Chapter 6, Problem 6.39EP

(a)

Interpretation Introduction

Interpretation:

Among $1.00mole$ of $S$ and $1.00mole$ of $S_8$, the one that contains greater number of atoms has to be selected using periodic table and not by performing calculations.

(b)

Interpretation Introduction

Interpretation:

Among $28.00g$ of $Al$ and $1.00mole$ of $Al$, the one that contains greater number of atoms has to be selected using periodic table and not by performing calculations.

(c)

Interpretation Introduction

Interpretation:

Among $28.09g$ of $Si$ and $30.09g$ of $Mg$, the one that contains greater number of atoms has to be selected using periodic table and not by performing calculations.

(d)

Interpretation Introduction

Interpretation:

Among $2.00g$ of $Na$ and $6.02x{10}^{23}$ atoms of $He$, the one that contains greater number of atoms has to be selected using periodic table and not by performing calculations.