Chemistry In Context
Chemistry In Context
9th Edition
ISBN: 9781259638145
Author: Fahlman, Bradley D., Purvis-roberts, Kathleen, Kirk, John S., Bentley, Anne K., Daubenmire, Patrick L., ELLIS, Jamie P., Mury, Michael T., American Chemical Society
Publisher: Mcgraw-hill Education,
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Chapter 6, Problem 45Q
Interpretation Introduction

Interpretation:

Two similarities and two differences between a nuclear-fueled power plant and a coal- fueled power plant have to be provided.

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Hydrazine, N2H4, can be used as fuel to orient and maneuver spacecraft. The energy used to do so is obtained by reacting the hydrazine with dinitrogen tetroxide to form nitrogen gas and water vapor. Write and balance the chemical equation for this reaction.The spy satellite US-193 had 453 kg of hydrazine on board when it was destroyed. What mass of dinitrogen tetroxide would have had to be on board in order to completely react with the hydrazine? This reaction is a redox reaction. Assign oxidation states to each atom in the reaction,identify what is oxidized, what is reduced, the oxidizing agent, and the reducing agent. Answer in full please.
Using your cars miles per gallon and the miles you drive in 1 week calculate the liters of carbon dioxide you produce when using your car.  Compare your miles in February (pre-covid) versus June (post-covid). Assume that your engine combusts at 1.00 atm and 25.0 celsius. Assume that your gasoline is 100% octane (C8H18). You will also need to balance the combustion reaction that occurs in your car engine. You will need to use PV=nRT I think calculations are not correct specially for June. please help     2C8H18+ 25O2→16CO2+18H2O   Feb, (pre covid), Miles covered per week=15×7=105 miles So fuel consumed per week=105 miles/30 miles ga =3.5 ga Density of octane=3.18 kg/ga Mass=volume × density  Mass of Octane used per week = 3.5 ga x 3.18 kg/ga =11.13 kg Moles of octane in 11.13 kg 11.13 kg/114 kg/k mol =0.097 kmol 2 kmol octan≡16 kmol CO2 0.097 kmol octane =16/2 × 0.097 kmol CO2   0.097 kmol octane = 0.781 kmol CO2  n= 0.781 kmol=781 moles CO2 V=781 mol x 8.314j/k. mol x (25+273)K/1atm x…

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Chemistry In Context

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