Chapter 6, Problem 6.155AP

(a)

Interpretation Introduction

Interpretation: The typical blood pressure in a resting body is given to be $"120\text{over}80"$. The conversion of this pressure value in the given units is to be stated.

Concept introduction: The relationship between units of pressure atm and mm Hg is,

$1\text{atm}=760\text{mm}\text{Hg}$

The relationship between units of pressure bar and mm Hg is,

$1.013\text{bar}=760\text{mm}\text{Hg}$

The relationship between units of pressure kPa and mm Hg is,

$101.325\text{kPa}=760\text{mm}\text{Hg}$

To determine: The conversion of the given pressure value in the torr units.

Answer to Problem 6.155AP

Solution

The value of given pressure in torr is same as that in mm Hg that is $\underset{\_}{120torr}\text{and}\underset{\_}{80torr}$.

Explanation of Solution

Explanation

The value of pressure expressed in torr is same as that in mm Hg.

Hence,

$\begin{array}{c}120\text{mm}\text{Hg}=\underset{\_}{120torr}\\ 80\text{mm}\text{Hg}=\underset{\_}{80torr}\end{array}$

Therefore, the pressure value in torr unit is $\underset{\_}{120torr}\text{and}\underset{\_}{80torr}$.

(b)

Interpretation Introduction

To determine: The conversion of the given pressure value in the atm units.

Answer to Problem 6.155AP

Solution

The pressure value in atm unit is $\underset{\_}{0.157atm}\text{and}\underset{\_}{0.105atm}$.

Explanation of Solution

Explanation

The relationship between units of pressure atm and mm Hg is,

$\begin{array}{c}1\text{atm}=760\text{mm}\text{Hg}\\ \text{1}\text{mm}\text{Hg}=\left(\frac{1}{760}\right)\text{atm}\end{array}$

The conversion of pressure from $\text{mm}\text{Hg}\text{to}\text{atm}$,

$\begin{array}{c}120\text{mm}\text{Hg}=\text{120}\text{mm}\text{Hg}\times \frac{1\text{atm}}{760\text{mm}\text{Hg}}\\ =\underset{\_}{0.157atm}\\ 80\text{mm}\text{Hg}=80\text{mm}\text{Hg}\times \frac{1\text{atm}}{760\text{mm}\text{Hg}}\\ =\underset{\_}{0.105atm}\end{array}$

Therefore, the pressure values in atm units is $\underset{\_}{0.157atm}\text{and}\underset{\_}{0.105atm}$.

(c)

Interpretation Introduction

To determine: The conversion of the given pressure value in the atm units.

Answer to Problem 6.155AP

Solution

The pressure value in bar unit is $\underset{\_}{0.160bar}\text{and}\underset{\_}{0.107bar}$.

Explanation of Solution

Explanation

The relationship between units of pressure bar and mm Hg is,

$\begin{array}{c}1.013\text{bar}=760\text{mm}\text{Hg}\\ \text{1}\text{mm}\text{Hg}=\left(\frac{1.013}{760}\right)\text{bar}\end{array}$

The conversion of pressure from $\text{mm}\text{Hg}\text{to}\text{bar}$,

$\begin{array}{c}120\text{mm}\text{Hg}=\text{120}\text{mm}\text{Hg}\times \frac{1.013\text{bar}}{760\text{mm}\text{Hg}}\\ =\underset{\_}{0.1599bar}\\ \approx \underset{\_}{0.160bar}\\ 80\text{mm}\text{Hg}=80\text{mm}\text{Hg}\times \frac{1.013\text{bar}}{760\text{mm}\text{Hg}}\\ =\underset{\_}{0.107bar}\end{array}$

Therefore, the pressure values in bar units is $\underset{\_}{0.160bar}\text{and}\underset{\_}{0.107bar}$.

(d)

Interpretation Introduction

To determine: The conversion of the given pressure value in the kPa units.

Answer to Problem 6.155AP

Solution

The pressure value in kPa unit is $\underset{\_}{15.9kPa}\text{and}\underset{\_}{10.7kPa}$.

Explanation of Solution

Explanation

The relationship between units of pressure kPa and mm Hg is,

$\begin{array}{c}101.325\text{kPa}=760\text{mm}\text{Hg}\\ \text{1}\text{mm}\text{Hg=}\left(\frac{101.325}{760}\right)\text{kPa}\end{array}$

Therefore, the conversion of the given pressure values from $\text{mm}\text{Hg}\text{to}\text{kPa}$ is,

$\begin{array}{c}120\text{mm}\text{Hg}=\text{120}\text{mm}\text{Hg}\times \frac{101.325\text{kPa}}{760\text{mm}\text{Hg}}\\ =\underset{\_}{15.99kPa}\\ 80\text{mm}\text{Hg}=80\text{mm}\text{Hg}\times \frac{101.325\text{kPa}}{760\text{mm}\text{Hg}}\\ =\underset{\_}{10.7kPa}\end{array}$

Therefore, the pressure values in kPa units are. $\underset{\_}{15.9kPa}\text{and}\underset{\_}{10.7kPa}$.

Conclusion

1. a) The value of given pressure in torr is same as that in mm Hg that is $\underset{\_}{120torr}\text{and}\underset{\_}{80torr}$.
2. b) The pressure value in atm unit is $\underset{\_}{0.157atm}\text{and}\underset{\_}{0.105atm}$.
3. c) The pressure value in bar unit is $\underset{\_}{0.160bar}\text{and}\underset{\_}{0.107bar}$.
4. d) The pressure value in kPa unit is $\underset{\_}{15.9kPa}\text{and}\underset{\_}{10.7kPa}$