COLLEGE PHYSICS
COLLEGE PHYSICS
2nd Edition
ISBN: 9781464196393
Author: Freedman
Publisher: MAC HIGHER
bartleby

Concept explainers

bartleby

Videos

Question
Book Icon
Chapter 6, Problem 55QAP
To determine

The Fmax in terms of m and v with the help of graph.

Expert Solution & Answer
Check Mark

Answer to Problem 55QAP

  Fmax=138.27 N

Explanation of Solution

Given info:

  Final velocity = vMass of sled = 22.0 kg

Formula used:

  F=maF=Forcea=accelerationm=mass

  v2=u2+2asv=Final velocityu=initial velocitya=accelerations=distance

Calculation:

COLLEGE PHYSICS, Chapter 6, Problem 55QAP

  Fmax=3f

  From x=0 to x=30F=maFmax=22.0 kg*aa=F max22

  v2=u2+2asv30= velocity at x=30v302=0+2*F max22*30 mv30= 60 F max 22

  From x=30 to x=55Acceleration = a30-55Force = Favg(30-55)Consider, Fmax=3 xForce at x=55 = F55 = -x

  Favg(30-55)= F 55 F max2=f3f2=fFavg(30-55) in turms of Fmax, Fmax=3 f F max3=fFavg(30-55)=xFavg(30-55)=F max3F=maFavg(30-55)=22.0 kg*aavg(30-55)Favg(30-55)=F max3F max3=22.0 kg*aavg(30-55)a=F max22*3

  For this point, u= 60 F max 22v2=u2+2asv55= velocity at x=55v552=60F max22+2*(F max22*3)*25 mv552=60F max2250F max22*3

  From x=55 to x=90F5590=Force from x=55 to x=90=-fa5590=acceleration from x=55 to x=90F5590 in turms of Fmax,F max3=fF5590=F max3F=maF max3=22.0 kg*aa5590=F max22*3

  For this point, u2=60F max2250F max22*3v2=u2+2asv90= velocity at x=90v552=60F max2250F max22*3+2*(F max22*3)*35 mv552=60F max2250F max22*370F max22*3

  From x=90 to x=100Acceleration = a90-100Force = Favg(90-100)Favg(90-100)=0(f)2=0.5fF max3=fFavg(90-100)=F max6F=maFavg(90-100)=22.0 kg*a90-100Favg(90-100)=F max6F max6=22.0 kg*a90-100a=F max22*6

  For this point, u2=60F max2250F max22*370F max22*3v2=u2+2asv100= velocity at x=100=12.5 ms-1v1002=60F max2250F max22*370F max22*3+2*F max22*6*10 mv1002=60F max2250F max22*370F max22*3+20F max22*6=(12.5 ms-1)260F max2250F max22*370F max22*3+20F max22*6=(12.5 ms-1)2156.25=2.73Fmax0.75Fmax1.00Fmax+0.15Fmax1.13Fmax=156.25Fmax=138.27 N

Conclusion:

  Fmax=138.27 N

Want to see more full solutions like this?

Subscribe now to access step-by-step solutions to millions of textbook problems written by subject matter experts!
Students have asked these similar questions
Can someone help me answer this physics 2 questions. Thank you.
Four capacitors are connected as shown in the figure below. (Let C = 12.0 μF.) a C 3.00 με Hh. 6.00 με 20.0 με HE (a) Find the equivalent capacitance between points a and b. 5.92 HF (b) Calculate the charge on each capacitor, taking AV ab = 16.0 V. 20.0 uF capacitor 94.7 6.00 uF capacitor 67.6 32.14 3.00 µF capacitor capacitor C ☑ με με The 3 µF and 12.0 uF capacitors are in series and that combination is in parallel with the 6 μF capacitor. What quantity is the same for capacitors in parallel? μC 32.14 ☑ You are correct that the charge on this capacitor will be the same as the charge on the 3 μF capacitor. μC
In the pivot assignment, we observed waves moving on a string stretched by hanging weights. We noticed that certain frequencies produced standing waves. One such situation is shown below: 0 ст Direct Measurement ©2015 Peter Bohacek I. 20 0 cm 10 20 30 40 50 60 70 80 90 100 Which Harmonic is this? Do NOT include units! What is the wavelength of this wave in cm with only no decimal places? If the speed of this wave is 2500 cm/s, what is the frequency of this harmonic (in Hz, with NO decimal places)?

Chapter 6 Solutions

COLLEGE PHYSICS

Ch. 6 - Prob. 11QAPCh. 6 - Prob. 12QAPCh. 6 - Prob. 13QAPCh. 6 - Prob. 14QAPCh. 6 - Prob. 15QAPCh. 6 - Prob. 16QAPCh. 6 - Prob. 17QAPCh. 6 - Prob. 18QAPCh. 6 - Prob. 19QAPCh. 6 - Prob. 20QAPCh. 6 - Prob. 21QAPCh. 6 - Prob. 22QAPCh. 6 - Prob. 23QAPCh. 6 - Prob. 24QAPCh. 6 - Prob. 25QAPCh. 6 - Prob. 26QAPCh. 6 - Prob. 27QAPCh. 6 - Prob. 28QAPCh. 6 - Prob. 29QAPCh. 6 - Prob. 30QAPCh. 6 - Prob. 31QAPCh. 6 - Prob. 32QAPCh. 6 - Prob. 33QAPCh. 6 - Prob. 34QAPCh. 6 - Prob. 35QAPCh. 6 - Prob. 36QAPCh. 6 - Prob. 37QAPCh. 6 - Prob. 38QAPCh. 6 - Prob. 39QAPCh. 6 - Prob. 40QAPCh. 6 - Prob. 41QAPCh. 6 - Prob. 42QAPCh. 6 - Prob. 43QAPCh. 6 - Prob. 44QAPCh. 6 - Prob. 45QAPCh. 6 - Prob. 46QAPCh. 6 - Prob. 47QAPCh. 6 - Prob. 48QAPCh. 6 - Prob. 49QAPCh. 6 - Prob. 50QAPCh. 6 - Prob. 51QAPCh. 6 - Prob. 52QAPCh. 6 - Prob. 53QAPCh. 6 - Prob. 54QAPCh. 6 - Prob. 55QAPCh. 6 - Prob. 56QAPCh. 6 - Prob. 57QAPCh. 6 - Prob. 58QAPCh. 6 - Prob. 59QAPCh. 6 - Prob. 60QAPCh. 6 - Prob. 61QAPCh. 6 - Prob. 62QAPCh. 6 - Prob. 63QAPCh. 6 - Prob. 64QAPCh. 6 - Prob. 65QAPCh. 6 - Prob. 66QAPCh. 6 - Prob. 67QAPCh. 6 - Prob. 68QAPCh. 6 - Prob. 69QAPCh. 6 - Prob. 70QAPCh. 6 - Prob. 71QAPCh. 6 - Prob. 72QAPCh. 6 - Prob. 73QAPCh. 6 - Prob. 74QAPCh. 6 - Prob. 75QAPCh. 6 - Prob. 76QAPCh. 6 - Prob. 77QAPCh. 6 - Prob. 78QAPCh. 6 - Prob. 79QAPCh. 6 - Prob. 80QAPCh. 6 - Prob. 81QAPCh. 6 - Prob. 82QAPCh. 6 - Prob. 83QAPCh. 6 - Prob. 84QAPCh. 6 - Prob. 85QAPCh. 6 - Prob. 86QAPCh. 6 - Prob. 87QAPCh. 6 - Prob. 88QAPCh. 6 - Prob. 89QAPCh. 6 - Prob. 90QAPCh. 6 - Prob. 91QAPCh. 6 - Prob. 92QAPCh. 6 - Prob. 93QAPCh. 6 - Prob. 94QAPCh. 6 - Prob. 95QAPCh. 6 - Prob. 96QAPCh. 6 - Prob. 97QAPCh. 6 - Prob. 98QAPCh. 6 - Prob. 99QAPCh. 6 - Prob. 100QAPCh. 6 - Prob. 101QAPCh. 6 - Prob. 102QAPCh. 6 - Prob. 103QAPCh. 6 - Prob. 104QAPCh. 6 - Prob. 105QAPCh. 6 - Prob. 106QAPCh. 6 - Prob. 107QAP
Knowledge Booster
Background pattern image
Physics
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, physics and related others by exploring similar questions and additional content below.
Similar questions
SEE MORE QUESTIONS
Recommended textbooks for you
Text book image
University Physics Volume 1
Physics
ISBN:9781938168277
Author:William Moebs, Samuel J. Ling, Jeff Sanny
Publisher:OpenStax - Rice University
Text book image
College Physics
Physics
ISBN:9781285737027
Author:Raymond A. Serway, Chris Vuille
Publisher:Cengage Learning
Text book image
Physics for Scientists and Engineers, Technology ...
Physics
ISBN:9781305116399
Author:Raymond A. Serway, John W. Jewett
Publisher:Cengage Learning
Text book image
College Physics
Physics
ISBN:9781938168000
Author:Paul Peter Urone, Roger Hinrichs
Publisher:OpenStax College
Text book image
Principles of Physics: A Calculus-Based Text
Physics
ISBN:9781133104261
Author:Raymond A. Serway, John W. Jewett
Publisher:Cengage Learning
Text book image
Glencoe Physics: Principles and Problems, Student...
Physics
ISBN:9780078807213
Author:Paul W. Zitzewitz
Publisher:Glencoe/McGraw-Hill
Conservative and Non Conservative Forces; Author: AK LECTURES;https://www.youtube.com/watch?v=vFVCluvSrFc;License: Standard YouTube License, CC-BY