Chapter 6, Problem 6.15QP

(a)

Interpretation Introduction

Interpretation:

The work done in joules if the gas expands against vacuum has to be calculated.

Concept Introduction:

At constant pressure, the exchange of heat between the system and surroundings is called as Enthalpy and its state function.

Enthalpy can be given by the formula,

$\text{H=U+PV}$

Where, H=enthalpy

U=internal energy

P=Pressure

V=Volume

The work done on the system or by the system can be calculated from the equation

$\text{w=-PΔV}$

Where w=work done

P=Pressure

V=Change in volume

(b)

Interpretation Introduction

Interpretation:

The work done in joules if the gas expands against constant pressure has to be calculated.

Concept Introduction:

At constant pressure, the exchange of heat between the system and surroundings is called as Enthalpy and its state function.

Enthalpy can be given by the formula,

$\text{H=U+PV}$

Where, H=enthalpy

U=internal energy

P=Pressure

V=Volume

The work done on the system or by the system can be calculated from the equation

$\text{w=-PΔV}$

Where w=work done

P=Pressure

V=Change in volume

(c)

Interpretation Introduction

Interpretation:

The work done in joules if the gas expands against constant pressure has to be calculated.

Concept Introduction:

At constant pressure, the exchange of heat between the system and surroundings is called as Enthalpy and its state function.

Enthalpy can be given by the formula,

$\text{H=U+PV}$

Where, H=enthalpy

U=internal energy

P=Pressure

V=Volume

The work done on the system or by the system can be calculated from the equation

$\text{w=-PΔV}$

Where w=work done

P=Pressure

V=Change in volume