Foundation Design: Principles and Practices (3rd Edition)
3rd Edition
ISBN: 9780133411898
Author: Donald P. Coduto, William A. Kitch, Man-chu Ronald Yeung
Publisher: PEARSON
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Chapter 6, Problem 6.7QPP
A 5 ft square, 2 ft deep spread footing is subjected to a concentric vertical load of 60 k and an overtuming moment of 30 ft-k. The overturning moment acts parallel to one of the sides of the footing, and the top of the footing is flush with the ground surface and the groundwater table is at a depth of 20 ft below the ground surface. Determine whether the resultant force acts within the middle third of the footing, compute the minimum and maximum bearing pressures and show the distribution of bearing pressure in a sketch. Determine the size of the equivalent uniformly loaded footing and compute the equivalent bearing pressure.
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7. A continuous strip footing bears on sand with groundwater one-half the footing width below the
base of the footing. Which of the following changes will Increase the allowable bearing
pressure?
D
B/2
PFT
B
SAND
A) Embedment depth remains D, but the footing width is decreased.
B) Embedment depth remains D, but the groundwater is raised to B/4 below the base of the
footing.
C) Embedment depth and groundwater remain D and B/2, but the unit weight of the sand is
increased.
D) Groundwater remains at B/2 below the base of the footing, but the embedment depth is
decreased.
A 10 foot diameter circular footing is to be constructed and will have a net bearing pressure of 2,000 psf. Determine the increase in vertical stress at a depth of 20 feet below
the center of the footing
the edge of the footing
A 5.125-ft square, 2.0-ft deep spread footing is subjected to a concentric vertical load of 62.0k and an overturning moment of 30.0 ft-k. The overturning moment acts parallel to one of the
sides of the footing, and the top of the footing is flush with the ground surface and the groundwater table is at a depth of 0.5 ft below the ground surface.
Determine whether the resultant force acts within the middle third of the footing, compute the minimum and maximum bearing pressures and show the distribution of bearing pressure in a
sketch. Determine the size of the equivalent uniformly loaded footing and compute the equivalent bearing pressure.
Solution:
1. Preliminary calculation:
1). Area of the footing: A =
2). Self weight of the footing: Wf
=
2). Middle third of the footing: B/6 =
3). Pore water pressure at the bottom of the footing due to ground water: u =
2. Check eccentricity:
1). Eccentricity of bearing pressure distribution: e =
ft²;
kips/ft²;
=
3). Thus the bearing pressure…
Chapter 6 Solutions
Foundation Design: Principles and Practices (3rd Edition)
Ch. 6 - What is the difference between a square footing...Ch. 6 - Prob. 6.2QPPCh. 6 - Prob. 6.3QPPCh. 6 - A 400 kN vertical downward column load acts at the...Ch. 6 - A bearing wall carries a dead load of 5.0 k/ft and...Ch. 6 - Prob. 6.6QPPCh. 6 - A 5 ft square, 2 ft deep spread footing is...Ch. 6 - Consider the footing and loads in Problem 6.7,...Ch. 6 - The two columns in Figure 6.19 are to be supported...Ch. 6 - Prob. 6.10QPP
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Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, civil-engineering and related others by exploring similar questions and additional content below.Similar questions
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- Design round column footing for 18 in diameter that supports loads of PD = 240 k and PL = 140 k. The bottom of the footing is 6 foot below final grade, reinforced concrete weight is 150 lb/ft3 and the soil weighs 100 lb/ft3 the allowable soil pressure is 5 ksf. The concrete strength is 4,000 psi and the steel is Grade 60. 2arrow_forwardA bearing wall carries a dead load of 5.0 k/ft and a live load of 3.0 k/ft. It is supported on a3 ft wide, 2 ft deep continuous footing. The top of this footing is flush with the ground surfaceand the groundwater table is at a depth of 35 ft below the ground surface. Compute the bearingpressure for ultimate limit state design using the ASD method.arrow_forward3. Calculate the total load on a 4'x4'x1' spread footing that is buried 3' below, and a hot tub is located directly above the spread footing and the footing column is l'x1'. Assume the hot tub is full and no one is in the tub. Use some or all of the following data to calculate the total compressive load on the soil directly underneath the footing: a. DL - 12,000 lbs and b. LL-8,000 lbs c. 400 gallon hot tub (empty hot tub weighs 200 lbs) d. Soil weight 120 PCF e. Concrete weight 150 PCFarrow_forward
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