Chapter 6, Problem 6.31P

Interpretation Introduction

Interpretation:

If in a rigid vessel of given volume, saturated water vapor and liquid water is filled at $\text{101}\text{.325}\text{kPa}$ .Find out amount of heat added to vessel for just evaporation of liquid water.

Concept Introduction:

During the heat transferred in the process, total mass and volume remains constant. So, the total volume after the heat addedis same as total volume at $\text{101}\text{.325}\text{kPa}$ . So, find the total volume and mass at $\text{101}\text{.325}\text{kPa}$ using the saturated steam table and use them to find pressure after the heat added.

The heat transferred in the process is defined as:

$Q=m(U_2-U_1)$

                    .... (a)

Where $m$ is the mass of steam, $U_2$ is the internal energy after heat transferred and $U_1$ is the internal energy before heat transferred.