COMPUTER SCIENCE ILLUMIN.-TEXT
6th Edition
ISBN: 2810016866372
Author: Dale
Publisher: JONES+BART
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Chapter 6, Problem 39E
Explanation of Solution
Program code:
LDA 0X0048,i ;Load character "H" in the accumulator
STA 0X008B,d ;Store contents of accumulator in 8B
CHARO 0X008C,d ;Read character from specified location and ;Write on the screen
LDA 0X0065,i ;Load character "e" in the accumulator
STA 0X008B,d ;Store contents of accumulator in 8B
CHARO 0X008C,d ;Read character from specified location and ;Write on the screen
LDA 0X006C,i ;Load character "l" in the accumulator
STA 0X008B,d ;Store contents of accumulator in 8B
CHARO 0X008C,d ;Read character from specified location and ;Write on the screen
LDA 0X006C,i ;Load character "l" in the accumulator
STA 0X008B,d ;Store contents of accumulator in 8B
CHARO 0X008C,d ;Read character from specified location and ;Write on the screen
LDA 0X006F,i ;Load character "o" in the accumulator
STA 0X008B,d ;Store contents of accumulator in 8B
CHARO 0X008C,d ;Read character from specified location and ;Write on the screen
STOP ;Stop processing
.END ;End program
Explanation:
The above program code is used to write the word “Hello” on the screen by using direct addressing mode.
- In the direct addressing mode, the operand in the instruction contains the address of the data which is needed to load into the accumulator.
- As it follows 16-bit addressing, while writing a character, it writes the next address of the loaded location.
In the program code:
- To write the character “H”,
- It loads the hexadecimal value “(0X0048)” of the character “H” into the accumulator.
- And it stores the content of the accumulator into the specified location “8B”...
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By dragging statements from the left column to the right column below, give a proof by induction of the following statement:
an
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The correct proof will use 8 of the statements below.
Statements to choose from:
Note that a₁ =
9a0 + 8.
Now assume that P(n) is true for all n ≥ 0.
Your Proof: Put chosen statements in order in this
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Let P(n) be the predicate, "a = 9″ – 1".
απ = 90 − 1 =
Note that
Let P(n) be the predicate, "an
9" - 1 is a
solution to the recurrence relation an = 9an-1 +8
with ao = 0."
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Now assume that P(k + 1) is true.
Thus P(k) is true for all k.
Thus P(k+1) is true.
Then ak+1
=
9ak +8, so P(k + 1) is true.
= 1 − 1 = 0, as required.
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This simplifies to
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Chapter 6 Solutions
COMPUTER SCIENCE ILLUMIN.-TEXT
Ch. 6 - Prob. 1ECh. 6 - Prob. 2ECh. 6 - Prob. 3ECh. 6 - Prob. 4ECh. 6 - Prob. 5ECh. 6 - Prob. 6ECh. 6 - Prob. 7ECh. 6 - Prob. 8ECh. 6 - Prob. 9ECh. 6 - Prob. 10E
Ch. 6 - Prob. 11ECh. 6 - Prob. 12ECh. 6 - Prob. 13ECh. 6 - Prob. 14ECh. 6 - Prob. 15ECh. 6 - Prob. 16ECh. 6 - Prob. 17ECh. 6 - Prob. 18ECh. 6 - Prob. 19ECh. 6 - Prob. 20ECh. 6 - Prob. 21ECh. 6 - Prob. 22ECh. 6 - Prob. 23ECh. 6 - Prob. 24ECh. 6 - Prob. 26ECh. 6 - Prob. 27ECh. 6 - Prob. 28ECh. 6 - Prob. 29ECh. 6 - Prob. 30ECh. 6 - Prob. 31ECh. 6 - Prob. 32ECh. 6 - Prob. 33ECh. 6 - Prob. 34ECh. 6 - Prob. 35ECh. 6 - Prob. 36ECh. 6 - Prob. 37ECh. 6 - Prob. 38ECh. 6 - Prob. 39ECh. 6 - Prob. 40ECh. 6 - Prob. 41ECh. 6 - Prob. 42ECh. 6 - Prob. 43ECh. 6 - Prob. 44ECh. 6 - Prob. 45ECh. 6 - Prob. 46ECh. 6 - Prob. 47ECh. 6 - Prob. 48ECh. 6 - Prob. 49ECh. 6 - Prob. 50ECh. 6 - Prob. 51ECh. 6 - Prob. 52ECh. 6 - Prob. 53ECh. 6 - Prob. 54ECh. 6 - Prob. 55ECh. 6 - Prob. 56ECh. 6 - Prob. 57ECh. 6 - Prob. 58ECh. 6 - Prob. 59ECh. 6 - Prob. 60ECh. 6 - Prob. 1TQCh. 6 - Prob. 3TQCh. 6 - Prob. 4TQ
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