Chapter 6, Problem 6.72P

A pressure cooker 6 ltr

Calculate the workdone, heat transfer and change in entropy.  Do not need to solve.  I just need the  steps to solve it e.g equations etc.

Q2: One mole of air at P: and temperature Ti is compressed at constant volume till its pressure doubled. Then it is allowed to expand reversibly and isothermally to the original pressure and finally restored to the originol temperature by cooling at constant pressure. Sketch the processes on a P-V and calculate the net work done by the

120 kJ of heat is added to 2.27 kg of gas (R =319.2 J/kg K, k = 1.26) in a piston-cylinder at constant pressure when the initial temperature is 305.2 K. Find the work of nonflow in kJ and entropy change in kJ/K

saturated steam at 0.6 mpa is compressed in an irreversible adiabatic process with an effieciency of 80% for a final pressure of 0.46 mpa. find final and initial entropies

Show complete solution with t-s diagram.

ESL-2 150 grams of water at 20.0°C in a pan is places in an oven that is at a constant 100.0°C. a) Starting with AS-dQr/T, clearly explain all steps – evaluating the integral and finding the mumerical value - to find the total change in entropy for the original H20 to go from 20.0°C to become steam at 100.0°C. b) Starting with AS-dQr/T, clearly explain all steps- evaluating the integral and finding the numerid value to find the change in entropy for the oven interior for this entire process. c) Find the total change in entropy for the universe for this entire process. (Neglect the change due to the warming of the pan). Use this answer to explain whether this process is reversible or irreversible.

Q2/ Air is contained in an insulated, rigid volume at 20°C and 200 kPa. A paddle wheel, inserted in the volume, does 720 kJ of work on the air. If the volume is 2m3, calculate the entropy increase assuming constant specifi c heats.

A 2.5 kg copper block at 200 °C and 5 kg aluminum block at 20 °C come in thermal contact. Find the final temperature and the entropy generated. Consider both blocks together as your system and assume no heat loss to the surroundings.