EBK INTRODUCTORY CHEMISTRY
EBK INTRODUCTORY CHEMISTRY
8th Edition
ISBN: 9780100480483
Author: DECOSTE
Publisher: YUZU
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Chapter 6, Problem 41QAP

Balance each of the following chemical equations.

l type='a'>

  • msp;  Fe 3 O 4 ( s ) + H 2 ( g ) Fe ( l ) + H 2 O ( g )

    i>   K 2 SO 4 ( a q ) + BaCl 2 ( a q ) BaSO 4 ( s ) + KCl ( a q )

    i>   HCl ( a q ) + FeS ( s ) FeCl 2 ( a q ) + H 2 S ( g )

    i>   Br 2 ( g ) + H 2 O ( l ) + SO 2 ( g ) HBr ( a q ) + H 2 SO 4 ( a q )

    i>   CS 2 ( l ) + Cl 2 ( g ) CCl 4 ( l ) + S 2 Cl 2 ( g )

    i>   Cl 2 O 7 ( g ) + Ca ( OH ) 2 ( a q ) Ca ( ClO 4 ) 2 ( a q ) + H 2 O ( l )

    i>   PBr 3 ( l ) + H 2 O ( l ) H 3 PO 3 ( a q ) + HBr ( g )

    i>   Ba ( ClO 3 ) 2 ( s ) BaCl 2 ( s ) + O 2 ( s )

    mg src=Images/HTML_99425-6-41QAP_image001.jpg alt="" align="top"/>

    Expert Solution
    Check Mark
    Interpretation Introduction

    (a)

    Interpretation:

    The given chemical equation is to be balanced.

    Concept Introduction:

    In a balanced chemical reaction, the number of similar type of elements on both sides of the reaction is equal. To balance an unbalanced equation, the coefficients that are present before the compounds are changed but the subscripts in the formulas are not changed.

    Answer to Problem 41QAP

    Fe3O4(s)+4H2(g)3Fe(l)+4H2O(g).

    Explanation of Solution

    The provided reaction is:

    Fe3O4(s)+H2(g)Fe(l)+H2O(g)

    The most complicated molecule is not clear, so we start arbitrarily. If we place a coefficient of 3 before Fe and 4 before H2 and H2 O, we get a balanced equation.

    Fe3O4(s)+4H2(g)3Fe(l)+4H2O(g).

    Expert Solution
    Check Mark
    Interpretation Introduction

    (b)

    Interpretation:

    The given chemical equation is to be balanced.

    Concept Introduction:

    In a balanced chemical reaction, the number of similar type of elements on both sides of the reaction is equal. To balance an unbalanced equation, the coefficients that are present before the compounds are changed but the subscripts in the formulas are not changed.

    Answer to Problem 41QAP

    K2SO4(aq)+BaCl2(aq)BaSO4(s)+KCl(aq).

    Explanation of Solution

    The given unbalanced equation is:

    K2SO4(aq)+BaCl2(aq)BaSO4(s)+KCl(aq)

    We start with placing 2 before KCl and we get the balanced chemical reaction as follows:

    K2SO4(aq)+BaCl2(aq)BaSO4(s)+2KCl(aq).

    Expert Solution
    Check Mark
    Interpretation Introduction

    (c)

    Interpretation:

    The given chemical equation is to be balanced.

    Concept Introduction:

    In a balanced chemical reaction, the number of similar type of elements on both sides of the reaction is equal. To balance an unbalanced equation, the coefficients that are present before the compounds are changed but the subscripts in the formulas are not changed.

    Answer to Problem 41QAP

    2HCl(aq)+FeS(s)FeCl2(aq)+H2S(g).

    Explanation of Solution

    The given unbalanced equation is:

    HCl(aq)+FeS(s)FeCl2(aq)+H2S(g)

    We start by balancing HCl. If we place a coefficient 2 before HCl we get a balanced chemical reaction as follows:

    2HCl(aq)+FeS(s)FeCl2(aq)+H2S(g).

    Expert Solution
    Check Mark
    Interpretation Introduction

    (d)

    Interpretation:

    The given chemical equation is to be balanced.

    Concept Introduction:

    In a balanced chemical reaction, the number of similar type of elements on both sides of the reaction is equal. To balance an unbalanced equation, the coefficients that are present before the compounds are changed but the subscripts in the formulas are not changed.

    Answer to Problem 41QAP

    Br2(g)+2H2O(l)+SO2(g)2HBr(aq)+H2SO4(aq).

    Explanation of Solution

    The provided equation is:

    Br2(g)+H2O(l)+SO2(g)HBr(aq)+H2SO4(aq)

    If we place a coefficient of 2 H2 O and HBr, we get a balanced equation as follows:

    Br2(g)+2H2O(l)+SO2(g)2HBr(aq)+H2SO4(aq).

    Expert Solution
    Check Mark
    Interpretation Introduction

    (e)

    Interpretation:

    The given chemical equation is to be balanced.

    Concept Introduction:

    In a balanced chemical reaction, the number of similar type of elements on both sides of the reaction is equal. To balance an unbalanced equation, the coefficients that are present before the compounds are changed but the subscripts in the formulas are not changed.

    Answer to Problem 41QAP

    CS2(l)+3Cl2(g)CCl4(l)+S2Cl2(g).

    Explanation of Solution

    The provided equation is:

    CS2(l)+Cl2(g)CCl4(l)+S2Cl2(g)

    If we place a coefficient of 3 before Cl2, we get the balanced chemical reaction as follows:

    CS2(l)+3Cl2(g)CCl4(l)+S2Cl2(g).

    Expert Solution
    Check Mark
    Interpretation Introduction

    (f)

    Interpretation:

    The given chemical equation is to be balanced.

    Concept Introduction:

    In a balanced chemical reaction, the number of similar type of elements on both sides of the reaction is equal. To balance an unbalanced equation, the coefficients that are present before the compounds are changed but the subscripts in the formulas are not changed.

    Answer to Problem 41QAP

    Cl2O7(g)+Ca(OH)2(aq)Ca(ClO4)2(aq)+H2O(l).

    Explanation of Solution

    The provided reaction is:

    Cl2O7(g)+Ca(OH)2(aq)Ca(ClO4)2(aq)+H2O(l)

    We can see that all the atoms on both the sides are already balanced. Therefore, we already have a balanced equation.

    Li2O(s)+H2O(l)2LiOH(aq).

    Expert Solution
    Check Mark
    Interpretation Introduction

    (g)

    Interpretation:

    The given chemical equation is to be balanced.

    Concept Introduction:

    In a balanced chemical reaction, the number of similar type of elements on both sides of the reaction is equal. To balance an unbalanced equation, the coefficients that are present before the compounds are changed but the subscripts in the formulas are not changed.

    Answer to Problem 41QAP

    PBr3(l)+3H2O(l)H3PO4(aq)+3HBr(g).

    Explanation of Solution

    The provided reaction is:

    PBr3(l)+H2O(l)H3PO4(aq)+HBr(g)

    The most complicated molecule is H3PO4 because it contains the most number of elements (three). We start with the elements of H3PO4. We first start with oxygen. To balance oxygen, we place a coefficient 3 before H2 O

    PBr3(l)+3H2O(l)H3PO4(aq)+HBr(g)

    We can balance hydrogen by giving HBr a coefficient of 3. We now have a balanced equation

    PBr3(l)+3H2O(l)H3PO4(aq)+3HBr(g).

    Expert Solution
    Check Mark
    Interpretation Introduction

    (h)

    Interpretation:

    The given chemical equation is to be balanced.

    Concept Introduction:

    In a balanced chemical reaction, the number of similar type of elements on both sides of the reaction is equal. To balance an unbalanced equation, the coefficients that are present before the compounds are changed but the subscripts in the formulas are not changed.

    Answer to Problem 41QAP

    Ba(ClO3)2(s)BaCl2(s)+3O2(g).

    Explanation of Solution

    The provided reaction is:

    Ba(ClO3)2(s)BaCl2(s)+O2(g)

    Ba(ClO3)2 is the most complicated element. It contains the most number of elements (three). We arbitrarily start with oxygen. If we place a coefficient of 3 before O2, we have a balanced equation.

    Ba(ClO3)2(s)BaCl2(s)+3O2(g).

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    Chapter 6 Solutions

    EBK INTRODUCTORY CHEMISTRY

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