(a) Interpretation: Appropriate products are to be drawn for the given proton transfer reaction with curved arrow notation. Concept introduction: In a proton transfer reaction, a proton is transferred from a Bronsted-Lowry acid to a Bronsted-Lowry base in a single elementary step in which one bond is broken and another is formed simultaneously. The curved arrow notation shows the movement of valence electrons, not atoms. The movement of two valence electrons is shown by curved arrow. To represent bond breaking, the tail of the arrow originates from the center of a bond whereas to represent bond formation, the head of arrow points to an atom which forms the new bond, that is, bond or the region where the bond is formed if the new bond is a bond. The conjugate acid is the species that the base becomes after gaining a proton, and the conjugate base is the species that the acid becomes after losing a proton.

Question

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Answer 1

Question

Chapter 6, Problem 6.38P

Interpretation Introduction

(a)

Interpretation:

Appropriate products are to be drawn for the given proton transfer reaction with curved arrow notation.

Concept introduction:

In a proton transfer reaction, a proton is transferred from a Bronsted-Lowry acid to a Bronsted-Lowry base in a single elementary step in which one bond is broken and another is formed simultaneously. The curved arrow notation shows the movement of valence electrons, not atoms. The movement of two valence electrons is shown by curved arrow. To represent bond breaking, the tail of the arrow originates from the center of a bond whereas to represent bond formation, the head of arrow points to an atom which forms the new bond, that is, bond or the region where the bond is formed if the new bond is a bond. The conjugate acid is the species that the base becomes after gaining a proton, and the conjugate base is the species that the acid becomes after losing a proton.

Expert Solution

Answer to Problem 6.38P

For the given proton transfer reaction, the products are as shown below.

EBK GET READY FOR ORGANIC CHEMISTRY, Chapter 6, Problem 6.38P , additional homework tip 3

Explanation of Solution

The curved arrow notation for the given proton transfer reaction is shown below:

EBK GET READY FOR ORGANIC CHEMISTRY, Chapter 6, Problem 6.38P , additional homework tip 4

In a proton transfer reaction, a proton is transferred from the Bronsted-Lowry acid to the Bronsted-Lowry base. The movement of two valence electrons is shown by curved arrow. The head of the arrow pointing to the atom shows the transfer of valence electrons to form a new single bond. In the above reaction, one curved arrow is drawn from the lone pair on O to the H on the other reactant, so it illustrates the formation of a new O-H bond in the first reactant. The tail of the second arrow originates from the center of O-H bond, so it illustrate the breaking of that bond, and it points to the O atom, showing that those electrons end up as a lone pair on O of the second reactant. Therefore, for the given proton transfer reaction, the products are as drawn below:

EBK GET READY FOR ORGANIC CHEMISTRY, Chapter 6, Problem 6.38P , additional homework tip 5

Conclusion

The products of the given proton transfer reaction are drawn on the basis of the curved arrow notation that shows breaking and formation of bonds.

Interpretation Introduction

(b)

Interpretation:

Appropriate products are to be drawn for the given proton transfer reaction with curved arrow notation.

Concept introduction:

In a proton transfer reaction, a proton is transferred from a Bronsted-Lowry acid to a Bronsted-Lowry base in a single elementary step in which one bond is broken and another is formed simultaneously. The curved arrow notation shows the movement of valence electrons, not atoms. The movement of two valence electrons is shown by curved arrow. To represent bond breaking, the tail of the arrow originates from the center of a bond whereas to represent bond formation, the head of arrow points to an atom which forms the new bond, that is, bond or the region where the bond is formed if the new bond is a bond. The conjugate acid is the species that the base becomes after gaining a proton, and the conjugate base is the species that the acid becomes after losing a proton.

Expert Solution

Answer to Problem 6.38P

For the given proton transfer reaction the products are drawn as below.

EBK GET READY FOR ORGANIC CHEMISTRY, Chapter 6, Problem 6.38P , additional homework tip 8

Explanation of Solution

The curved arrow notation for the given proton transfer reaction is shown below:

EBK GET READY FOR ORGANIC CHEMISTRY, Chapter 6, Problem 6.38P , additional homework tip 9

In a proton transfer reaction, a proton is transferred from the Bronsted-Lowry acid to the Bronsted-Lowry base. The movement of two valence electrons is shown by curved arrow. The head of the arrow pointing to atom shows the transfer of valence electrons to form a new single bond. In the above reaction, one curved arrow is drawn from the lone pair on H to the H of the first reactant, so it illustrates the formation of a new H-H bond in the second reactant. The tail of the second arrow originates from the center of the S-H bond, so it illustrates the breaking of that bond, and it points to the S atom, showing that those electrons end up as a lone pair on S of the first reactant. Therefore, for the given proton transfer reaction, the products are as drawn below:

EBK GET READY FOR ORGANIC CHEMISTRY, Chapter 6, Problem 6.38P , additional homework tip 10

Conclusion

The products of the given proton transfer reaction are drawn on the basis of the curved arrow notation that shows breaking and formation of bonds.

Interpretation Introduction

(c)

Interpretation:

Appropriate products are to be drawn for the given proton transfer reaction with curved arrow notation.

Concept introduction:

In a proton transfer reaction, a proton is transferred from a Bronsted-Lowry acid to a Bronsted-Lowry base in a single elementary step in which one bond is broken and another is formed simultaneously. The curved arrow notation shows the movement of valence electrons, not atoms. The movement of two valence electrons is shown by curved arrow. To represent bond breaking, the tail of the arrow originates from the center of a bond whereas to represent bond formation, the head of arrow points to an atom which forms the new bond, that is, bond or the region where the bond is formed if the new bond is a bond. The conjugate acid is the species that the base becomes after gaining a proton, and the conjugate base is the species that the acid becomes after losing a proton.

Expert Solution

Answer to Problem 6.38P

For the given proton transfer reaction, the products are drawn as below.

EBK GET READY FOR ORGANIC CHEMISTRY, Chapter 6, Problem 6.38P , additional homework tip 13

Explanation of Solution

The curved arrow notation for the given proton transfer reaction is shown below:

EBK GET READY FOR ORGANIC CHEMISTRY, Chapter 6, Problem 6.38P , additional homework tip 14

In a proton transfer reaction, a proton is transferred from the Bronsted-Lowry acid to the Bronsted-Lowry base. The movement of two valence electrons is shown by curved arrow. The head of the arrow pointing to an atom shows the transfer of valence electrons to form a new single bond. In the above reaction, one curved arrow is drawn from the lone pair on N to the H of the second reactant, so it illustrates the formation of a new N-H bond in the first reactant. The tail of the second arrow originates from the center of the O-H bond, so it illustrates the breaking of that bond, and it points to the O atom, showing that those electrons end up as a lone pair on the O of the second reactant. Therefore, for the given proton transfer reaction, the products are as drawn below:

EBK GET READY FOR ORGANIC CHEMISTRY, Chapter 6, Problem 6.38P , additional homework tip 15

Conclusion

The products of the given proton transfer reaction are drawn on the basis of the curved arrow notation that shows breaking and formation of bonds.

Interpretation Introduction

(d)

Interpretation:

Appropriate products are to be drawn for the given proton transfer reaction with curved arrow notation.

Concept introduction:

In a proton transfer reaction, a proton is transferred from a Bronsted-Lowry acid to a Bronsted-Lowry base in a single elementary step in which one bond is broken and another is formed simultaneously. The curved arrow notation shows the movement of valence electrons, not atoms. The movement of two valence electrons is shown by curved arrow. To represent bond breaking, the tail of the arrow originates from the center of a bond whereas to represent bond formation, the head of arrow points to an atom which forms the new bond, that is, bond or the region where the bond is formed if the new bond is a bond. The conjugate acid is the species that the base becomes after gaining a proton, and the conjugate base is the species that the acid becomes after losing a proton.

Expert Solution

Answer to Problem 6.38P

For the given proton transfer reaction, the products are drawn as below.

EBK GET READY FOR ORGANIC CHEMISTRY, Chapter 6, Problem 6.38P , additional homework tip 18

Explanation of Solution

The curved arrow notation for the given proton transfer reaction are shown below:

EBK GET READY FOR ORGANIC CHEMISTRY, Chapter 6, Problem 6.38P , additional homework tip 19

In a proton transfer reaction, a proton is transferred from the Bronsted-Lowry acid to the Bronsted-Lowry base. The movement of two valence electrons is shown by curved arrow. The head of the arrow pointing to an atom shows the transfer of valence electrons to form a new single bond. In the above reaction, one curved arrow is drawn from the lone pair on O to the H of the first reactant, so it illustrates the formation of a new O-H bond in the second reactant. The tail of the second arrow originates from the center of the O-H bond, so it illustratea the breaking of that bond, and it points to the O atom, showing that those electrons end up as a lone pair on the O of the first reactant. Therefore, For the given proton transfer reaction, the products are drawn as below:

EBK GET READY FOR ORGANIC CHEMISTRY, Chapter 6, Problem 6.38P , additional homework tip 20

Conclusion

The products of the given proton transfer reaction are drawn on the basis of the curved arrow notation that shows breaking and formation of bonds.

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Answer 2

Question

Chapter 6, Problem 6.38P

Interpretation Introduction

(a)

Interpretation:

Appropriate products are to be drawn for the given proton transfer reaction with curved arrow notation.

Concept introduction:

In a proton transfer reaction, a proton is transferred from a Bronsted-Lowry acid to a Bronsted-Lowry base in a single elementary step in which one bond is broken and another is formed simultaneously. The curved arrow notation shows the movement of valence electrons, not atoms. The movement of two valence electrons is shown by curved arrow. To represent bond breaking, the tail of the arrow originates from the center of a bond whereas to represent bond formation, the head of arrow points to an atom which forms the new bond, that is, bond or the region where the bond is formed if the new bond is a bond. The conjugate acid is the species that the base becomes after gaining a proton, and the conjugate base is the species that the acid becomes after losing a proton.

Expert Solution

Answer to Problem 6.38P

For the given proton transfer reaction, the products are as shown below.

EBK GET READY FOR ORGANIC CHEMISTRY, Chapter 6, Problem 6.38P , additional homework tip 3

Explanation of Solution

The curved arrow notation for the given proton transfer reaction is shown below:

EBK GET READY FOR ORGANIC CHEMISTRY, Chapter 6, Problem 6.38P , additional homework tip 4

In a proton transfer reaction, a proton is transferred from the Bronsted-Lowry acid to the Bronsted-Lowry base. The movement of two valence electrons is shown by curved arrow. The head of the arrow pointing to the atom shows the transfer of valence electrons to form a new single bond. In the above reaction, one curved arrow is drawn from the lone pair on O to the H on the other reactant, so it illustrates the formation of a new O-H bond in the first reactant. The tail of the second arrow originates from the center of O-H bond, so it illustrate the breaking of that bond, and it points to the O atom, showing that those electrons end up as a lone pair on O of the second reactant. Therefore, for the given proton transfer reaction, the products are as drawn below:

EBK GET READY FOR ORGANIC CHEMISTRY, Chapter 6, Problem 6.38P , additional homework tip 5

Conclusion

The products of the given proton transfer reaction are drawn on the basis of the curved arrow notation that shows breaking and formation of bonds.

Interpretation Introduction

(b)

Interpretation:

Appropriate products are to be drawn for the given proton transfer reaction with curved arrow notation.

Concept introduction:

In a proton transfer reaction, a proton is transferred from a Bronsted-Lowry acid to a Bronsted-Lowry base in a single elementary step in which one bond is broken and another is formed simultaneously. The curved arrow notation shows the movement of valence electrons, not atoms. The movement of two valence electrons is shown by curved arrow. To represent bond breaking, the tail of the arrow originates from the center of a bond whereas to represent bond formation, the head of arrow points to an atom which forms the new bond, that is, bond or the region where the bond is formed if the new bond is a bond. The conjugate acid is the species that the base becomes after gaining a proton, and the conjugate base is the species that the acid becomes after losing a proton.

Expert Solution

Answer to Problem 6.38P

For the given proton transfer reaction the products are drawn as below.

EBK GET READY FOR ORGANIC CHEMISTRY, Chapter 6, Problem 6.38P , additional homework tip 8

Explanation of Solution

The curved arrow notation for the given proton transfer reaction is shown below:

EBK GET READY FOR ORGANIC CHEMISTRY, Chapter 6, Problem 6.38P , additional homework tip 9

In a proton transfer reaction, a proton is transferred from the Bronsted-Lowry acid to the Bronsted-Lowry base. The movement of two valence electrons is shown by curved arrow. The head of the arrow pointing to atom shows the transfer of valence electrons to form a new single bond. In the above reaction, one curved arrow is drawn from the lone pair on H to the H of the first reactant, so it illustrates the formation of a new H-H bond in the second reactant. The tail of the second arrow originates from the center of the S-H bond, so it illustrates the breaking of that bond, and it points to the S atom, showing that those electrons end up as a lone pair on S of the first reactant. Therefore, for the given proton transfer reaction, the products are as drawn below:

EBK GET READY FOR ORGANIC CHEMISTRY, Chapter 6, Problem 6.38P , additional homework tip 10

Conclusion

The products of the given proton transfer reaction are drawn on the basis of the curved arrow notation that shows breaking and formation of bonds.

Interpretation Introduction

(c)

Interpretation:

Appropriate products are to be drawn for the given proton transfer reaction with curved arrow notation.

Concept introduction:

In a proton transfer reaction, a proton is transferred from a Bronsted-Lowry acid to a Bronsted-Lowry base in a single elementary step in which one bond is broken and another is formed simultaneously. The curved arrow notation shows the movement of valence electrons, not atoms. The movement of two valence electrons is shown by curved arrow. To represent bond breaking, the tail of the arrow originates from the center of a bond whereas to represent bond formation, the head of arrow points to an atom which forms the new bond, that is, bond or the region where the bond is formed if the new bond is a bond. The conjugate acid is the species that the base becomes after gaining a proton, and the conjugate base is the species that the acid becomes after losing a proton.

Expert Solution

Answer to Problem 6.38P

For the given proton transfer reaction, the products are drawn as below.

EBK GET READY FOR ORGANIC CHEMISTRY, Chapter 6, Problem 6.38P , additional homework tip 13

Explanation of Solution

The curved arrow notation for the given proton transfer reaction is shown below:

EBK GET READY FOR ORGANIC CHEMISTRY, Chapter 6, Problem 6.38P , additional homework tip 14

In a proton transfer reaction, a proton is transferred from the Bronsted-Lowry acid to the Bronsted-Lowry base. The movement of two valence electrons is shown by curved arrow. The head of the arrow pointing to an atom shows the transfer of valence electrons to form a new single bond. In the above reaction, one curved arrow is drawn from the lone pair on N to the H of the second reactant, so it illustrates the formation of a new N-H bond in the first reactant. The tail of the second arrow originates from the center of the O-H bond, so it illustrates the breaking of that bond, and it points to the O atom, showing that those electrons end up as a lone pair on the O of the second reactant. Therefore, for the given proton transfer reaction, the products are as drawn below:

EBK GET READY FOR ORGANIC CHEMISTRY, Chapter 6, Problem 6.38P , additional homework tip 15

Conclusion

The products of the given proton transfer reaction are drawn on the basis of the curved arrow notation that shows breaking and formation of bonds.

Interpretation Introduction

(d)

Interpretation:

Appropriate products are to be drawn for the given proton transfer reaction with curved arrow notation.

Concept introduction:

In a proton transfer reaction, a proton is transferred from a Bronsted-Lowry acid to a Bronsted-Lowry base in a single elementary step in which one bond is broken and another is formed simultaneously. The curved arrow notation shows the movement of valence electrons, not atoms. The movement of two valence electrons is shown by curved arrow. To represent bond breaking, the tail of the arrow originates from the center of a bond whereas to represent bond formation, the head of arrow points to an atom which forms the new bond, that is, bond or the region where the bond is formed if the new bond is a bond. The conjugate acid is the species that the base becomes after gaining a proton, and the conjugate base is the species that the acid becomes after losing a proton.

Expert Solution

Answer to Problem 6.38P

For the given proton transfer reaction, the products are drawn as below.

EBK GET READY FOR ORGANIC CHEMISTRY, Chapter 6, Problem 6.38P , additional homework tip 18

Explanation of Solution

The curved arrow notation for the given proton transfer reaction are shown below:

EBK GET READY FOR ORGANIC CHEMISTRY, Chapter 6, Problem 6.38P , additional homework tip 19

In a proton transfer reaction, a proton is transferred from the Bronsted-Lowry acid to the Bronsted-Lowry base. The movement of two valence electrons is shown by curved arrow. The head of the arrow pointing to an atom shows the transfer of valence electrons to form a new single bond. In the above reaction, one curved arrow is drawn from the lone pair on O to the H of the first reactant, so it illustrates the formation of a new O-H bond in the second reactant. The tail of the second arrow originates from the center of the O-H bond, so it illustratea the breaking of that bond, and it points to the O atom, showing that those electrons end up as a lone pair on the O of the first reactant. Therefore, For the given proton transfer reaction, the products are drawn as below:

EBK GET READY FOR ORGANIC CHEMISTRY, Chapter 6, Problem 6.38P , additional homework tip 20

Conclusion

The products of the given proton transfer reaction are drawn on the basis of the curved arrow notation that shows breaking and formation of bonds.

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Answer 3

Question

Chapter 6, Problem 6.38P

Interpretation Introduction

(a)

Interpretation:

Appropriate products are to be drawn for the given proton transfer reaction with curved arrow notation.

Concept introduction:

In a proton transfer reaction, a proton is transferred from a Bronsted-Lowry acid to a Bronsted-Lowry base in a single elementary step in which one bond is broken and another is formed simultaneously. The curved arrow notation shows the movement of valence electrons, not atoms. The movement of two valence electrons is shown by curved arrow. To represent bond breaking, the tail of the arrow originates from the center of a bond whereas to represent bond formation, the head of arrow points to an atom which forms the new bond, that is, bond or the region where the bond is formed if the new bond is a bond. The conjugate acid is the species that the base becomes after gaining a proton, and the conjugate base is the species that the acid becomes after losing a proton.

Expert Solution

Answer to Problem 6.38P

For the given proton transfer reaction, the products are as shown below.

EBK GET READY FOR ORGANIC CHEMISTRY, Chapter 6, Problem 6.38P , additional homework tip 3

Explanation of Solution

The curved arrow notation for the given proton transfer reaction is shown below:

EBK GET READY FOR ORGANIC CHEMISTRY, Chapter 6, Problem 6.38P , additional homework tip 4

In a proton transfer reaction, a proton is transferred from the Bronsted-Lowry acid to the Bronsted-Lowry base. The movement of two valence electrons is shown by curved arrow. The head of the arrow pointing to the atom shows the transfer of valence electrons to form a new single bond. In the above reaction, one curved arrow is drawn from the lone pair on O to the H on the other reactant, so it illustrates the formation of a new O-H bond in the first reactant. The tail of the second arrow originates from the center of O-H bond, so it illustrate the breaking of that bond, and it points to the O atom, showing that those electrons end up as a lone pair on O of the second reactant. Therefore, for the given proton transfer reaction, the products are as drawn below:

EBK GET READY FOR ORGANIC CHEMISTRY, Chapter 6, Problem 6.38P , additional homework tip 5

Conclusion

The products of the given proton transfer reaction are drawn on the basis of the curved arrow notation that shows breaking and formation of bonds.

Interpretation Introduction

(b)

Interpretation:

Appropriate products are to be drawn for the given proton transfer reaction with curved arrow notation.

Concept introduction:

In a proton transfer reaction, a proton is transferred from a Bronsted-Lowry acid to a Bronsted-Lowry base in a single elementary step in which one bond is broken and another is formed simultaneously. The curved arrow notation shows the movement of valence electrons, not atoms. The movement of two valence electrons is shown by curved arrow. To represent bond breaking, the tail of the arrow originates from the center of a bond whereas to represent bond formation, the head of arrow points to an atom which forms the new bond, that is, bond or the region where the bond is formed if the new bond is a bond. The conjugate acid is the species that the base becomes after gaining a proton, and the conjugate base is the species that the acid becomes after losing a proton.

Expert Solution

Answer to Problem 6.38P

For the given proton transfer reaction the products are drawn as below.

EBK GET READY FOR ORGANIC CHEMISTRY, Chapter 6, Problem 6.38P , additional homework tip 8

Explanation of Solution

The curved arrow notation for the given proton transfer reaction is shown below:

EBK GET READY FOR ORGANIC CHEMISTRY, Chapter 6, Problem 6.38P , additional homework tip 9

In a proton transfer reaction, a proton is transferred from the Bronsted-Lowry acid to the Bronsted-Lowry base. The movement of two valence electrons is shown by curved arrow. The head of the arrow pointing to atom shows the transfer of valence electrons to form a new single bond. In the above reaction, one curved arrow is drawn from the lone pair on H to the H of the first reactant, so it illustrates the formation of a new H-H bond in the second reactant. The tail of the second arrow originates from the center of the S-H bond, so it illustrates the breaking of that bond, and it points to the S atom, showing that those electrons end up as a lone pair on S of the first reactant. Therefore, for the given proton transfer reaction, the products are as drawn below:

EBK GET READY FOR ORGANIC CHEMISTRY, Chapter 6, Problem 6.38P , additional homework tip 10

Conclusion

The products of the given proton transfer reaction are drawn on the basis of the curved arrow notation that shows breaking and formation of bonds.

Interpretation Introduction

(c)

Interpretation:

Appropriate products are to be drawn for the given proton transfer reaction with curved arrow notation.

Concept introduction:

In a proton transfer reaction, a proton is transferred from a Bronsted-Lowry acid to a Bronsted-Lowry base in a single elementary step in which one bond is broken and another is formed simultaneously. The curved arrow notation shows the movement of valence electrons, not atoms. The movement of two valence electrons is shown by curved arrow. To represent bond breaking, the tail of the arrow originates from the center of a bond whereas to represent bond formation, the head of arrow points to an atom which forms the new bond, that is, bond or the region where the bond is formed if the new bond is a bond. The conjugate acid is the species that the base becomes after gaining a proton, and the conjugate base is the species that the acid becomes after losing a proton.

Expert Solution

Answer to Problem 6.38P

For the given proton transfer reaction, the products are drawn as below.

EBK GET READY FOR ORGANIC CHEMISTRY, Chapter 6, Problem 6.38P , additional homework tip 13

Explanation of Solution

The curved arrow notation for the given proton transfer reaction is shown below:

EBK GET READY FOR ORGANIC CHEMISTRY, Chapter 6, Problem 6.38P , additional homework tip 14

In a proton transfer reaction, a proton is transferred from the Bronsted-Lowry acid to the Bronsted-Lowry base. The movement of two valence electrons is shown by curved arrow. The head of the arrow pointing to an atom shows the transfer of valence electrons to form a new single bond. In the above reaction, one curved arrow is drawn from the lone pair on N to the H of the second reactant, so it illustrates the formation of a new N-H bond in the first reactant. The tail of the second arrow originates from the center of the O-H bond, so it illustrates the breaking of that bond, and it points to the O atom, showing that those electrons end up as a lone pair on the O of the second reactant. Therefore, for the given proton transfer reaction, the products are as drawn below:

EBK GET READY FOR ORGANIC CHEMISTRY, Chapter 6, Problem 6.38P , additional homework tip 15

Conclusion

The products of the given proton transfer reaction are drawn on the basis of the curved arrow notation that shows breaking and formation of bonds.

Interpretation Introduction

(d)

Interpretation:

Appropriate products are to be drawn for the given proton transfer reaction with curved arrow notation.

Concept introduction:

In a proton transfer reaction, a proton is transferred from a Bronsted-Lowry acid to a Bronsted-Lowry base in a single elementary step in which one bond is broken and another is formed simultaneously. The curved arrow notation shows the movement of valence electrons, not atoms. The movement of two valence electrons is shown by curved arrow. To represent bond breaking, the tail of the arrow originates from the center of a bond whereas to represent bond formation, the head of arrow points to an atom which forms the new bond, that is, bond or the region where the bond is formed if the new bond is a bond. The conjugate acid is the species that the base becomes after gaining a proton, and the conjugate base is the species that the acid becomes after losing a proton.

Expert Solution

Answer to Problem 6.38P

For the given proton transfer reaction, the products are drawn as below.

EBK GET READY FOR ORGANIC CHEMISTRY, Chapter 6, Problem 6.38P , additional homework tip 18

Explanation of Solution

The curved arrow notation for the given proton transfer reaction are shown below:

EBK GET READY FOR ORGANIC CHEMISTRY, Chapter 6, Problem 6.38P , additional homework tip 19

In a proton transfer reaction, a proton is transferred from the Bronsted-Lowry acid to the Bronsted-Lowry base. The movement of two valence electrons is shown by curved arrow. The head of the arrow pointing to an atom shows the transfer of valence electrons to form a new single bond. In the above reaction, one curved arrow is drawn from the lone pair on O to the H of the first reactant, so it illustrates the formation of a new O-H bond in the second reactant. The tail of the second arrow originates from the center of the O-H bond, so it illustratea the breaking of that bond, and it points to the O atom, showing that those electrons end up as a lone pair on the O of the first reactant. Therefore, For the given proton transfer reaction, the products are drawn as below:

EBK GET READY FOR ORGANIC CHEMISTRY, Chapter 6, Problem 6.38P , additional homework tip 20

Conclusion

The products of the given proton transfer reaction are drawn on the basis of the curved arrow notation that shows breaking and formation of bonds.

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Subscribe now to access step-by-step solutions to millions of textbook problems written by subject matter experts!

Answer 4

Question

Chapter 6, Problem 6.38P

Interpretation Introduction

(a)

Interpretation:

Appropriate products are to be drawn for the given proton transfer reaction with curved arrow notation.

Concept introduction:

In a proton transfer reaction, a proton is transferred from a Bronsted-Lowry acid to a Bronsted-Lowry base in a single elementary step in which one bond is broken and another is formed simultaneously. The curved arrow notation shows the movement of valence electrons, not atoms. The movement of two valence electrons is shown by curved arrow. To represent bond breaking, the tail of the arrow originates from the center of a bond whereas to represent bond formation, the head of arrow points to an atom which forms the new bond, that is, bond or the region where the bond is formed if the new bond is a bond. The conjugate acid is the species that the base becomes after gaining a proton, and the conjugate base is the species that the acid becomes after losing a proton.

Expert Solution

Answer to Problem 6.38P

For the given proton transfer reaction, the products are as shown below.

EBK GET READY FOR ORGANIC CHEMISTRY, Chapter 6, Problem 6.38P , additional homework tip 3

Explanation of Solution

The curved arrow notation for the given proton transfer reaction is shown below:

EBK GET READY FOR ORGANIC CHEMISTRY, Chapter 6, Problem 6.38P , additional homework tip 4

In a proton transfer reaction, a proton is transferred from the Bronsted-Lowry acid to the Bronsted-Lowry base. The movement of two valence electrons is shown by curved arrow. The head of the arrow pointing to the atom shows the transfer of valence electrons to form a new single bond. In the above reaction, one curved arrow is drawn from the lone pair on O to the H on the other reactant, so it illustrates the formation of a new O-H bond in the first reactant. The tail of the second arrow originates from the center of O-H bond, so it illustrate the breaking of that bond, and it points to the O atom, showing that those electrons end up as a lone pair on O of the second reactant. Therefore, for the given proton transfer reaction, the products are as drawn below:

EBK GET READY FOR ORGANIC CHEMISTRY, Chapter 6, Problem 6.38P , additional homework tip 5

Conclusion

The products of the given proton transfer reaction are drawn on the basis of the curved arrow notation that shows breaking and formation of bonds.

Interpretation Introduction

(b)

Interpretation:

Appropriate products are to be drawn for the given proton transfer reaction with curved arrow notation.

Concept introduction:

In a proton transfer reaction, a proton is transferred from a Bronsted-Lowry acid to a Bronsted-Lowry base in a single elementary step in which one bond is broken and another is formed simultaneously. The curved arrow notation shows the movement of valence electrons, not atoms. The movement of two valence electrons is shown by curved arrow. To represent bond breaking, the tail of the arrow originates from the center of a bond whereas to represent bond formation, the head of arrow points to an atom which forms the new bond, that is, bond or the region where the bond is formed if the new bond is a bond. The conjugate acid is the species that the base becomes after gaining a proton, and the conjugate base is the species that the acid becomes after losing a proton.

Expert Solution

Answer to Problem 6.38P

For the given proton transfer reaction the products are drawn as below.

EBK GET READY FOR ORGANIC CHEMISTRY, Chapter 6, Problem 6.38P , additional homework tip 8

Explanation of Solution

The curved arrow notation for the given proton transfer reaction is shown below:

EBK GET READY FOR ORGANIC CHEMISTRY, Chapter 6, Problem 6.38P , additional homework tip 9

In a proton transfer reaction, a proton is transferred from the Bronsted-Lowry acid to the Bronsted-Lowry base. The movement of two valence electrons is shown by curved arrow. The head of the arrow pointing to atom shows the transfer of valence electrons to form a new single bond. In the above reaction, one curved arrow is drawn from the lone pair on H to the H of the first reactant, so it illustrates the formation of a new H-H bond in the second reactant. The tail of the second arrow originates from the center of the S-H bond, so it illustrates the breaking of that bond, and it points to the S atom, showing that those electrons end up as a lone pair on S of the first reactant. Therefore, for the given proton transfer reaction, the products are as drawn below:

EBK GET READY FOR ORGANIC CHEMISTRY, Chapter 6, Problem 6.38P , additional homework tip 10

Conclusion

The products of the given proton transfer reaction are drawn on the basis of the curved arrow notation that shows breaking and formation of bonds.

Interpretation Introduction

(c)

Interpretation:

Appropriate products are to be drawn for the given proton transfer reaction with curved arrow notation.

Concept introduction:

In a proton transfer reaction, a proton is transferred from a Bronsted-Lowry acid to a Bronsted-Lowry base in a single elementary step in which one bond is broken and another is formed simultaneously. The curved arrow notation shows the movement of valence electrons, not atoms. The movement of two valence electrons is shown by curved arrow. To represent bond breaking, the tail of the arrow originates from the center of a bond whereas to represent bond formation, the head of arrow points to an atom which forms the new bond, that is, bond or the region where the bond is formed if the new bond is a bond. The conjugate acid is the species that the base becomes after gaining a proton, and the conjugate base is the species that the acid becomes after losing a proton.

Expert Solution

Answer to Problem 6.38P

For the given proton transfer reaction, the products are drawn as below.

EBK GET READY FOR ORGANIC CHEMISTRY, Chapter 6, Problem 6.38P , additional homework tip 13

Explanation of Solution

The curved arrow notation for the given proton transfer reaction is shown below:

EBK GET READY FOR ORGANIC CHEMISTRY, Chapter 6, Problem 6.38P , additional homework tip 14

In a proton transfer reaction, a proton is transferred from the Bronsted-Lowry acid to the Bronsted-Lowry base. The movement of two valence electrons is shown by curved arrow. The head of the arrow pointing to an atom shows the transfer of valence electrons to form a new single bond. In the above reaction, one curved arrow is drawn from the lone pair on N to the H of the second reactant, so it illustrates the formation of a new N-H bond in the first reactant. The tail of the second arrow originates from the center of the O-H bond, so it illustrates the breaking of that bond, and it points to the O atom, showing that those electrons end up as a lone pair on the O of the second reactant. Therefore, for the given proton transfer reaction, the products are as drawn below:

EBK GET READY FOR ORGANIC CHEMISTRY, Chapter 6, Problem 6.38P , additional homework tip 15

Conclusion

The products of the given proton transfer reaction are drawn on the basis of the curved arrow notation that shows breaking and formation of bonds.

Interpretation Introduction

(d)

Interpretation:

Appropriate products are to be drawn for the given proton transfer reaction with curved arrow notation.

Concept introduction:

In a proton transfer reaction, a proton is transferred from a Bronsted-Lowry acid to a Bronsted-Lowry base in a single elementary step in which one bond is broken and another is formed simultaneously. The curved arrow notation shows the movement of valence electrons, not atoms. The movement of two valence electrons is shown by curved arrow. To represent bond breaking, the tail of the arrow originates from the center of a bond whereas to represent bond formation, the head of arrow points to an atom which forms the new bond, that is, bond or the region where the bond is formed if the new bond is a bond. The conjugate acid is the species that the base becomes after gaining a proton, and the conjugate base is the species that the acid becomes after losing a proton.

Expert Solution

Answer to Problem 6.38P

For the given proton transfer reaction, the products are drawn as below.

EBK GET READY FOR ORGANIC CHEMISTRY, Chapter 6, Problem 6.38P , additional homework tip 18

Explanation of Solution

The curved arrow notation for the given proton transfer reaction are shown below:

EBK GET READY FOR ORGANIC CHEMISTRY, Chapter 6, Problem 6.38P , additional homework tip 19

In a proton transfer reaction, a proton is transferred from the Bronsted-Lowry acid to the Bronsted-Lowry base. The movement of two valence electrons is shown by curved arrow. The head of the arrow pointing to an atom shows the transfer of valence electrons to form a new single bond. In the above reaction, one curved arrow is drawn from the lone pair on O to the H of the first reactant, so it illustrates the formation of a new O-H bond in the second reactant. The tail of the second arrow originates from the center of the O-H bond, so it illustratea the breaking of that bond, and it points to the O atom, showing that those electrons end up as a lone pair on the O of the first reactant. Therefore, For the given proton transfer reaction, the products are drawn as below:

EBK GET READY FOR ORGANIC CHEMISTRY, Chapter 6, Problem 6.38P , additional homework tip 20

Conclusion

The products of the given proton transfer reaction are drawn on the basis of the curved arrow notation that shows breaking and formation of bonds.

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Answer 5

Chapter 6, Problem 6.38P

Interpretation Introduction

(a)

Interpretation:

Appropriate products are to be drawn for the given proton transfer reaction with curved arrow notation.

Concept introduction:

In a proton transfer reaction, a proton is transferred from a Bronsted-Lowry acid to a Bronsted-Lowry base in a single elementary step in which one bond is broken and another is formed simultaneously. The curved arrow notation shows the movement of valence electrons, not atoms. The movement of two valence electrons is shown by curved arrow. To represent bond breaking, the tail of the arrow originates from the center of a bond whereas to represent bond formation, the head of arrow points to an atom which forms the new bond, that is, bond or the region where the bond is formed if the new bond is a bond. The conjugate acid is the species that the base becomes after gaining a proton, and the conjugate base is the species that the acid becomes after losing a proton.

Expert Solution

Answer to Problem 6.38P

For the given proton transfer reaction, the products are as shown below.

EBK GET READY FOR ORGANIC CHEMISTRY, Chapter 6, Problem 6.38P , additional homework tip 3

Explanation of Solution

The curved arrow notation for the given proton transfer reaction is shown below:

EBK GET READY FOR ORGANIC CHEMISTRY, Chapter 6, Problem 6.38P , additional homework tip 4

In a proton transfer reaction, a proton is transferred from the Bronsted-Lowry acid to the Bronsted-Lowry base. The movement of two valence electrons is shown by curved arrow. The head of the arrow pointing to the atom shows the transfer of valence electrons to form a new single bond. In the above reaction, one curved arrow is drawn from the lone pair on O to the H on the other reactant, so it illustrates the formation of a new O-H bond in the first reactant. The tail of the second arrow originates from the center of O-H bond, so it illustrate the breaking of that bond, and it points to the O atom, showing that those electrons end up as a lone pair on O of the second reactant. Therefore, for the given proton transfer reaction, the products are as drawn below:

EBK GET READY FOR ORGANIC CHEMISTRY, Chapter 6, Problem 6.38P , additional homework tip 5

Conclusion

The products of the given proton transfer reaction are drawn on the basis of the curved arrow notation that shows breaking and formation of bonds.

Interpretation Introduction

(b)

Interpretation:

Appropriate products are to be drawn for the given proton transfer reaction with curved arrow notation.

Concept introduction:

In a proton transfer reaction, a proton is transferred from a Bronsted-Lowry acid to a Bronsted-Lowry base in a single elementary step in which one bond is broken and another is formed simultaneously. The curved arrow notation shows the movement of valence electrons, not atoms. The movement of two valence electrons is shown by curved arrow. To represent bond breaking, the tail of the arrow originates from the center of a bond whereas to represent bond formation, the head of arrow points to an atom which forms the new bond, that is, bond or the region where the bond is formed if the new bond is a bond. The conjugate acid is the species that the base becomes after gaining a proton, and the conjugate base is the species that the acid becomes after losing a proton.

Expert Solution

Answer to Problem 6.38P

For the given proton transfer reaction the products are drawn as below.

EBK GET READY FOR ORGANIC CHEMISTRY, Chapter 6, Problem 6.38P , additional homework tip 8

Explanation of Solution

The curved arrow notation for the given proton transfer reaction is shown below:

EBK GET READY FOR ORGANIC CHEMISTRY, Chapter 6, Problem 6.38P , additional homework tip 9

In a proton transfer reaction, a proton is transferred from the Bronsted-Lowry acid to the Bronsted-Lowry base. The movement of two valence electrons is shown by curved arrow. The head of the arrow pointing to atom shows the transfer of valence electrons to form a new single bond. In the above reaction, one curved arrow is drawn from the lone pair on H to the H of the first reactant, so it illustrates the formation of a new H-H bond in the second reactant. The tail of the second arrow originates from the center of the S-H bond, so it illustrates the breaking of that bond, and it points to the S atom, showing that those electrons end up as a lone pair on S of the first reactant. Therefore, for the given proton transfer reaction, the products are as drawn below:

EBK GET READY FOR ORGANIC CHEMISTRY, Chapter 6, Problem 6.38P , additional homework tip 10

Conclusion

The products of the given proton transfer reaction are drawn on the basis of the curved arrow notation that shows breaking and formation of bonds.

Interpretation Introduction

(c)

Interpretation:

Appropriate products are to be drawn for the given proton transfer reaction with curved arrow notation.

Concept introduction:

In a proton transfer reaction, a proton is transferred from a Bronsted-Lowry acid to a Bronsted-Lowry base in a single elementary step in which one bond is broken and another is formed simultaneously. The curved arrow notation shows the movement of valence electrons, not atoms. The movement of two valence electrons is shown by curved arrow. To represent bond breaking, the tail of the arrow originates from the center of a bond whereas to represent bond formation, the head of arrow points to an atom which forms the new bond, that is, bond or the region where the bond is formed if the new bond is a bond. The conjugate acid is the species that the base becomes after gaining a proton, and the conjugate base is the species that the acid becomes after losing a proton.

Expert Solution

Answer to Problem 6.38P

For the given proton transfer reaction, the products are drawn as below.

EBK GET READY FOR ORGANIC CHEMISTRY, Chapter 6, Problem 6.38P , additional homework tip 13

Explanation of Solution

The curved arrow notation for the given proton transfer reaction is shown below:

EBK GET READY FOR ORGANIC CHEMISTRY, Chapter 6, Problem 6.38P , additional homework tip 14

In a proton transfer reaction, a proton is transferred from the Bronsted-Lowry acid to the Bronsted-Lowry base. The movement of two valence electrons is shown by curved arrow. The head of the arrow pointing to an atom shows the transfer of valence electrons to form a new single bond. In the above reaction, one curved arrow is drawn from the lone pair on N to the H of the second reactant, so it illustrates the formation of a new N-H bond in the first reactant. The tail of the second arrow originates from the center of the O-H bond, so it illustrates the breaking of that bond, and it points to the O atom, showing that those electrons end up as a lone pair on the O of the second reactant. Therefore, for the given proton transfer reaction, the products are as drawn below:

EBK GET READY FOR ORGANIC CHEMISTRY, Chapter 6, Problem 6.38P , additional homework tip 15

Conclusion

The products of the given proton transfer reaction are drawn on the basis of the curved arrow notation that shows breaking and formation of bonds.

Interpretation Introduction

(d)

Interpretation:

Appropriate products are to be drawn for the given proton transfer reaction with curved arrow notation.

Concept introduction:

In a proton transfer reaction, a proton is transferred from a Bronsted-Lowry acid to a Bronsted-Lowry base in a single elementary step in which one bond is broken and another is formed simultaneously. The curved arrow notation shows the movement of valence electrons, not atoms. The movement of two valence electrons is shown by curved arrow. To represent bond breaking, the tail of the arrow originates from the center of a bond whereas to represent bond formation, the head of arrow points to an atom which forms the new bond, that is, bond or the region where the bond is formed if the new bond is a bond. The conjugate acid is the species that the base becomes after gaining a proton, and the conjugate base is the species that the acid becomes after losing a proton.

Expert Solution

Answer to Problem 6.38P

For the given proton transfer reaction, the products are drawn as below.

EBK GET READY FOR ORGANIC CHEMISTRY, Chapter 6, Problem 6.38P , additional homework tip 18

Explanation of Solution

The curved arrow notation for the given proton transfer reaction are shown below:

EBK GET READY FOR ORGANIC CHEMISTRY, Chapter 6, Problem 6.38P , additional homework tip 19

In a proton transfer reaction, a proton is transferred from the Bronsted-Lowry acid to the Bronsted-Lowry base. The movement of two valence electrons is shown by curved arrow. The head of the arrow pointing to an atom shows the transfer of valence electrons to form a new single bond. In the above reaction, one curved arrow is drawn from the lone pair on O to the H of the first reactant, so it illustrates the formation of a new O-H bond in the second reactant. The tail of the second arrow originates from the center of the O-H bond, so it illustratea the breaking of that bond, and it points to the O atom, showing that those electrons end up as a lone pair on the O of the first reactant. Therefore, For the given proton transfer reaction, the products are drawn as below:

EBK GET READY FOR ORGANIC CHEMISTRY, Chapter 6, Problem 6.38P , additional homework tip 20

Conclusion

The products of the given proton transfer reaction are drawn on the basis of the curved arrow notation that shows breaking and formation of bonds.

Answer 6

Chapter 6, Problem 6.38P

Interpretation Introduction

(a)

Interpretation:

Appropriate products are to be drawn for the given proton transfer reaction with curved arrow notation.

Concept introduction:

In a proton transfer reaction, a proton is transferred from a Bronsted-Lowry acid to a Bronsted-Lowry base in a single elementary step in which one bond is broken and another is formed simultaneously. The curved arrow notation shows the movement of valence electrons, not atoms. The movement of two valence electrons is shown by curved arrow. To represent bond breaking, the tail of the arrow originates from the center of a bond whereas to represent bond formation, the head of arrow points to an atom which forms the new bond, that is, bond or the region where the bond is formed if the new bond is a bond. The conjugate acid is the species that the base becomes after gaining a proton, and the conjugate base is the species that the acid becomes after losing a proton.

Expert Solution

Answer to Problem 6.38P

For the given proton transfer reaction, the products are as shown below.

EBK GET READY FOR ORGANIC CHEMISTRY, Chapter 6, Problem 6.38P , additional homework tip 3

Explanation of Solution

The curved arrow notation for the given proton transfer reaction is shown below:

EBK GET READY FOR ORGANIC CHEMISTRY, Chapter 6, Problem 6.38P , additional homework tip 4

In a proton transfer reaction, a proton is transferred from the Bronsted-Lowry acid to the Bronsted-Lowry base. The movement of two valence electrons is shown by curved arrow. The head of the arrow pointing to the atom shows the transfer of valence electrons to form a new single bond. In the above reaction, one curved arrow is drawn from the lone pair on O to the H on the other reactant, so it illustrates the formation of a new O-H bond in the first reactant. The tail of the second arrow originates from the center of O-H bond, so it illustrate the breaking of that bond, and it points to the O atom, showing that those electrons end up as a lone pair on O of the second reactant. Therefore, for the given proton transfer reaction, the products are as drawn below:

EBK GET READY FOR ORGANIC CHEMISTRY, Chapter 6, Problem 6.38P , additional homework tip 5

Conclusion

The products of the given proton transfer reaction are drawn on the basis of the curved arrow notation that shows breaking and formation of bonds.

Answer 7

Chapter 6, Problem 6.38P

Interpretation Introduction

(a)

Interpretation:

Appropriate products are to be drawn for the given proton transfer reaction with curved arrow notation.

Concept introduction:

In a proton transfer reaction, a proton is transferred from a Bronsted-Lowry acid to a Bronsted-Lowry base in a single elementary step in which one bond is broken and another is formed simultaneously. The curved arrow notation shows the movement of valence electrons, not atoms. The movement of two valence electrons is shown by curved arrow. To represent bond breaking, the tail of the arrow originates from the center of a bond whereas to represent bond formation, the head of arrow points to an atom which forms the new bond, that is, bond or the region where the bond is formed if the new bond is a bond. The conjugate acid is the species that the base becomes after gaining a proton, and the conjugate base is the species that the acid becomes after losing a proton.

Answer 8

Expert Solution

Answer to Problem 6.38P

For the given proton transfer reaction, the products are as shown below.

EBK GET READY FOR ORGANIC CHEMISTRY, Chapter 6, Problem 6.38P , additional homework tip 3

Answer 9

Expert Solution

Answer 10

Expert Solution

Answer 11

Expert Solution

Answer 12

Explanation of Solution

The curved arrow notation for the given proton transfer reaction is shown below:

EBK GET READY FOR ORGANIC CHEMISTRY, Chapter 6, Problem 6.38P , additional homework tip 4

In a proton transfer reaction, a proton is transferred from the Bronsted-Lowry acid to the Bronsted-Lowry base. The movement of two valence electrons is shown by curved arrow. The head of the arrow pointing to the atom shows the transfer of valence electrons to form a new single bond. In the above reaction, one curved arrow is drawn from the lone pair on O to the H on the other reactant, so it illustrates the formation of a new O-H bond in the first reactant. The tail of the second arrow originates from the center of O-H bond, so it illustrate the breaking of that bond, and it points to the O atom, showing that those electrons end up as a lone pair on O of the second reactant. Therefore, for the given proton transfer reaction, the products are as drawn below:

EBK GET READY FOR ORGANIC CHEMISTRY, Chapter 6, Problem 6.38P , additional homework tip 5

Answer 13

Conclusion

The products of the given proton transfer reaction are drawn on the basis of the curved arrow notation that shows breaking and formation of bonds.

Answer 14

Interpretation Introduction

(b)

Interpretation:

Appropriate products are to be drawn for the given proton transfer reaction with curved arrow notation.

Concept introduction:

In a proton transfer reaction, a proton is transferred from a Bronsted-Lowry acid to a Bronsted-Lowry base in a single elementary step in which one bond is broken and another is formed simultaneously. The curved arrow notation shows the movement of valence electrons, not atoms. The movement of two valence electrons is shown by curved arrow. To represent bond breaking, the tail of the arrow originates from the center of a bond whereas to represent bond formation, the head of arrow points to an atom which forms the new bond, that is, bond or the region where the bond is formed if the new bond is a bond. The conjugate acid is the species that the base becomes after gaining a proton, and the conjugate base is the species that the acid becomes after losing a proton.

Expert Solution

Answer to Problem 6.38P

For the given proton transfer reaction the products are drawn as below.

EBK GET READY FOR ORGANIC CHEMISTRY, Chapter 6, Problem 6.38P , additional homework tip 8

Explanation of Solution

The curved arrow notation for the given proton transfer reaction is shown below:

EBK GET READY FOR ORGANIC CHEMISTRY, Chapter 6, Problem 6.38P , additional homework tip 9

In a proton transfer reaction, a proton is transferred from the Bronsted-Lowry acid to the Bronsted-Lowry base. The movement of two valence electrons is shown by curved arrow. The head of the arrow pointing to atom shows the transfer of valence electrons to form a new single bond. In the above reaction, one curved arrow is drawn from the lone pair on H to the H of the first reactant, so it illustrates the formation of a new H-H bond in the second reactant. The tail of the second arrow originates from the center of the S-H bond, so it illustrates the breaking of that bond, and it points to the S atom, showing that those electrons end up as a lone pair on S of the first reactant. Therefore, for the given proton transfer reaction, the products are as drawn below:

EBK GET READY FOR ORGANIC CHEMISTRY, Chapter 6, Problem 6.38P , additional homework tip 10

Conclusion

The products of the given proton transfer reaction are drawn on the basis of the curved arrow notation that shows breaking and formation of bonds.

Answer 15

Interpretation Introduction

(b)

Interpretation:

Appropriate products are to be drawn for the given proton transfer reaction with curved arrow notation.

Concept introduction:

In a proton transfer reaction, a proton is transferred from a Bronsted-Lowry acid to a Bronsted-Lowry base in a single elementary step in which one bond is broken and another is formed simultaneously. The curved arrow notation shows the movement of valence electrons, not atoms. The movement of two valence electrons is shown by curved arrow. To represent bond breaking, the tail of the arrow originates from the center of a bond whereas to represent bond formation, the head of arrow points to an atom which forms the new bond, that is, bond or the region where the bond is formed if the new bond is a bond. The conjugate acid is the species that the base becomes after gaining a proton, and the conjugate base is the species that the acid becomes after losing a proton.

Answer 16

Expert Solution

Answer to Problem 6.38P

For the given proton transfer reaction the products are drawn as below.

EBK GET READY FOR ORGANIC CHEMISTRY, Chapter 6, Problem 6.38P , additional homework tip 8

Answer 17

Expert Solution

Answer 18

Expert Solution

Answer 19

Expert Solution

Answer 20

Explanation of Solution

The curved arrow notation for the given proton transfer reaction is shown below:

EBK GET READY FOR ORGANIC CHEMISTRY, Chapter 6, Problem 6.38P , additional homework tip 9

In a proton transfer reaction, a proton is transferred from the Bronsted-Lowry acid to the Bronsted-Lowry base. The movement of two valence electrons is shown by curved arrow. The head of the arrow pointing to atom shows the transfer of valence electrons to form a new single bond. In the above reaction, one curved arrow is drawn from the lone pair on H to the H of the first reactant, so it illustrates the formation of a new H-H bond in the second reactant. The tail of the second arrow originates from the center of the S-H bond, so it illustrates the breaking of that bond, and it points to the S atom, showing that those electrons end up as a lone pair on S of the first reactant. Therefore, for the given proton transfer reaction, the products are as drawn below:

EBK GET READY FOR ORGANIC CHEMISTRY, Chapter 6, Problem 6.38P , additional homework tip 10

Answer 21

Conclusion

The products of the given proton transfer reaction are drawn on the basis of the curved arrow notation that shows breaking and formation of bonds.

Answer 22

Interpretation Introduction

(c)

Interpretation:

Appropriate products are to be drawn for the given proton transfer reaction with curved arrow notation.

Concept introduction:

In a proton transfer reaction, a proton is transferred from a Bronsted-Lowry acid to a Bronsted-Lowry base in a single elementary step in which one bond is broken and another is formed simultaneously. The curved arrow notation shows the movement of valence electrons, not atoms. The movement of two valence electrons is shown by curved arrow. To represent bond breaking, the tail of the arrow originates from the center of a bond whereas to represent bond formation, the head of arrow points to an atom which forms the new bond, that is, bond or the region where the bond is formed if the new bond is a bond. The conjugate acid is the species that the base becomes after gaining a proton, and the conjugate base is the species that the acid becomes after losing a proton.

Expert Solution

Answer to Problem 6.38P

For the given proton transfer reaction, the products are drawn as below.

EBK GET READY FOR ORGANIC CHEMISTRY, Chapter 6, Problem 6.38P , additional homework tip 13

Explanation of Solution

The curved arrow notation for the given proton transfer reaction is shown below:

EBK GET READY FOR ORGANIC CHEMISTRY, Chapter 6, Problem 6.38P , additional homework tip 14

In a proton transfer reaction, a proton is transferred from the Bronsted-Lowry acid to the Bronsted-Lowry base. The movement of two valence electrons is shown by curved arrow. The head of the arrow pointing to an atom shows the transfer of valence electrons to form a new single bond. In the above reaction, one curved arrow is drawn from the lone pair on N to the H of the second reactant, so it illustrates the formation of a new N-H bond in the first reactant. The tail of the second arrow originates from the center of the O-H bond, so it illustrates the breaking of that bond, and it points to the O atom, showing that those electrons end up as a lone pair on the O of the second reactant. Therefore, for the given proton transfer reaction, the products are as drawn below:

EBK GET READY FOR ORGANIC CHEMISTRY, Chapter 6, Problem 6.38P , additional homework tip 15

Conclusion

The products of the given proton transfer reaction are drawn on the basis of the curved arrow notation that shows breaking and formation of bonds.

Answer 23

Interpretation Introduction

(c)

Interpretation:

Appropriate products are to be drawn for the given proton transfer reaction with curved arrow notation.

Concept introduction:

In a proton transfer reaction, a proton is transferred from a Bronsted-Lowry acid to a Bronsted-Lowry base in a single elementary step in which one bond is broken and another is formed simultaneously. The curved arrow notation shows the movement of valence electrons, not atoms. The movement of two valence electrons is shown by curved arrow. To represent bond breaking, the tail of the arrow originates from the center of a bond whereas to represent bond formation, the head of arrow points to an atom which forms the new bond, that is, bond or the region where the bond is formed if the new bond is a bond. The conjugate acid is the species that the base becomes after gaining a proton, and the conjugate base is the species that the acid becomes after losing a proton.

Answer 24

Expert Solution

Answer to Problem 6.38P

For the given proton transfer reaction, the products are drawn as below.

EBK GET READY FOR ORGANIC CHEMISTRY, Chapter 6, Problem 6.38P , additional homework tip 13

Answer 25

Expert Solution

Answer 26

Expert Solution

Answer 27

Expert Solution

Answer 28

Explanation of Solution

The curved arrow notation for the given proton transfer reaction is shown below:

EBK GET READY FOR ORGANIC CHEMISTRY, Chapter 6, Problem 6.38P , additional homework tip 14

In a proton transfer reaction, a proton is transferred from the Bronsted-Lowry acid to the Bronsted-Lowry base. The movement of two valence electrons is shown by curved arrow. The head of the arrow pointing to an atom shows the transfer of valence electrons to form a new single bond. In the above reaction, one curved arrow is drawn from the lone pair on N to the H of the second reactant, so it illustrates the formation of a new N-H bond in the first reactant. The tail of the second arrow originates from the center of the O-H bond, so it illustrates the breaking of that bond, and it points to the O atom, showing that those electrons end up as a lone pair on the O of the second reactant. Therefore, for the given proton transfer reaction, the products are as drawn below:

EBK GET READY FOR ORGANIC CHEMISTRY, Chapter 6, Problem 6.38P , additional homework tip 15

Answer 29

Conclusion

The products of the given proton transfer reaction are drawn on the basis of the curved arrow notation that shows breaking and formation of bonds.

Answer 30

Interpretation Introduction

(d)

Interpretation:

Appropriate products are to be drawn for the given proton transfer reaction with curved arrow notation.

Concept introduction:

In a proton transfer reaction, a proton is transferred from a Bronsted-Lowry acid to a Bronsted-Lowry base in a single elementary step in which one bond is broken and another is formed simultaneously. The curved arrow notation shows the movement of valence electrons, not atoms. The movement of two valence electrons is shown by curved arrow. To represent bond breaking, the tail of the arrow originates from the center of a bond whereas to represent bond formation, the head of arrow points to an atom which forms the new bond, that is, bond or the region where the bond is formed if the new bond is a bond. The conjugate acid is the species that the base becomes after gaining a proton, and the conjugate base is the species that the acid becomes after losing a proton.

Expert Solution

Answer to Problem 6.38P

For the given proton transfer reaction, the products are drawn as below.

EBK GET READY FOR ORGANIC CHEMISTRY, Chapter 6, Problem 6.38P , additional homework tip 18

Explanation of Solution

The curved arrow notation for the given proton transfer reaction are shown below:

EBK GET READY FOR ORGANIC CHEMISTRY, Chapter 6, Problem 6.38P , additional homework tip 19

In a proton transfer reaction, a proton is transferred from the Bronsted-Lowry acid to the Bronsted-Lowry base. The movement of two valence electrons is shown by curved arrow. The head of the arrow pointing to an atom shows the transfer of valence electrons to form a new single bond. In the above reaction, one curved arrow is drawn from the lone pair on O to the H of the first reactant, so it illustrates the formation of a new O-H bond in the second reactant. The tail of the second arrow originates from the center of the O-H bond, so it illustratea the breaking of that bond, and it points to the O atom, showing that those electrons end up as a lone pair on the O of the first reactant. Therefore, For the given proton transfer reaction, the products are drawn as below:

EBK GET READY FOR ORGANIC CHEMISTRY, Chapter 6, Problem 6.38P , additional homework tip 20

Conclusion

The products of the given proton transfer reaction are drawn on the basis of the curved arrow notation that shows breaking and formation of bonds.

Answer 31

Interpretation Introduction

(d)

Interpretation:

Appropriate products are to be drawn for the given proton transfer reaction with curved arrow notation.

Concept introduction:

In a proton transfer reaction, a proton is transferred from a Bronsted-Lowry acid to a Bronsted-Lowry base in a single elementary step in which one bond is broken and another is formed simultaneously. The curved arrow notation shows the movement of valence electrons, not atoms. The movement of two valence electrons is shown by curved arrow. To represent bond breaking, the tail of the arrow originates from the center of a bond whereas to represent bond formation, the head of arrow points to an atom which forms the new bond, that is, bond or the region where the bond is formed if the new bond is a bond. The conjugate acid is the species that the base becomes after gaining a proton, and the conjugate base is the species that the acid becomes after losing a proton.

Answer 32

Expert Solution

Answer to Problem 6.38P

For the given proton transfer reaction, the products are drawn as below.

EBK GET READY FOR ORGANIC CHEMISTRY, Chapter 6, Problem 6.38P , additional homework tip 18

Answer 33

Expert Solution

Answer 34

Expert Solution

Answer 35

Expert Solution

Answer 36

Explanation of Solution

The curved arrow notation for the given proton transfer reaction are shown below:

EBK GET READY FOR ORGANIC CHEMISTRY, Chapter 6, Problem 6.38P , additional homework tip 19

In a proton transfer reaction, a proton is transferred from the Bronsted-Lowry acid to the Bronsted-Lowry base. The movement of two valence electrons is shown by curved arrow. The head of the arrow pointing to an atom shows the transfer of valence electrons to form a new single bond. In the above reaction, one curved arrow is drawn from the lone pair on O to the H of the first reactant, so it illustrates the formation of a new O-H bond in the second reactant. The tail of the second arrow originates from the center of the O-H bond, so it illustratea the breaking of that bond, and it points to the O atom, showing that those electrons end up as a lone pair on the O of the first reactant. Therefore, For the given proton transfer reaction, the products are drawn as below:

EBK GET READY FOR ORGANIC CHEMISTRY, Chapter 6, Problem 6.38P , additional homework tip 20