Chapter 6, Problem 6.55CP

Interpretation Introduction

Interpretation:

The number of molecules present in $\text{0}\text{.5μg}$ should be determined.

Concept introduction:

Mole:

A mole is corresponds to the mass of a substance that contains $\text{6}{\text{.023×10}}^{\text{23}}$ particles of the substance.

The mole is the SI units for the amount of a substance and its symbol is mol.

1 mole of carbon -12 has a mass of 12 gram and it contains

$\text{6}{\text{.022140857 x 10}}^{\text{23}}\text{ of carbon atoms}$

So, $\text{1mole = 6}{\text{.023×10}}^{\text{23}}\text{molecules}$.

Formula:

Moles of Batrachotoxin (${\text{C}}_{\text{31}}{\text{H}}_{\text{42}}{\text{N}}_{\text{2}}{\text{O}}_{\text{6}}$) = $\frac{\text{Weight in gram }}{\text{molar mass}}$.