COLLEGE PHYSICS
COLLEGE PHYSICS
2nd Edition
ISBN: 9781464196393
Author: Freedman
Publisher: MAC HIGHER
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Chapter 6, Problem 55QAP
To determine

The Fmax in terms of m and v with the help of graph.

Expert Solution & Answer
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Answer to Problem 55QAP

  Fmax=138.27 N

Explanation of Solution

Given info:

  Final velocity = vMass of sled = 22.0 kg

Formula used:

  F=maF=Forcea=accelerationm=mass

  v2=u2+2asv=Final velocityu=initial velocitya=accelerations=distance

Calculation:

COLLEGE PHYSICS, Chapter 6, Problem 55QAP

  Fmax=3f

  From x=0 to x=30F=maFmax=22.0 kg*aa=F max22

  v2=u2+2asv30= velocity at x=30v302=0+2*F max22*30 mv30= 60 F max 22

  From x=30 to x=55Acceleration = a30-55Force = Favg(30-55)Consider, Fmax=3 xForce at x=55 = F55 = -x

  Favg(30-55)= F 55 F max2=f3f2=fFavg(30-55) in turms of Fmax, Fmax=3 f F max3=fFavg(30-55)=xFavg(30-55)=F max3F=maFavg(30-55)=22.0 kg*aavg(30-55)Favg(30-55)=F max3F max3=22.0 kg*aavg(30-55)a=F max22*3

  For this point, u= 60 F max 22v2=u2+2asv55= velocity at x=55v552=60F max22+2*(F max22*3)*25 mv552=60F max2250F max22*3

  From x=55 to x=90F5590=Force from x=55 to x=90=-fa5590=acceleration from x=55 to x=90F5590 in turms of Fmax,F max3=fF5590=F max3F=maF max3=22.0 kg*aa5590=F max22*3

  For this point, u2=60F max2250F max22*3v2=u2+2asv90= velocity at x=90v552=60F max2250F max22*3+2*(F max22*3)*35 mv552=60F max2250F max22*370F max22*3

  From x=90 to x=100Acceleration = a90-100Force = Favg(90-100)Favg(90-100)=0(f)2=0.5fF max3=fFavg(90-100)=F max6F=maFavg(90-100)=22.0 kg*a90-100Favg(90-100)=F max6F max6=22.0 kg*a90-100a=F max22*6

  For this point, u2=60F max2250F max22*370F max22*3v2=u2+2asv100= velocity at x=100=12.5 ms-1v1002=60F max2250F max22*370F max22*3+2*F max22*6*10 mv1002=60F max2250F max22*370F max22*3+20F max22*6=(12.5 ms-1)260F max2250F max22*370F max22*3+20F max22*6=(12.5 ms-1)2156.25=2.73Fmax0.75Fmax1.00Fmax+0.15Fmax1.13Fmax=156.25Fmax=138.27 N

Conclusion:

  Fmax=138.27 N

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Chapter 6 Solutions

COLLEGE PHYSICS

Ch. 6 - Prob. 11QAPCh. 6 - Prob. 12QAPCh. 6 - Prob. 13QAPCh. 6 - Prob. 14QAPCh. 6 - Prob. 15QAPCh. 6 - Prob. 16QAPCh. 6 - Prob. 17QAPCh. 6 - Prob. 18QAPCh. 6 - Prob. 19QAPCh. 6 - Prob. 20QAPCh. 6 - Prob. 21QAPCh. 6 - Prob. 22QAPCh. 6 - Prob. 23QAPCh. 6 - Prob. 24QAPCh. 6 - Prob. 25QAPCh. 6 - Prob. 26QAPCh. 6 - Prob. 27QAPCh. 6 - Prob. 28QAPCh. 6 - Prob. 29QAPCh. 6 - Prob. 30QAPCh. 6 - Prob. 31QAPCh. 6 - Prob. 32QAPCh. 6 - Prob. 33QAPCh. 6 - Prob. 34QAPCh. 6 - Prob. 35QAPCh. 6 - Prob. 36QAPCh. 6 - Prob. 37QAPCh. 6 - Prob. 38QAPCh. 6 - Prob. 39QAPCh. 6 - Prob. 40QAPCh. 6 - Prob. 41QAPCh. 6 - Prob. 42QAPCh. 6 - Prob. 43QAPCh. 6 - Prob. 44QAPCh. 6 - Prob. 45QAPCh. 6 - Prob. 46QAPCh. 6 - Prob. 47QAPCh. 6 - Prob. 48QAPCh. 6 - Prob. 49QAPCh. 6 - Prob. 50QAPCh. 6 - Prob. 51QAPCh. 6 - Prob. 52QAPCh. 6 - Prob. 53QAPCh. 6 - Prob. 54QAPCh. 6 - Prob. 55QAPCh. 6 - Prob. 56QAPCh. 6 - Prob. 57QAPCh. 6 - Prob. 58QAPCh. 6 - Prob. 59QAPCh. 6 - Prob. 60QAPCh. 6 - Prob. 61QAPCh. 6 - Prob. 62QAPCh. 6 - Prob. 63QAPCh. 6 - Prob. 64QAPCh. 6 - Prob. 65QAPCh. 6 - Prob. 66QAPCh. 6 - Prob. 67QAPCh. 6 - Prob. 68QAPCh. 6 - Prob. 69QAPCh. 6 - Prob. 70QAPCh. 6 - Prob. 71QAPCh. 6 - Prob. 72QAPCh. 6 - Prob. 73QAPCh. 6 - Prob. 74QAPCh. 6 - Prob. 75QAPCh. 6 - Prob. 76QAPCh. 6 - Prob. 77QAPCh. 6 - Prob. 78QAPCh. 6 - Prob. 79QAPCh. 6 - Prob. 80QAPCh. 6 - Prob. 81QAPCh. 6 - Prob. 82QAPCh. 6 - Prob. 83QAPCh. 6 - Prob. 84QAPCh. 6 - Prob. 85QAPCh. 6 - Prob. 86QAPCh. 6 - Prob. 87QAPCh. 6 - Prob. 88QAPCh. 6 - Prob. 89QAPCh. 6 - Prob. 90QAPCh. 6 - Prob. 91QAPCh. 6 - Prob. 92QAPCh. 6 - Prob. 93QAPCh. 6 - Prob. 94QAPCh. 6 - Prob. 95QAPCh. 6 - Prob. 96QAPCh. 6 - Prob. 97QAPCh. 6 - Prob. 98QAPCh. 6 - Prob. 99QAPCh. 6 - Prob. 100QAPCh. 6 - Prob. 101QAPCh. 6 - Prob. 102QAPCh. 6 - Prob. 103QAPCh. 6 - Prob. 104QAPCh. 6 - Prob. 105QAPCh. 6 - Prob. 106QAPCh. 6 - Prob. 107QAP
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