Gen Combo Ll Statistical Techniques In Business And Economics; Connect Ac
17th Edition
ISBN: 9781260149623
Author: Lind
Publisher: MCG
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Chapter 6, Problem 54CE
a.
To determine
Explain the reason why hypergeometric distribution is appropriate for the given context.
b.
To determine
Compute the
c.
To determine
Compute the probability that at least one of the audited returns had a charitable contribution of more than $1,000.
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Calculate the 90% confidence interval for the population mean difference using the data in the attached image. I need to see where I went wrong.
Microsoft Excel snapshot for random sampling: Also note the formula used for the last
column
02
x✓ fx =INDEX(5852:58551, RANK(C2, $C$2:$C$51))
A
B
1
No.
States
2
1
ALABAMA
Rand No.
0.925957526
3
2
ALASKA
0.372999976
4
3
ARIZONA
0.941323044
5
4 ARKANSAS
0.071266381
Random Sample
CALIFORNIA
NORTH CAROLINA
ARKANSAS
WASHINGTON
G7
Microsoft Excel snapshot for systematic sampling:
xfx INDEX(SD52:50551, F7)
A
B
E
F
G
1
No.
States
Rand No. Random Sample
population
50
2
1 ALABAMA
0.5296685 NEW HAMPSHIRE
sample
10
3
2 ALASKA
0.4493186 OKLAHOMA
k
5
4
3 ARIZONA
0.707914 KANSAS
5
4 ARKANSAS 0.4831379 NORTH DAKOTA
6
5 CALIFORNIA 0.7277162 INDIANA
Random Sample
Sample Name
7
6 COLORADO 0.5865002 MISSISSIPPI
8
7:ONNECTICU 0.7640596 ILLINOIS
9
8 DELAWARE 0.5783029 MISSOURI
525
10
15
INDIANA
MARYLAND
COLORADO
Chapter 6 Solutions
Gen Combo Ll Statistical Techniques In Business And Economics; Connect Ac
Ch. 6 - The possible outcomes of an experiment involving...Ch. 6 - The Pizza Palace offers three sizes of cola. The...Ch. 6 - FILE Compute the mean and variance of the...Ch. 6 - FILE Compute the mean and variance of the...Ch. 6 - FILE Compute the mean and variance of the...Ch. 6 - Which of these variables are discrete and which...Ch. 6 - FILE The information below is the number of daily...Ch. 6 - FILE The director of admissions at Kinzua...Ch. 6 - Prob. 7ECh. 6 - FILE The Downtown Parking Authority of Tampa,...
Ch. 6 - Ninety-five percent of the employees at the J. M....Ch. 6 - In a binomial situation, n = 4 and = .25....Ch. 6 - In a binomial situation, n = 5 and = .40....Ch. 6 - Prob. 11ECh. 6 - Assume a binomial distribution where n = 5 and =...Ch. 6 - An American Society of Investors survey found 30%...Ch. 6 - Prob. 14ECh. 6 - Prob. 15ECh. 6 - FILE A telemarketer makes six phone calls per hour...Ch. 6 - FILE A recent survey by the American Accounting...Ch. 6 - Prob. 18ECh. 6 - Prob. 4SRCh. 6 - Prob. 19ECh. 6 - In a binomial distribution, n = 12 and = .60....Ch. 6 - FILE In a recent study, 90% of the homes in the...Ch. 6 - FILE A manufacturer of window frames knows from...Ch. 6 - Prob. 23ECh. 6 - Prob. 24ECh. 6 - Prob. 5SRCh. 6 - Prob. 25ECh. 6 - A population consists of 15 items, 10 of which are...Ch. 6 - Prob. 27ECh. 6 - Prob. 28ECh. 6 - Prob. 29ECh. 6 - Prob. 30ECh. 6 - Prob. 6SRCh. 6 - Prob. 31ECh. 6 - Prob. 32ECh. 6 - Prob. 33ECh. 6 - Automobiles arrive at the Elkhart exit of the...Ch. 6 - It is estimated that 0.5% of the callers to the...Ch. 6 - Prob. 36ECh. 6 - Prob. 37CECh. 6 - For each of the following indicate whether the...Ch. 6 - Prob. 39CECh. 6 - Prob. 40CECh. 6 - Prob. 41CECh. 6 - The payouts for the Powerball lottery and their...Ch. 6 - In a recent study, 35% of people surveyed...Ch. 6 - Prob. 44CECh. 6 - An auditor for Health Maintenance Services of...Ch. 6 - Prob. 46CECh. 6 - Prob. 47CECh. 6 - The Bank of Hawaii reports that 7% of its credit...Ch. 6 - Prob. 49CECh. 6 - Prob. 50CECh. 6 - Prob. 51CECh. 6 - Prob. 52CECh. 6 - Prob. 53CECh. 6 - Prob. 54CECh. 6 - Prob. 55CECh. 6 - Prob. 56CECh. 6 - Prob. 57CECh. 6 - Prob. 58CECh. 6 - Prob. 59CECh. 6 - Prob. 60CECh. 6 - Prob. 61CECh. 6 - Prob. 62CECh. 6 - Prob. 63CECh. 6 - Prob. 64CECh. 6 - The National Aeronautics and Space Administration...Ch. 6 - Prob. 66CECh. 6 - Prob. 67CECh. 6 - Prob. 68CECh. 6 - A recent CBS News survey reported that 67% of...Ch. 6 - Prob. 70DACh. 6 - Prob. 71DA
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- Client 1 Weight before diet (pounds) Weight after diet (pounds) 128 120 2 131 123 3 140 141 4 178 170 5 121 118 6 136 136 7 118 121 8 136 127arrow_forwardClient 1 Weight before diet (pounds) Weight after diet (pounds) 128 120 2 131 123 3 140 141 4 178 170 5 121 118 6 136 136 7 118 121 8 136 127 a) Determine the mean change in patient weight from before to after the diet (after – before). What is the 95% confidence interval of this mean difference?arrow_forwardIn order to find probability, you can use this formula in Microsoft Excel: The best way to understand and solve these problems is by first drawing a bell curve and marking key points such as x, the mean, and the areas of interest. Once marked on the bell curve, figure out what calculations are needed to find the area of interest. =NORM.DIST(x, Mean, Standard Dev., TRUE). When the question mentions “greater than” you may have to subtract your answer from 1. When the question mentions “between (two values)”, you need to do separate calculation for both values and then subtract their results to get the answer. 1. Compute the probability of a value between 44.0 and 55.0. (The question requires finding probability value between 44 and 55. Solve it in 3 steps. In the first step, use the above formula and x = 44, calculate probability value. In the second step repeat the first step with the only difference that x=55. In the third step, subtract the answer of the first part from the…arrow_forward
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