C}}_7{\text{H}}_{16}+{\text{O}}_2\to \text{C}{\text{O}}_2+{\text{H}}_2\text{O}$

The equation is unbalanced with the 7 carbon molecules on the reactant and one carbon molecules on the product side. It is balanced by multiplying 11 to the oxygen on reactant side and multiplied 7 on the carbon di oxide and 8 to the water molecules on the product side.

The balanced equation is,

${\text{C}}_7{\text{H}}_{16}+11{\text{O}}_2\to 7\text{C}{\text{O}}_2+8{\text{H}}_2\text{O}$.

Interpretation Introduction

(h)

Interpretation:

To balance the given chemical equation.

Concept Introduction:

Balancing a chemical equation is important to make the equation follow the conservation mass of law. The atoms in the chemical reaction from the reactant side is equal to the atoms in the product side.

Answer to Problem 73AP

$2{\text{C}}_2{\text{H}}_6(g)+7{\text{O}}_2(g)\to 4\text{C}{\text{O}}_2(g)+6{\text{H}}_2\text{O}(g)$.

Explanation of Solution

The given equation is,

${\text{C}}_2{\text{H}}_6(g)+{\text{O}}_2(g)\to \text{C}{\text{O}}_2(g)+{\text{H}}_2\text{O}(g)$

The equation is unbalanced by having 6 molecules of hydrogen and 2 molecules of oxygen on the reactant side and three oxygen along with 2 molecules of hydrogen on the product side. The equation is balanced by multiplying two on the ethane and 7 on the oxygen in the reactant side. 4 is multiplied on the carbon dioxide and 6ismultiplied on the water molecules of the product side.

The balanced equation is,

$2{\text{C}}_2{\text{H}}_6(g)+7{\text{O}}_2(g)\to 4\text{C}{\text{O}}_2(g)+6{\text{H}}_2\text{O}(g)$.