Look up the lattice energies in Table 6.3, and calculate the energy change in kilojoules per mole for the formation of the following substances from their elements. (a) LiF( s ) (The sublimation energy for Li( s ) is +159.4 kJ/mol, the E i for Li( g ) is 520 kJ/mol, the E ea for F( g ) is − 328 kJ/mol , and the bond dissociation energy of F 2 ( g ) is + 158 kJ/mol .] (b) CaF 2 ( s ) [The sublimation energy for Ca( s ) is + 178.2 kJ/mol, E i1 = + 589 . 8 kJ/mol , and E i2 = + 1145 kJ/mol .]
Look up the lattice energies in Table 6.3, and calculate the energy change in kilojoules per mole for the formation of the following substances from their elements. (a) LiF( s ) (The sublimation energy for Li( s ) is +159.4 kJ/mol, the E i for Li( g ) is 520 kJ/mol, the E ea for F( g ) is − 328 kJ/mol , and the bond dissociation energy of F 2 ( g ) is + 158 kJ/mol .] (b) CaF 2 ( s ) [The sublimation energy for Ca( s ) is + 178.2 kJ/mol, E i1 = + 589 . 8 kJ/mol , and E i2 = + 1145 kJ/mol .]
Solution Summary: The author explains the Born-Haber cycle of ionic solids from its constituent elements.
Look up the lattice energies in Table 6.3, and calculate the energy change in kilojoules per mole for the formation of the following substances from their elements. (a) LiF(s) (The sublimation energy for Li(s) is +159.4 kJ/mol, the
E
i
for Li(g) is 520 kJ/mol, the
E
ea
for F(g) is
−
328 kJ/mol
, and the bond dissociation energy of
F
2
(
g
)
is
+
158 kJ/mol
.] (b) CaF2(s) [The sublimation energy for Ca(s) is + 178.2 kJ/mol,
E
i1
=
+
589
.
8 kJ/mol
, and
E
i2
=
+
1145 kJ/mol
.]
Formula Formula Bond dissociation energy (BDE) is the energy required to break a bond, making it an endothermic process. BDE is calculated for a particular bond and therefore consists of fragments such as radicals since it undergoes homolytic bond cleavage. For the homolysis of a X-Y molecule, the energy of bond dissociation is calculated as the difference in the total enthalpy of formation for the reactants and products. X-Y → X + Y BDE = Δ H f X + Δ H f Y – Δ H f X-Y where, ΔHf is the heat of formation.
Predict the product formed when the compound shown below undergoes a reaction with MCPBA in CH2Cl2. MCPBA is meta-chloroperoxybenzoic acid.
k
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Dimensional Analysis - Aktiv Chemistry
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Question 19 of 22
Polyethylene terephthalate (PET) is used in plastic water bottles. A water bottle has a
mass of 14.0 grams. Given a density of 1.38 g/cm³, what is the volume of the
plastic used to make the water bottle in cm³ ?
ADD FACTOR
ANSWER
RESET
ว
100
14.0
0.01
10.1
1000
0.099
1.38
0.001
Q Search
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+ 11
A doctor gives a patient 10 Ci of beta radiation. How many betaparticles would the patient receive in 1 minute? (1 Ci = 3.7 x 1010d/s)
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