COLLEGE PHYSICS
2nd Edition
ISBN: 9781464196393
Author: Freedman
Publisher: MAC HIGHER
expand_more
expand_more
format_list_bulleted
Videos
Question
Chapter 6, Problem 1QAP
To determine
The condition when the work done on an object by a force can be equal to zero.
Expert Solution & Answer
Explanation of Solution
Introduction:
When a force is applied on a body and it is moved at some distance in the direction of force, then work is said to be done.
The mathematical relation of work done is,
Where,
F is the applied force.
d is the total distance travelled by an object.
So, the work done will be zero when either force or displacement is zero. Also, it can be zero if force and displacement are perpendicular to each other even if they are non-zero quantities.
Conclusion:
Thus, the amount of work done will be zero if displacement is zero and, when force is perpendicular to the displacement.
Want to see more full solutions like this?
Subscribe now to access step-by-step solutions to millions of textbook problems written by subject matter experts!
Students have asked these similar questions
a 500-n block is dragged along a horizontal surface by an applied force t at an angle of 30.0° (see figure). the coefficient of kinetic friction is uk = 0.400 and the block moves at a constant velocity. what is the magnitude of the applied force T in newtons?
a 500-n block is dragged along a horizontal surface by an applied force t at an angle of 30.0° (see figure). the coefficient of kinetic friction is uk = 0.400 and the block moves at a constant velocity. what is the magnitude of the applied force T in newtons?
Block A, with a mass of 10 kg, rests on a 30° incline. The coefficient of kinetic friction is 0.20. The attached string is parallel to the incline and passes over a massless, frictionless pulley at the top. Block B, with a mass of 15.0 kg. is attached to the dangling end of the string. What is the acceleration of Block B in m/s?
show all steps please
Chapter 6 Solutions
COLLEGE PHYSICS
Ch. 6 - Prob. 1QAPCh. 6 - Prob. 2QAPCh. 6 - Prob. 3QAPCh. 6 - Prob. 4QAPCh. 6 - Prob. 5QAPCh. 6 - Prob. 6QAPCh. 6 - Prob. 7QAPCh. 6 - Prob. 8QAPCh. 6 - Prob. 9QAPCh. 6 - Prob. 10QAP
Ch. 6 - Prob. 11QAPCh. 6 - Prob. 12QAPCh. 6 - Prob. 13QAPCh. 6 - Prob. 14QAPCh. 6 - Prob. 15QAPCh. 6 - Prob. 16QAPCh. 6 - Prob. 17QAPCh. 6 - Prob. 18QAPCh. 6 - Prob. 19QAPCh. 6 - Prob. 20QAPCh. 6 - Prob. 21QAPCh. 6 - Prob. 22QAPCh. 6 - Prob. 23QAPCh. 6 - Prob. 24QAPCh. 6 - Prob. 25QAPCh. 6 - Prob. 26QAPCh. 6 - Prob. 27QAPCh. 6 - Prob. 28QAPCh. 6 - Prob. 29QAPCh. 6 - Prob. 30QAPCh. 6 - Prob. 31QAPCh. 6 - Prob. 32QAPCh. 6 - Prob. 33QAPCh. 6 - Prob. 34QAPCh. 6 - Prob. 35QAPCh. 6 - Prob. 36QAPCh. 6 - Prob. 37QAPCh. 6 - Prob. 38QAPCh. 6 - Prob. 39QAPCh. 6 - Prob. 40QAPCh. 6 - Prob. 41QAPCh. 6 - Prob. 42QAPCh. 6 - Prob. 43QAPCh. 6 - Prob. 44QAPCh. 6 - Prob. 45QAPCh. 6 - Prob. 46QAPCh. 6 - Prob. 47QAPCh. 6 - Prob. 48QAPCh. 6 - Prob. 49QAPCh. 6 - Prob. 50QAPCh. 6 - Prob. 51QAPCh. 6 - Prob. 52QAPCh. 6 - Prob. 53QAPCh. 6 - Prob. 54QAPCh. 6 - Prob. 55QAPCh. 6 - Prob. 56QAPCh. 6 - Prob. 57QAPCh. 6 - Prob. 58QAPCh. 6 - Prob. 59QAPCh. 6 - Prob. 60QAPCh. 6 - Prob. 61QAPCh. 6 - Prob. 62QAPCh. 6 - Prob. 63QAPCh. 6 - Prob. 64QAPCh. 6 - Prob. 65QAPCh. 6 - Prob. 66QAPCh. 6 - Prob. 67QAPCh. 6 - Prob. 68QAPCh. 6 - Prob. 69QAPCh. 6 - Prob. 70QAPCh. 6 - Prob. 71QAPCh. 6 - Prob. 72QAPCh. 6 - Prob. 73QAPCh. 6 - Prob. 74QAPCh. 6 - Prob. 75QAPCh. 6 - Prob. 76QAPCh. 6 - Prob. 77QAPCh. 6 - Prob. 78QAPCh. 6 - Prob. 79QAPCh. 6 - Prob. 80QAPCh. 6 - Prob. 81QAPCh. 6 - Prob. 82QAPCh. 6 - Prob. 83QAPCh. 6 - Prob. 84QAPCh. 6 - Prob. 85QAPCh. 6 - Prob. 86QAPCh. 6 - Prob. 87QAPCh. 6 - Prob. 88QAPCh. 6 - Prob. 89QAPCh. 6 - Prob. 90QAPCh. 6 - Prob. 91QAPCh. 6 - Prob. 92QAPCh. 6 - Prob. 93QAPCh. 6 - Prob. 94QAPCh. 6 - Prob. 95QAPCh. 6 - Prob. 96QAPCh. 6 - Prob. 97QAPCh. 6 - Prob. 98QAPCh. 6 - Prob. 99QAPCh. 6 - Prob. 100QAPCh. 6 - Prob. 101QAPCh. 6 - Prob. 102QAPCh. 6 - Prob. 103QAPCh. 6 - Prob. 104QAPCh. 6 - Prob. 105QAPCh. 6 - Prob. 106QAPCh. 6 - Prob. 107QAP
Knowledge Booster
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, physics and related others by exploring similar questions and additional content below.Similar questions
- When current is flowing through the coil, the direction of the torque can be thought of in two ways. Either as the result of the forces on current carrying wires, or as a magnetic dipole moment trying to line up with an external field (e.g. like a compass). Note: the magnetic moment of a coil points in the direction of the coil's magnetic field at the center of the coil. d) Forces: We can consider the left-most piece of the loop (labeled ○) as a short segment of straight wire carrying current directly out of the page at us. Similarly, we can consider the right-most piece of the loop (labeled ) as a short segment straight wire carrying current directly into the page, away from us. Add to the picture below the two forces due to the external magnetic field acting on these two segments. Then describe how these two forces give a torque and determine if the torque acts to rotate the loop clockwise or counterclockwise according to this picture? Barrow_forwardIn each of the following, solve the problem stated. Express your answers in three significant figures. No unit is considered incorrect. 1. For the circuit shown, determine all the currents in each branch using Kirchhoff's Laws. (3 points) 6 5V 2 B C 4 A www 6 VT ww T10 V F E 2. Compute for the total power dissipation of the circuit in previous item. (1 point) 3. Use Maxwell's Mesh to find Ix and VAB for the circuit shown. (3 points) Ix 50 V 20 ww 21x B 4. Calculate all the currents in each branch using Maxwell's Mesh for the circuit shown. (3 points) www 5ი 10 24V 2A 2002 36Varrow_forwardIf the mass of substance (1 kg), initial temperature (125˚C), the final temperature (175˚C) and the total volume of a closed container (1 m3) remains constant in two experiments, but one experiment is done with water ( ) and the other is done with nitrogen ( ). What is the difference in the change in pressure between water and nitrogen?arrow_forward
- Using the simplified energy balance in Equation 1, suppose there is heat transfer of 40.00 J to a system, while the system does 10.00 J of work. Later, there is heat transfer of 25.00 J out of the system while 4.00 J of work is done on the system. What is the net change in internal energy of the system?arrow_forwardYou pour a litre (1 kg) of 25.0˚C water into a 0.500 kg aluminium pan off the stove, but has previously been heated so it starts with a temperature of 120˚C. What is the temperature when the water and the pan reach thermal equilibrium (i.e., what is the temperature of both objects when they reach the same temperature)? Assume that the pan is placed on an insulated pad and a negligible amount of water boils off.arrow_forwardA golf club hits a golf ball and the golf ball’s flight reaches a maximum height of 5.48 m. Calculate the momentum of the golf ball at the maximum height if the mass of the golf ball is 0.459 kg.arrow_forward
- • Superposition Theorem • Thevenin's and Norton's Theorem 1. Find the unknown voltage V₁, unknown resistances R1 and R2, and currents flowing through R1 and R2 for the circuit shown below using Superposition Theorem. 40 V + R₁₂ w B C ♥16A 10A www 4A F ww 2 E Ꭰ 2. Use Thevenin's Theorem to find the current flowing in 3-ohm resistor and its power dissipation from the circuit shown in the right. + 3. Use Norton's Theorem for the same instruction as for No. 2. 8 V A www 202 B wwww 20 Ω 10 V + 302 202 www C - 12 V 502 www.arrow_forwardFill in blanksarrow_forwardA rock is dropped from a height of 2.00 m. Determine the velocity of the rock just before it hits the ground. If the momentum of the rock just before hitting the ground is 14.0 kg m/s, what is the mass of the rock? Is the collision between the rock and the ground elastic or inelastic? Explain.arrow_forward
- Describe how the momentum of a single ball changes as it free falls from a height of approximately 1 m, collides with a hard floor, and rebounds.arrow_forward• Nature of Resistance Temperature-Resistance Relationship Ohm's Law, Energy and Power Kirchhoff's Law • • Maxwell's Mesh Analysis 1. The steel of the third rail of a railway system has a resistivity of 21.4 μ-cm. If its cross-sectional area is 8.2 in², calculate the resistance per mile of rail, neglecting the effect of joints between sections. (1 point) 2. An incandescent lamp has a tungsten filament whose resistance is 96 at its operating temperature of 2900°C. Calculate the filament resistance when the lamp is disconnected from the electric source, under which condition its temperature is 24°C. (Use do = 0.0045 02/°C for tungsten) (1 point) 3. For the circuit shown, find the following: 50 V 602 10 V 702 a. the value of resistor R. (1 point) b. the equivalent resistance with respect to the 50-V source. (1 point) 4. For the circuit shown, determine all the currents in each branch using Kirchhoff's Laws. (3 points) A 5V 2 В -ний C 4 6 VT ww F E 5. Use Maxwell's Mesh to find I, and VAB…arrow_forwardFor items 8-9, refer to the problem below. Find all the currents flowing in every resistor, power dissipation in every resistor and the total power of the circuit shown at the right using... 8. Kirchhoff's Laws (5 pts) 9. Maxwell's Mesh Analysis (5 pts) A 8 V 10 V B + 20 Ω 3Ω 202 wwww C wwww 202 + 50 www 12 Varrow_forward
arrow_back_ios
SEE MORE QUESTIONS
arrow_forward_ios
Recommended textbooks for you
Principles of Physics: A Calculus-Based TextPhysicsISBN:9781133104261Author:Raymond A. Serway, John W. JewettPublisher:Cengage Learning
Glencoe Physics: Principles and Problems, Student...PhysicsISBN:9780078807213Author:Paul W. ZitzewitzPublisher:Glencoe/McGraw-Hill
University Physics Volume 1PhysicsISBN:9781938168277Author:William Moebs, Samuel J. Ling, Jeff SannyPublisher:OpenStax - Rice University
Physics for Scientists and Engineers with Modern ...PhysicsISBN:9781337553292Author:Raymond A. Serway, John W. JewettPublisher:Cengage Learning
College PhysicsPhysicsISBN:9781285737027Author:Raymond A. Serway, Chris VuillePublisher:Cengage Learning
College PhysicsPhysicsISBN:9781938168000Author:Paul Peter Urone, Roger HinrichsPublisher:OpenStax College
Principles of Physics: A Calculus-Based Text
Physics
ISBN:9781133104261
Author:Raymond A. Serway, John W. Jewett
Publisher:Cengage Learning
Glencoe Physics: Principles and Problems, Student...
Physics
ISBN:9780078807213
Author:Paul W. Zitzewitz
Publisher:Glencoe/McGraw-Hill
University Physics Volume 1
Physics
ISBN:9781938168277
Author:William Moebs, Samuel J. Ling, Jeff Sanny
Publisher:OpenStax - Rice University
Physics for Scientists and Engineers with Modern ...
Physics
ISBN:9781337553292
Author:Raymond A. Serway, John W. Jewett
Publisher:Cengage Learning
College Physics
Physics
ISBN:9781285737027
Author:Raymond A. Serway, Chris Vuille
Publisher:Cengage Learning
College Physics
Physics
ISBN:9781938168000
Author:Paul Peter Urone, Roger Hinrichs
Publisher:OpenStax College
Mechanical work done (GCSE Physics); Author: Dr de Bruin's Classroom;https://www.youtube.com/watch?v=OapgRhYDMvw;License: Standard YouTube License, CC-BY