The energy of a sodium ion and a fluoride ion that are at their equilibrium ion-pair separation distance has to be calculated. Concept Introduction: Coulomb’s Law of attraction: Coulomb’s law states that the energy of interaction of two ions is directly proportional to the product their electric charges and is inversely proportional to the distance between them. The formula is, E Coulomb =k ⋅ Q 1 Q 2 d Q 1 ,Q 2 = Charges of the two ions d= Distance between the centers of the two ions k= Proportionality constant The value of proportionality constant depends on the units of charges and distance.

Question

Want to see the full answer?

Answer 1

Question

Chapter 6, Problem 6.50P

Interpretation Introduction

Interpretation:

The energy of a sodium ion and a fluoride ion that are at their equilibrium ion-pair separation distance has to be calculated.

Concept Introduction:

Coulomb’s Law of attraction:

Coulomb’s law states that the energy of interaction of two ions is directly proportional to the product their electric charges and is inversely proportional to the distance between them. The formula is,

ECoulomb=k⋅Q1Q2d

Q1,Q2= Charges of the two ions

d= Distance between the centers of the two ions

k= Proportionality constant

The value of proportionality constant depends on the units of charges and distance.

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Students have asked these similar questions

Please help with number 6 I got a negative number could that be right?

1,4-Dimethyl-1,3-cyclohexadiene can undergo 1,2- or 1,4-addition with hydrogen halides. (a) 1,2-Addition i. Draw the carbocation intermediate(s) formed during the 1,2-addition of hydrobromic acid to 1,4-dimethyl-1,3-cyclohexadiene. ii. What is the major 1,2-addition product formed during the reaction in (i)? (b) 1,4-Addition i. Draw the carbocation intermediate(s) formed during the 1,4-addition of hydrobromic acid to 1,4-dimethyl-1,3-cyclohexadiene. ii. What is the major 1,4-addition product formed from the reaction in (i)? (c) What is the kinetic product from the reaction of one mole of hydrobromic acid with 1,4-dimethyl-1,3-cyclohexadiene? Explain your reasoning. (d) What is the thermodynamic product from the reaction of one mole of hydrobro-mic acid with 1,4-dimethyl-1,3-cyclohexadiene? Explain your reasoning. (e) What major product will result when 1,4-dimethyl-1,3-cyclohexadiene is treated with one mole of hydrobromic acid at - 78 deg * C ? Explain your reasoning.

Give the product of the bimolecular elimination from each of the isomeric halogenated compounds. Reaction A Reaction B. КОВ CH₂ HotBu +B+ ко HOIBU +Br+ Templates More QQQ Select Cv Templates More Cras QQQ One of these compounds undergoes elimination 50x faster than the other. Which one and why? Reaction A because the conformation needed for elimination places the phenyl groups and to each other Reaction A because the conformation needed for elimination places the phenyl groups gauche to each other. ◇ Reaction B because the conformation needed for elimination places the phenyl groups gach to each other. Reaction B because the conformation needed for elimination places the phenyl groups anti to each other.