Look-ahead information can be used to automatically steer a bicycle in a closed-loop configuration. A line is drawn in the middle of the lane to be followed, and an arbitrary point is chosen in the vehicle’s longitudinal axis. A look-ahead offset is calculated by measuring the distance between the look-ahead point and the reference line and is used by the system to correct the vehicle’s trajectory. A linearized model of a particular bicycle traveling on a straight-line path at a fixed longitudinal speed is
In this model, V = bicycle’s lateral velocity, r = bicycle’s yaw velocity,

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Chapter 6 Solutions
CONTROL SYSTEMS ENGINEERING - WILEYPLUS
- Correct answer and complete fbd only. I will upvote. The compound shaft, consisting of steel and aluminumsegments, carries the two torques shown in the figure. Determine themaximum permissible value of T subject to the following designconditions: τst ≤ 83 MPa, τal ≤ 55 MPa, and θ ≤ 6⁰ (θ is the angle ofrotation of the free end). Use G =83 GPa for steel and G = 28 GPa foraluminum.arrow_forwardThe solid compound shaft, made of threedifferent materials, carries the two torques shown. Theshear moduli are 28 GPa for aluminum, 83 GPa for steel,and 35 GPa for bronze.1. Calculate the maximum shear stress (MPa) in eachmaterial.2. Find the angle of rotation (degrees) of the free endof the shaft.arrow_forwardCorrect answer only please. I will upvote. The velocity of a particle moves along the x-axis and is given by the equation ds/dt = 40 - 3t^2 m/s. Calculate the acceleration at time t=2 s and t=4 s. Calculate also the total displacement at the given interval. Assume at t=0 s=5m.Write the solution using pen and draw the graph if needed.arrow_forward
- I want the steps of operation of the circuit, clearly in detail. Please. LV1arrow_forwardComplet the solution: Vavg Ti Te Ts Qhexp Nuexp htheo Re Nutheo Error (m/s) (°C) (°C) (°C) (W) 2.11 18.8 21.3 45.8 2.61 18.5 20.8 46.3 Heat transfer Given data: a= 10 cm. L= 10 cm. b= 20 cm. H=40cm. ⚫ a = 10, cm: This could represent the width of the duct. ⚫b=20, cm: This might be the height of the duct. ⚫L = 10, cm: This usually stands for the length of the duct in the direction of flow. ⚫H=40, cm: This could indicate the height of some component or another duct-related dimension, but the exact meaning depends on the experiment's context.arrow_forwardplease explain each step and include drawings on the phase diagram. thanksarrow_forward
- Write clearly which points correspond to concentration of solute in front of alpha, concentration of solute in front of beta, amount of solid in the liquid in front of alpha/beta, lowest possible energy (tangent), as well as any other important information. Thank youarrow_forwardQ3: A 4-stroke 6 litres engine is fuelled with methane (CH4) at an air-fuel ratio = 0.8. It operates at 2000 rpm with a volumetric efficiency of 80%. The exhaust (product) leaves the engine at 800 K, and the heat lost to the coolant is 3.4×105 kJ/kmol. What is the engine's output power? Assume both air and fuel (methane) inlet to the engine at 298 K. Take for methane, the molecular weight is M = 16 kg/kmol, and the heat of combustion is 50.01 MJ/kg. The ambient conditions (p = 101 kPa, T = 25 °C). (24 points)arrow_forwardTemperature (°C) 100 4. Consider the solidification of a binary Pb-10%Sn alloy. Assume that during solidification, there is complete mixing in the liquid and no diffusion in the solid. Use the phase diagram below to answer the following question. (a) Draw (on the phase diagram) the compositions of the liquid and the solid at the interface as a function of temperature during solidification. (b) Illustrate on the phase diagram how one would calculate the volume fraction solidified at a given temperature. (c) (d) Indicate the temperature at which solidification is complete. Do you expect ẞ to be present in the as-cast microstructure? Explain 300 327°C 200 a (Pb) 20 20 a + L 18.3 183°C α + β 40 60 Composition (wt% Sn) Liquid 600 500 232°C B+L 400 B 61.9 97.8 300 808 100 (Sn) 200 100 Temperature (°F)arrow_forward
- I tried this problem a couple of times and don't know where I'm going wrong can you help me out pleasearrow_forwardy(0)=1, Using Laplace transforms solve the following differential equations : 11) y"-4y+4y=0, 12) y+2y+2y=0, y(0)=2.1, y'(0) = 3.9 y'(0)=-3. 13) y+7y+12y=21e", y(0)=3.5, y'(0)=-10. 14) +9y=10e. y(0)=0, y'(0) = 0. 15) y+3y+2.25y=91³ +64, y(0)=1, y'(0) = 31.5 16) -6y+5y= 29 cos(21), y(0)=3.2, y'(0)=6.2 17) "+2y+2y=0, y(0)=0, y'(0)=1. 18) +2y+17y=0, y(0)=0, y'(0)=12. 19) y-4y+5y=0, y(0)=1, y'(0) = 2. 20) 9y-6y+y=0, y(0)=3, y'(0)=1. 21) -2y+10y=0, y(0)=3, y'(0)=3.arrow_forward4. Consider the rectangulan 2535 Let 16 a and section discussed 977b + class. in ie make a M thin" rectangle, Can you you show that Q = Go {a² = x² } . Imax = 2 Ga ты J =arrow_forward
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