Chemistry: An Atoms-Focused Approach
14th Edition
ISBN: 9780393912340
Author: Thomas R. Gilbert, Rein V. Kirss, Natalie Foster
Publisher: W. W. Norton & Company
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Chapter 6, Problem 6.43QA
Interpretation Introduction
To explain:
What is meant by the term equilibrium line as it is used in Section 6.4?
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Students have asked these similar questions
For the decomposition reaction of N2O5(g): 2 N2O5(g) → 4 NO2(g) + O2(g), the following mechanism has been proposed:
N2O5 NO2 + NO3 (K1) | NO2 + NO3 → N2O5 (k-1) | NO2 + NO3 NO2 + O2 + NO (k2) | NO + N2O51 NO2 + NO2 + NO2 (K3)
→
Give the expression for the acceptable rate.
→
→
(A).
d[N205]
dt
==
2k,k₂[N₂O₂]
k₁+k₁₂
(B).
d[N2O5]
=-k₁[N₂O] + k₁[NO₂] [NO3] - k₂[NO₂]³
dt
(C).
d[N2O5]
=-k₁[N₂O] + k [NO] - k₂[NO] [NO]
d[N2O5]
(D).
=
dt
= -k₁[N2O5] - k¸[NO][N₂05]
dt
Do not apply the calculations, based on the approximation of the stationary state, to make them perform correctly. Basta discard
the 3 responses that you encounter that are obviously erroneous if you apply the formula to determine the speed of a reaction.
For the decomposition reaction of N2O5(g): 2 N2O5(g) → 4 NO2(g) + O2(g), the following mechanism has been proposed:
N2O5 NO2 + NO3 (K1) | NO2 + NO3 → N2O5 (k-1) | NO2 + NO3 NO2 + O2 + NO (k2) | NO + N2O51 NO2 + NO2 + NO2 (K3)
→
Give the expression for the acceptable rate.
→
→
(A).
d[N205]
dt
==
2k,k₂[N₂O₂]
k₁+k₁₂
(B).
d[N2O5]
=-k₁[N₂O] + k₁[NO₂] [NO3] - k₂[NO₂]³
dt
(C).
d[N2O5]
=-k₁[N₂O] + k [NO] - k₂[NO] [NO]
d[N2O5]
(D).
=
dt
= -k₁[N2O5] - k¸[NO][N₂05]
dt
Do not apply the calculations, based on the approximation of the stationary state, to make them perform correctly. Basta discard
the 3 responses that you encounter that are obviously erroneous if you apply the formula to determine the speed of a reaction.
R lactam or lactone considering as weak acid or weak base and why
Chapter 6 Solutions
Chemistry: An Atoms-Focused Approach
Ch. 6 - Prob. 6.1VPCh. 6 - Prob. 6.2VPCh. 6 - Prob. 6.3VPCh. 6 - Prob. 6.4VPCh. 6 - Prob. 6.5VPCh. 6 - Prob. 6.6VPCh. 6 - Prob. 6.7VPCh. 6 - Prob. 6.8VPCh. 6 - Prob. 6.9VPCh. 6 - Prob. 6.10VP
Ch. 6 - Prob. 6.11VPCh. 6 - Prob. 6.12VPCh. 6 - Prob. 6.13VPCh. 6 - Prob. 6.14VPCh. 6 - Prob. 6.15VPCh. 6 - Prob. 6.16VPCh. 6 - Prob. 6.17QACh. 6 - Prob. 6.18QACh. 6 - Prob. 6.19QACh. 6 - Prob. 6.20QACh. 6 - Prob. 6.21QACh. 6 - Prob. 6.22QACh. 6 - Prob. 6.23QACh. 6 - Prob. 6.24QACh. 6 - Prob. 6.25QACh. 6 - Prob. 6.26QACh. 6 - Prob. 6.27QACh. 6 - Prob. 6.28QACh. 6 - Prob. 6.29QACh. 6 - Prob. 6.30QACh. 6 - Prob. 6.31QACh. 6 - Prob. 6.32QACh. 6 - Prob. 6.33QACh. 6 - Prob. 6.34QACh. 6 - Prob. 6.35QACh. 6 - Prob. 6.36QACh. 6 - Prob. 6.37QACh. 6 - Prob. 6.38QACh. 6 - Prob. 6.39QACh. 6 - Prob. 6.40QACh. 6 - Prob. 6.41QACh. 6 - Prob. 6.42QACh. 6 - Prob. 6.43QACh. 6 - Prob. 6.44QACh. 6 - Prob. 6.45QACh. 6 - Prob. 6.46QACh. 6 - Prob. 6.47QACh. 6 - Prob. 6.48QACh. 6 - Prob. 6.49QACh. 6 - Prob. 6.50QACh. 6 - Prob. 6.51QACh. 6 - Prob. 6.52QACh. 6 - Prob. 6.53QACh. 6 - Prob. 6.54QACh. 6 - Prob. 6.55QACh. 6 - Prob. 6.56QACh. 6 - Prob. 6.57QACh. 6 - Prob. 6.58QACh. 6 - Prob. 6.59QACh. 6 - Prob. 6.60QACh. 6 - Prob. 6.61QACh. 6 - Prob. 6.62QACh. 6 - Prob. 6.63QACh. 6 - Prob. 6.64QACh. 6 - Prob. 6.65QACh. 6 - Prob. 6.66QACh. 6 - Prob. 6.67QACh. 6 - Prob. 6.68QACh. 6 - Prob. 6.69QACh. 6 - Prob. 6.70QACh. 6 - Prob. 6.71QACh. 6 - Prob. 6.72QACh. 6 - Prob. 6.73QACh. 6 - Prob. 6.74QA
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Similar questions
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