Engineering Electromagnetics
Engineering Electromagnetics
9th Edition
ISBN: 9781260029963
Author: Hayt
Publisher: MCG
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Chapter 6, Problem 6.5P
To determine

The factor by which capacitance is increased.

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(6) A parallel-plates capacitor with plate area of 100 cm? has a separation of 3mm between the pates. The separation is divided into three slabs, where each slab has 1 mm distance. The first slab is filled by air and has a constant of 1. The second slab is filled by polystyrene and has a constant of 2.5, while the third slab is filled by silicon dioxide and has a constant of 4. Compute the capacitance of the system. Note: for parallel slabs; Conductor 1 E = T 1 Air E1 83 Material A Material 3 Conductor Ans. C = 54 pF
5. Cylindrical capacitors of length L is filled up with an inhomogeneous dielectric as shown in the figure. Find the capacitance of each capacitor. $! 8x2 (a) Erl (b) &
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Chapter 6 Solutions

Engineering Electromagnetics

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