
Concept explainers
a.
To determine:
Raffinose, a soluble fiber containing three carbohydrate units is classified as a monosaccharide, disaccharide, oligosaccharide or polysaccharide
Introduction:
Carbohydrates are used by body in two forms- simpler form or in the complex form. The simplest forms of carbohydrates are monosaccharides. The form of carbohydrates which are composed of two monosaccharide units are known as disaccharides. Oligosaccharides are the carbohydrates which consists of three to nine monosaccharides units. When more than 10 monomer units of monosaccharides combine, they form a large molecule known as polysaccharide.
b.
To determine:
Starch, a storage carbohydrate of plants that contains thousands of glucose units is classified as a monosaccharide, disaccharide, oligosaccharide or polysaccharide.
Introduction:
Carbohydrates are used by body in two forms- simpler form or in the complex form. The simplest forms of carbohydrates are monosaccharides. The form of carbohydrates which are composed of two monosaccharide units are known as disaccharides. Oligosaccharides are the carbohydrates which consists of three to nine monosaccharides units. When more than 10 monomer units of monosaccharides combine, they form a large molecule known as polysaccharide.
c.
To determine:
Fructose is a simple sugar found in fruit with the formula C6H12O6 is classified as a monosaccharide, disaccharide, oligosaccharide or polysaccharide
Introduction:
Carbohydrates are used by body in two forms- simpler form or in the complex form. The simplest forms of carbohydrates are monosaccharides. The form of carbohydrates which are composed of two monosaccharide units are known as disaccharides. Oligosaccharides are the carbohydrates which consists of three to nine monosaccharides units. When more than 10 monomer units of monosaccharides combine, they form a large molecule known as polysaccharide.

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Chapter 6 Solutions
GENERAL ORGANIC+BIO...(LL)-W/MOD.ACCESS
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- In one electrode: Pt, H2(1 atm) | H+(a=1), the interchange current density at 298K is 0.79 mA·cm-2. If the voltage difference of the interface is +5 mV. What will be the correct intensity at pH = 2?. Maximum transfer voltage and beta = 0.5.arrow_forwardIn a Pt electrode, H2(1 atm) | H+(a=1), the interchange current density of an electrode is 0.79 mA cm-2. ¿Qué corriente flow across the electrode of área 5 cm2 when the difference in potential of the interface is +5 mV?.arrow_forwardIf the current voltage is n = 0.14 V, indicate which of the 2 voltage formulas of the ley of Tafel must be applied i a a) == exp (1-B). xp[(1 - ß³): Fn Fn a b) == exp B RT RTarrow_forward
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- With the help of the Tafel line, it is estimated that the interchange density of the VO2+/VO2+ system on the carbon paper has a value of 3 mA cm-2. Calculate a) the current density if the voltage has a value of 1.6 mV and the temperature is 25°C. b) the beta value of the anódico process if the Tafel pendulum is 0.6 V at 25°C. Data: R = 8.314 JK-1mol-1, y F = 96485 C mol-1.arrow_forwardApply the NANSTE law to the MnO4- + 8H+ + 5e- ⇄ Mn2+ + 4H2Oarrow_forwardIn the Nernst Law, how much is RT / F?arrow_forward
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