Chapter 6, Problem 6.6P

Interpretation Introduction

Interpretation: The power input to the test pump for the given fluid in units of horse power is to be determined by using the energy balance equation.

Concept introduction: The Energy balance across the pipe is given by the Bernoulli’s equation in which the sum of Potential head, Kinetic head and Pressure head is constant. The Bernoulli equation across 2 points of any system is given by:-

  $\frac{{\text{P}}_{\text{1}}}{\text{ρg}}\text{+}\frac{{\text{v}}_{\text{1}}{}^{\text{2}}}{\text{2g}}{\text{+ Z}}_{\text{1}}\text{+}\text{H}\text{=}\frac{{\text{P}}_{\text{2}}}{\text{ρg}}\text{+}\frac{{\text{v}}_{\text{2}}{}^{\text{2}}}{\text{2g}}{\text{+ Z}}_{\text{2}}\text{+}{\text{h}}_{\text{f}}$   ...... (1)

The notations used in equation (1) are:-

P₁ and P₂ are pressure at inlet and outlet of the pipe

v₁ and v₂ are velocity at inlet and outlet of the pipe

Z₁ and Z₂ are the locations of the liquid.

  $\text{ρ}$ = Density of the water

H = Head developed by the pump

g = Acceleration due to gravity

h_f = Frictional losses

The power delivered by the pump is given as,

  $\text{<msup><mo>P</mo><mo>′</mo></msup>}\text{=}\text{ρgHQ}$   ...... (2)

Q = Flow rate of the water

  $\text{<msup><mo>P</mo><mo>′</mo></msup>}$ = Power of the pump

The flow rate is given as,

  $\text{Q}\text{=}\text{A×v}$   ...... (3)

A = Area of the pipe

v = Velocity of the water