Chapter 6, Problem 6.73P

Please show correct solution and clear explanation. Choose from the choices for the correct answer. Thank you.

0.2Kg of gas at 100⁰C is expanded isothermally and reversibly from 1MPa pressure to 100KPa. Take Cv=718J/Kg.K and R= 287J/Kg.K.Calculate: a. The work b) the change in internal energy c) the heat transfer

A rigid 11-L vessel initially contains a mixture of liquid, water and vapor at 105o C with 10.9 percent quality. The misture is then heated until its temperature is 170o C. Calculate the heat transfer required for this process.

Steam at 7 bar, dryness fraction 0.96, is throttled-down to 3.5 bar. Solve for the change of entropy per unit mass of steam and show the process on T-s diagram.

Calculate the workdone, heat transfer and change in entropy.  Do not need to solve.  I just need the  steps to solve it e.g equations etc.

Please don't provide handwritten solution ....

One way to determine the quality of saturated steam is to throttle the steam to a low enough pressure that it exists as a superheated vapor. Saturated steam at 500 kPa is throttled to 0.1 MPa, 100 oC. Determine the quality of the steam at 400 kPa side. (Starts the calculation from mass and energy conservation)

ii. Inside the cylinder-piston is water with at-200C. During isothermal process, 550 kJ of heat is transferred to the water. Due to this, some water evaporated. The change of entropy of water during this process.

2000 kg cast iron hoisin at 350 degree Celsius is quenched in 4000 kg of water at 15 degree Celsius. Find the amount of heat transferred to the water bath, entropy change for water and cast iron, use the entropy generation to prove that the entire system does not violate the second law of thermodynamics. Water specific heat of 4.18kj/kg.k, cast iron specific heat of 0.42kj/kg.k