Engineering Electromagnetics
Engineering Electromagnetics
9th Edition
ISBN: 9781260029963
Author: Hayt
Publisher: MCG
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Chapter 6, Problem 6.3P

Capacitors tend to be more expensive as their capacitance and maximum voltage V max increase. The voltage V max is limited by the field strength at which the dielectric breaks down, Ebd- Which of these dielectrics will give the largest CVmax product for equal plate areas? (a) Air: đ�œ–y = 1, Ebd = 3 MV/m. (b) Barium titanate: e? = 1200, EBD = 3 MV/m. (c) Silicon dioxide: đ�œ–r = 3.78, EBD = 16 MV/m. (d) Polyethylene: đ�œ–T = 2.26, EBD = 4.7 MV/m.

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We want to investigate how the field strength will be with air as dielectric and with steatite. A plate capacitor is placed in a 24 kV network between phase and ground. The relative permittivity of air is &=1 and for steatite &-6. The plate capacitor has area = 1m². The distance between the electrodes is 2 mm. Ep = 8.854-10-12 F/m A=1m² d=2mm a) Calculate the maximum field strength in the plate capacitor. (Answer: 9.8kV/mm) b) What is the capacitance of the capacitor if we use steatite? (Answer: C = 26.6nF)
write down the measure capacitance on your bench figure.1

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