COLLEGE PHYSICS,VOLUME 1
COLLEGE PHYSICS,VOLUME 1
2nd Edition
ISBN: 9781319115104
Author: Freedman
Publisher: MAC HIGHER
bartleby

Videos

Question
Book Icon
Chapter 6, Problem 42QAP
To determine

(a)

Work done by the assistant for the football team in carrying a 30.0 kg cooler from the top row of the stadium to the bench area located 20.0 m below.

Expert Solution
Check Mark

Answer to Problem 42QAP

The work done by the assistant for the football team in carrying a 30.0 kg cooler from the top row of the stadium to the bench area located 20.0 m below is 5.88×103 J.

Explanation of Solution

Given:

Mass of the cooler

  m=30.0 kg

Vertical displacement of the cooler

  h=20.0 m(j^)

Acceleration due to gravity

  g=9.80 m/s2(j^)

Formula used:

The work done W by a force F is equal to the scalar (dot) product of the force and the displacement d of the point of application of the force.

  W=F·d

Calculation:

The weight FG ( gravitational force) of the cooler acts downwards, while the force F exerted by the assistant acts in the upward direction. If the cooler moves with constant velocity, the force F is equal in magnitude to the weight FG but is in a direction opposite to it, keeping the net force on the cooler to have a value zero.

  F=FG

Write an expression for FG. Assume the + x direction along the right and +y direction upwards.

  FG=mg

Therefore,

  F=FG=mg

Write an expression for the work done by the force exerted by the assistant.

  W=F·h=mg·h

Calculate the work done by substituting the known values in the above equation.

  W=mg·h=(30.0 kg)[9.80 m/s2( j ^)][20.0 m( j ^)]=5.88×103 J

Conclusion:

Thus, the work done by the assistant for the football team in carrying a 30.0 kg cooler from the top row of the stadium to the bench area located 20.0 m below is 5.88×103 J.

To determine

(b)

The work done by the gravity on the cooler.

Expert Solution
Check Mark

Answer to Problem 42QAP

The work done by the gravity on the cooler is 5.88×103 J.

Explanation of Solution

Given:

Mass of the cooler

  m=30.0 kg

Vertical displacement of the cooler

  h=20.0 m(j^)

Acceleration due to gravity

  g=9.80 m/s2(j^)

Formula used:

The work done W by a force F is equal to the scalar (dot) product of the force and the displacement d of the point of application of the force.

  W=F·d

Calculation:

Write an expression for the work done by gravitational force.

  WG=mg·h

Substitute the known values of the variables in the expression.

  WG=mg·h=(30.0 kg)[9.80 m/s2( j ^)][15.0 m( j ^)]=5.88×103 J

Since the displacement is in the direction of the force, the work done is positive.

Conclusion:

Thus, the work done by the gravity on the cooler is 5.88×103 J.

Want to see more full solutions like this?

Subscribe now to access step-by-step solutions to millions of textbook problems written by subject matter experts!
Students have asked these similar questions
a 500-n block is dragged along a horizontal surface by an applied force t at an angle of 30.0° (see figure). the coefficient of kinetic friction is uk = 0.400 and the block moves at a constant velocity. what is the magnitude of the applied force T in newtons?
a 500-n block is dragged along a horizontal surface by an applied force t at an angle of 30.0° (see figure). the coefficient of kinetic friction is uk = 0.400 and the block moves at a constant velocity. what is the magnitude of the applied force T in newtons?
Block A, with a mass of 10 kg, rests on a 30° incline. The coefficient of kinetic friction is 0.20. The attached string is parallel to the incline and passes over a massless, frictionless pulley at the top. Block B, with a mass of 15.0 kg. is attached to the dangling end of the string. What is the acceleration of Block B in m/s?  show all steps please

Chapter 6 Solutions

COLLEGE PHYSICS,VOLUME 1

Ch. 6 - Prob. 11QAPCh. 6 - Prob. 12QAPCh. 6 - Prob. 13QAPCh. 6 - Prob. 14QAPCh. 6 - Prob. 15QAPCh. 6 - Prob. 16QAPCh. 6 - Prob. 17QAPCh. 6 - Prob. 18QAPCh. 6 - Prob. 19QAPCh. 6 - Prob. 20QAPCh. 6 - Prob. 21QAPCh. 6 - Prob. 22QAPCh. 6 - Prob. 23QAPCh. 6 - Prob. 24QAPCh. 6 - Prob. 25QAPCh. 6 - Prob. 26QAPCh. 6 - Prob. 27QAPCh. 6 - Prob. 28QAPCh. 6 - Prob. 29QAPCh. 6 - Prob. 30QAPCh. 6 - Prob. 31QAPCh. 6 - Prob. 32QAPCh. 6 - Prob. 33QAPCh. 6 - Prob. 34QAPCh. 6 - Prob. 35QAPCh. 6 - Prob. 36QAPCh. 6 - Prob. 37QAPCh. 6 - Prob. 38QAPCh. 6 - Prob. 39QAPCh. 6 - Prob. 40QAPCh. 6 - Prob. 41QAPCh. 6 - Prob. 42QAPCh. 6 - Prob. 43QAPCh. 6 - Prob. 44QAPCh. 6 - Prob. 45QAPCh. 6 - Prob. 46QAPCh. 6 - Prob. 47QAPCh. 6 - Prob. 48QAPCh. 6 - Prob. 49QAPCh. 6 - Prob. 50QAPCh. 6 - Prob. 51QAPCh. 6 - Prob. 52QAPCh. 6 - Prob. 53QAPCh. 6 - Prob. 54QAPCh. 6 - Prob. 55QAPCh. 6 - Prob. 56QAPCh. 6 - Prob. 57QAPCh. 6 - Prob. 58QAPCh. 6 - Prob. 59QAPCh. 6 - Prob. 60QAPCh. 6 - Prob. 61QAPCh. 6 - Prob. 62QAPCh. 6 - Prob. 63QAPCh. 6 - Prob. 64QAPCh. 6 - Prob. 65QAPCh. 6 - Prob. 66QAPCh. 6 - Prob. 67QAPCh. 6 - Prob. 68QAPCh. 6 - Prob. 69QAPCh. 6 - Prob. 70QAPCh. 6 - Prob. 71QAPCh. 6 - Prob. 72QAPCh. 6 - Prob. 73QAPCh. 6 - Prob. 74QAPCh. 6 - Prob. 75QAPCh. 6 - Prob. 76QAPCh. 6 - Prob. 77QAPCh. 6 - Prob. 78QAPCh. 6 - Prob. 79QAPCh. 6 - Prob. 80QAPCh. 6 - Prob. 81QAPCh. 6 - Prob. 82QAPCh. 6 - Prob. 83QAPCh. 6 - Prob. 84QAPCh. 6 - Prob. 85QAPCh. 6 - Prob. 86QAPCh. 6 - Prob. 87QAPCh. 6 - Prob. 88QAPCh. 6 - Prob. 89QAPCh. 6 - Prob. 90QAPCh. 6 - Prob. 91QAPCh. 6 - Prob. 92QAPCh. 6 - Prob. 93QAPCh. 6 - Prob. 94QAPCh. 6 - Prob. 95QAPCh. 6 - Prob. 96QAPCh. 6 - Prob. 97QAPCh. 6 - Prob. 98QAPCh. 6 - Prob. 99QAPCh. 6 - Prob. 100QAPCh. 6 - Prob. 101QAPCh. 6 - Prob. 102QAPCh. 6 - Prob. 103QAPCh. 6 - Prob. 104QAPCh. 6 - Prob. 105QAPCh. 6 - Prob. 106QAPCh. 6 - Prob. 107QAP
Knowledge Booster
Background pattern image
Physics
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, physics and related others by exploring similar questions and additional content below.
Similar questions
SEE MORE QUESTIONS
Recommended textbooks for you
Text book image
Principles of Physics: A Calculus-Based Text
Physics
ISBN:9781133104261
Author:Raymond A. Serway, John W. Jewett
Publisher:Cengage Learning
Text book image
Physics for Scientists and Engineers with Modern ...
Physics
ISBN:9781337553292
Author:Raymond A. Serway, John W. Jewett
Publisher:Cengage Learning
Text book image
Physics for Scientists and Engineers, Technology ...
Physics
ISBN:9781305116399
Author:Raymond A. Serway, John W. Jewett
Publisher:Cengage Learning
Text book image
College Physics
Physics
ISBN:9781938168000
Author:Paul Peter Urone, Roger Hinrichs
Publisher:OpenStax College
Text book image
College Physics
Physics
ISBN:9781285737027
Author:Raymond A. Serway, Chris Vuille
Publisher:Cengage Learning
Text book image
Physics for Scientists and Engineers
Physics
ISBN:9781337553278
Author:Raymond A. Serway, John W. Jewett
Publisher:Cengage Learning
Mechanical work done (GCSE Physics); Author: Dr de Bruin's Classroom;https://www.youtube.com/watch?v=OapgRhYDMvw;License: Standard YouTube License, CC-BY