Principles of General, Organic, Biological Chemistry
Principles of General, Organic, Biological Chemistry
2nd Edition
ISBN: 9780073511191
Author: Janice Gorzynski Smith Dr.
Publisher: McGraw-Hill Education
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Chapter 6, Problem 6.33UKC

(a)

Interpretation Introduction

Interpretation:

The picture has to be drawn to represent the change that the balloon is inflated outside on a cold winter day and then taken into a building at 75K.

Concept Introduction:

Charles Law:

At constant pressure, the temperature and the volume of the gas are proportionally related.

  VT=K

Where V is the volume of the gas.

T is the temperature of the gas in Kelvin.

K is the constant.

(b)

Interpretation Introduction

Interpretation:

The picture has to be drawn to represent the change that the balloon is taken to the top of Mauna Kea at constant temperature.

Concept Introduction:

Avogadro’s Law:

At constant pressure and temperature, the number of moles in the gas and the volume of the gas are related proportionally.

  Vn=K

Where V is the volume of the gas.

n is the number of moles.

K is the constant.

(c)

Interpretation Introduction

Interpretation:

The picture has to be drawn to represent the change that the balloon is taken inside an airplane pressurized at 0.8atm.

Concept Introduction:

Boyle’s Law:

At constant temperature, the pressure and the volume of the gas are inversely related.

  PV=K

Where P is pressure of the gas at constant temperature.

V is volume of the gas at constant temperature.

K is the constant.

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142. A mixture of H2(g) and N2(g) has a density of 0.216 g/liter at 300 K and 500 torr. What is the mole fraction composition of the mixture?
One liter of N2(g) at 2.1 bar and two liters of Ar(g) at 3.4 bar are mixed in a 4.0 liter flask to form an ideal gas mixture.  Calculate the value of the final pressure of the mixture if the initial and final temperature of the gases are the same.  Repeat this calculation if the initial temperature of the N2(g) and Ar(g) are 304 K and 402 K, respectively, and the final temperature of the mixture is 377 K.

Chapter 6 Solutions

Principles of General, Organic, Biological Chemistry

Ch. 6.4 - Prob. 6.11PCh. 6.5 - Prob. 6.12PCh. 6.6 - Prob. 6.13PCh. 6.6 - Prob. 6.14PCh. 6.6 - Prob. 6.15PCh. 6.6 - Prob. 6.16PCh. 6.7 - Prob. 6.17PCh. 6.7 - Prob. 6.18PCh. 6.7 - Prob. 6.19PCh. 6.8 - Prob. 6.20PCh. 6.8 - Prob. 6.21PCh. 6.8 - Prob. 6.22PCh. 6.9 - Prob. 6.25PCh. 6.9 - Prob. 6.26PCh. 6 - Prob. 6.27UKCCh. 6 - Prob. 6.28UKCCh. 6 - Prob. 6.29UKCCh. 6 - Prob. 6.30UKCCh. 6 - Prob. 6.31UKCCh. 6 - Prob. 6.32UKCCh. 6 - Prob. 6.33UKCCh. 6 - Prob. 6.34UKCCh. 6 - Prob. 6.35UKCCh. 6 - Prob. 6.36UKCCh. 6 - Prob. 6.37UKCCh. 6 - Prob. 6.38UKCCh. 6 - Prob. 6.39UKCCh. 6 - Prob. 6.40UKCCh. 6 - Prob. 6.41APCh. 6 - The lowest atmospheric pressure ever measured is...Ch. 6 - Prob. 6.43APCh. 6 - Prob. 6.44APCh. 6 - Prob. 6.45APCh. 6 - Prob. 6.46APCh. 6 - Prob. 6.47APCh. 6 - Prob. 6.48APCh. 6 - Prob. 6.49APCh. 6 - Prob. 6.50APCh. 6 - Prob. 6.51APCh. 6 - Prob. 6.52APCh. 6 - Prob. 6.53APCh. 6 - Prob. 6.54APCh. 6 - Prob. 6.55APCh. 6 - Prob. 6.56APCh. 6 - Prob. 6.57APCh. 6 - Prob. 6.58APCh. 6 - Prob. 6.59APCh. 6 - Prob. 6.60APCh. 6 - Prob. 6.61APCh. 6 - Prob. 6.62APCh. 6 - Prob. 6.63APCh. 6 - Prob. 6.64APCh. 6 - Prob. 6.65APCh. 6 - Prob. 6.66APCh. 6 - Prob. 6.67APCh. 6 - Prob. 6.68APCh. 6 - Prob. 6.69APCh. 6 - Prob. 6.70APCh. 6 - Prob. 6.71APCh. 6 - Prob. 6.72APCh. 6 - Prob. 6.73APCh. 6 - Prob. 6.74APCh. 6 - Prob. 6.75APCh. 6 - Prob. 6.77APCh. 6 - Prob. 6.79APCh. 6 - Prob. 6.81APCh. 6 - Prob. 6.82APCh. 6 - Prob. 6.83APCh. 6 - Prob. 6.84APCh. 6 - Prob. 6.85APCh. 6 - Prob. 6.86APCh. 6 - Prob. 6.87APCh. 6 - Prob. 6.88APCh. 6 - Prob. 6.89CP
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