Find the lattice energy of LiBr( s ) in Table 6.3, and calculate the energy change in kilojoules for the formation of one mole of solid LiBr from the elements. [The sublimation energy forLi(s) is +159.4 kJ/mol, the bond dissodation energy of Br 2 ( g ) is + 224 kJ/mol , and the energy necessary to convert Br 2 ( l ) to Br 2 ( g ) is 30.9 kJ/mol.]
Find the lattice energy of LiBr( s ) in Table 6.3, and calculate the energy change in kilojoules for the formation of one mole of solid LiBr from the elements. [The sublimation energy forLi(s) is +159.4 kJ/mol, the bond dissodation energy of Br 2 ( g ) is + 224 kJ/mol , and the energy necessary to convert Br 2 ( l ) to Br 2 ( g ) is 30.9 kJ/mol.]
Solution Summary: The author describes the Born-Haber cycle of ionic solids from its constituent elements.
Find the lattice energy of LiBr(s) in Table 6.3, and calculate the energy change in kilojoules for the formation of one mole of solid LiBr from the elements. [The sublimation energy forLi(s) is +159.4 kJ/mol, the bond dissodation energy of
Br
2
(
g
)
is
+
224 kJ/mol
, and the energy necessary to convert
Br
2
(
l
)
to
Br
2
(
g
)
is 30.9 kJ/mol.]
There is an instrument in Johnson 334 that measures total-reflectance x-ray fluorescence (TXRF) to do elemental analysis (i.e., determine what elements are present in a sample). A researcher is preparing a to measure calcium content in a series of well water samples by TXRF with an internal standard of vanadium (atomic symbol: V). She has prepared a series of standard solutions to ensure a linear instrument response over the expected Ca concentration range of 40-80 ppm. The concentrations of Ca and V (ppm) and the instrument response (peak area, arbitrary units) are shown below. Also included is a sample spectrum. Equation 1 describes the response factor, K, relating the analyte signal (SA) and the standard signal (SIS) to their respective concentrations (CA and CIS).
Ca, ppm
V, ppm
SCa, arb. units
SV, arb. units
20.0
10.0
14375.11
14261.02
40.0
10.0
36182.15
17997.10
60.0
10.0
39275.74
12988.01
80.0
10.0
57530.75
14268.54
100.0…
A mixture of 0.568 M H₂O, 0.438 M Cl₂O, and 0.710 M HClO are enclosed in a vessel at 25 °C.
H₂O(g) + C₁₂O(g) = 2 HOCl(g)
K = 0.0900 at 25°C
с
Calculate the equilibrium concentrations of each gas at 25 °C.
[H₂O]=
[C₁₂O]=
[HOCI]=
M
Σ
M
What units (if any) does the response factor (K) have? Does the response factor (K) depend upon how the concentration is expressed (e.g. molarity, ppm, ppb, etc.)?
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Calorimetry Concept, Examples and Thermochemistry | How to Pass Chemistry; Author: Melissa Maribel;https://www.youtube.com/watch?v=nSh29lUGj00;License: Standard YouTube License, CC-BY