Gen Combo Ll Statistical Techniques In Business And Economics; Connect Ac
17th Edition
ISBN: 9781260149623
Author: Lind
Publisher: MCG
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Chapter 6, Problem 51CE
To determine
Compute the
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Consider the time series X₁ and Y₁ = (I – B)² (I – B³)Xt. What transformations were
performed on Xt to obtain Yt?
seasonal difference of order 2
simple difference of order 5
seasonal difference of order 1
seasonal difference of order 5
simple difference of order 2
Calculate the 90% confidence interval for the population mean difference using the data in the attached image. I need to see where I went wrong.
Microsoft Excel snapshot for random sampling: Also note the formula used for the last
column
02
x✓ fx =INDEX(5852:58551, RANK(C2, $C$2:$C$51))
A
B
1
No.
States
2
1
ALABAMA
Rand No.
0.925957526
3
2
ALASKA
0.372999976
4
3
ARIZONA
0.941323044
5
4 ARKANSAS
0.071266381
Random Sample
CALIFORNIA
NORTH CAROLINA
ARKANSAS
WASHINGTON
G7
Microsoft Excel snapshot for systematic sampling:
xfx INDEX(SD52:50551, F7)
A
B
E
F
G
1
No.
States
Rand No. Random Sample
population
50
2
1 ALABAMA
0.5296685 NEW HAMPSHIRE
sample
10
3
2 ALASKA
0.4493186 OKLAHOMA
k
5
4
3 ARIZONA
0.707914 KANSAS
5
4 ARKANSAS 0.4831379 NORTH DAKOTA
6
5 CALIFORNIA 0.7277162 INDIANA
Random Sample
Sample Name
7
6 COLORADO 0.5865002 MISSISSIPPI
8
7:ONNECTICU 0.7640596 ILLINOIS
9
8 DELAWARE 0.5783029 MISSOURI
525
10
15
INDIANA
MARYLAND
COLORADO
Chapter 6 Solutions
Gen Combo Ll Statistical Techniques In Business And Economics; Connect Ac
Ch. 6 - The possible outcomes of an experiment involving...Ch. 6 - The Pizza Palace offers three sizes of cola. The...Ch. 6 - FILE Compute the mean and variance of the...Ch. 6 - FILE Compute the mean and variance of the...Ch. 6 - FILE Compute the mean and variance of the...Ch. 6 - Which of these variables are discrete and which...Ch. 6 - FILE The information below is the number of daily...Ch. 6 - FILE The director of admissions at Kinzua...Ch. 6 - Prob. 7ECh. 6 - FILE The Downtown Parking Authority of Tampa,...
Ch. 6 - Ninety-five percent of the employees at the J. M....Ch. 6 - In a binomial situation, n = 4 and = .25....Ch. 6 - In a binomial situation, n = 5 and = .40....Ch. 6 - Prob. 11ECh. 6 - Assume a binomial distribution where n = 5 and =...Ch. 6 - An American Society of Investors survey found 30%...Ch. 6 - Prob. 14ECh. 6 - Prob. 15ECh. 6 - FILE A telemarketer makes six phone calls per hour...Ch. 6 - FILE A recent survey by the American Accounting...Ch. 6 - Prob. 18ECh. 6 - Prob. 4SRCh. 6 - Prob. 19ECh. 6 - In a binomial distribution, n = 12 and = .60....Ch. 6 - FILE In a recent study, 90% of the homes in the...Ch. 6 - FILE A manufacturer of window frames knows from...Ch. 6 - Prob. 23ECh. 6 - Prob. 24ECh. 6 - Prob. 5SRCh. 6 - Prob. 25ECh. 6 - A population consists of 15 items, 10 of which are...Ch. 6 - Prob. 27ECh. 6 - Prob. 28ECh. 6 - Prob. 29ECh. 6 - Prob. 30ECh. 6 - Prob. 6SRCh. 6 - Prob. 31ECh. 6 - Prob. 32ECh. 6 - Prob. 33ECh. 6 - Automobiles arrive at the Elkhart exit of the...Ch. 6 - It is estimated that 0.5% of the callers to the...Ch. 6 - Prob. 36ECh. 6 - Prob. 37CECh. 6 - For each of the following indicate whether the...Ch. 6 - Prob. 39CECh. 6 - Prob. 40CECh. 6 - Prob. 41CECh. 6 - The payouts for the Powerball lottery and their...Ch. 6 - In a recent study, 35% of people surveyed...Ch. 6 - Prob. 44CECh. 6 - An auditor for Health Maintenance Services of...Ch. 6 - Prob. 46CECh. 6 - Prob. 47CECh. 6 - The Bank of Hawaii reports that 7% of its credit...Ch. 6 - Prob. 49CECh. 6 - Prob. 50CECh. 6 - Prob. 51CECh. 6 - Prob. 52CECh. 6 - Prob. 53CECh. 6 - Prob. 54CECh. 6 - Prob. 55CECh. 6 - Prob. 56CECh. 6 - Prob. 57CECh. 6 - Prob. 58CECh. 6 - Prob. 59CECh. 6 - Prob. 60CECh. 6 - Prob. 61CECh. 6 - Prob. 62CECh. 6 - Prob. 63CECh. 6 - Prob. 64CECh. 6 - The National Aeronautics and Space Administration...Ch. 6 - Prob. 66CECh. 6 - Prob. 67CECh. 6 - Prob. 68CECh. 6 - A recent CBS News survey reported that 67% of...Ch. 6 - Prob. 70DACh. 6 - Prob. 71DA
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- Client 1 Weight before diet (pounds) Weight after diet (pounds) 128 120 2 131 123 3 140 141 4 178 170 5 121 118 6 136 136 7 118 121 8 136 127arrow_forwardClient 1 Weight before diet (pounds) Weight after diet (pounds) 128 120 2 131 123 3 140 141 4 178 170 5 121 118 6 136 136 7 118 121 8 136 127 a) Determine the mean change in patient weight from before to after the diet (after – before). What is the 95% confidence interval of this mean difference?arrow_forwardIn order to find probability, you can use this formula in Microsoft Excel: The best way to understand and solve these problems is by first drawing a bell curve and marking key points such as x, the mean, and the areas of interest. Once marked on the bell curve, figure out what calculations are needed to find the area of interest. =NORM.DIST(x, Mean, Standard Dev., TRUE). When the question mentions “greater than” you may have to subtract your answer from 1. When the question mentions “between (two values)”, you need to do separate calculation for both values and then subtract their results to get the answer. 1. Compute the probability of a value between 44.0 and 55.0. (The question requires finding probability value between 44 and 55. Solve it in 3 steps. In the first step, use the above formula and x = 44, calculate probability value. In the second step repeat the first step with the only difference that x=55. In the third step, subtract the answer of the first part from the…arrow_forward
- If a uniform distribution is defined over the interval from 6 to 10, then answer the followings: What is the mean of this uniform distribution? Show that the probability of any value between 6 and 10 is equal to 1.0 Find the probability of a value more than 7. Find the probability of a value between 7 and 9. The closing price of Schnur Sporting Goods Inc. common stock is uniformly distributed between $20 and $30 per share. What is the probability that the stock price will be: More than $27? Less than or equal to $24? The April rainfall in Flagstaff, Arizona, follows a uniform distribution between 0.5 and 3.00 inches. What is the mean amount of rainfall for the month? What is the probability of less than an inch of rain for the month? What is the probability of exactly 1.00 inch of rain? What is the probability of more than 1.50 inches of rain for the month? The best way to solve this problem is begin by creating a chart. Clearly mark the range, identifying the lower and upper…arrow_forwardProblem 1: The mean hourly pay of an American Airlines flight attendant is normally distributed with a mean of 40 per hour and a standard deviation of 3.00 per hour. What is the probability that the hourly pay of a randomly selected flight attendant is: Between the mean and $45 per hour? More than $45 per hour? Less than $32 per hour? Problem 2: The mean of a normal probability distribution is 400 pounds. The standard deviation is 10 pounds. What is the area between 415 pounds and the mean of 400 pounds? What is the area between the mean and 395 pounds? What is the probability of randomly selecting a value less than 395 pounds? Problem 3: In New York State, the mean salary for high school teachers in 2022 was 81,410 with a standard deviation of 9,500. Only Alaska’s mean salary was higher. Assume New York’s state salaries follow a normal distribution. What percent of New York State high school teachers earn between 70,000 and 75,000? What percent of New York State high school…arrow_forwardPls help asaparrow_forward
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