Physics for Scientists and Engineers, Vol. 1
6th Edition
ISBN: 9781429201322
Author: Paul A. Tipler, Gene Mosca
Publisher: Macmillan Higher Education
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Question
Chapter 6, Problem 30P
(a)
To determine
The SI units of
(b)
To determine
Work done by force when particle moves from
(c)
To determine
The final velocity of particle.
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Check out a sample textbook solutionStudents have asked these similar questions
Suppose that 4 J of work is needed to stretch a spring from its natural length of 36 cm to a length of 46 cm.
(a) How much work (in J) is needed to stretch the spring from 40 cm to 44 cm? (Round your answer to two decimal places.)
1.28
X J
(b) How far beyond its natural length (in cm) will a force of 25 N keep the spring stretched? (Round your answer one decimal place.)
1000
x cm
Suppose that 6 J of work is needed to stretch a spring from its natural length of 32 cm to a length of 43 cm.
(a) How much work (in J) is needed to stretch the spring from 34 cm to 38 cm? (Round your answer to two decimal places.)
J
(b) How far beyond its natural length (in cm) will a force of 50 N keep the spring stretched? (Round your answer one decimal place.)
cm
A spring needs a force of 2 N to compress it 18 cm. How much work is required to stretch the spring 54 cm?
ROUND OFF ANSWER UP TO 2 DECIMAL PLACES. INPUT BOTH THE NUMBER AND THE UNIT (ABBREVIATION OF UNIT ONLY).
Chapter 6 Solutions
Physics for Scientists and Engineers, Vol. 1
Ch. 6 - Prob. 1PCh. 6 - Prob. 2PCh. 6 - Prob. 3PCh. 6 - Prob. 4PCh. 6 - Prob. 5PCh. 6 - Prob. 6PCh. 6 - Prob. 7PCh. 6 - Prob. 8PCh. 6 - Prob. 9PCh. 6 - Prob. 10P
Ch. 6 - Prob. 11PCh. 6 - Prob. 12PCh. 6 - Prob. 13PCh. 6 - Prob. 14PCh. 6 - Prob. 15PCh. 6 - Prob. 16PCh. 6 - Prob. 17PCh. 6 - Prob. 18PCh. 6 - Prob. 19PCh. 6 - Prob. 20PCh. 6 - Prob. 21PCh. 6 - Prob. 22PCh. 6 - Prob. 23PCh. 6 - Prob. 24PCh. 6 - Prob. 25PCh. 6 - Prob. 26PCh. 6 - Prob. 27PCh. 6 - Prob. 28PCh. 6 - Prob. 29PCh. 6 - Prob. 30PCh. 6 - Prob. 31PCh. 6 - Prob. 32PCh. 6 - Prob. 33PCh. 6 - Prob. 34PCh. 6 - Prob. 35PCh. 6 - Prob. 36PCh. 6 - Prob. 37PCh. 6 - Prob. 38PCh. 6 - Prob. 39PCh. 6 - Prob. 40PCh. 6 - Prob. 41PCh. 6 - Prob. 42PCh. 6 - Prob. 43PCh. 6 - Prob. 44PCh. 6 - Prob. 45PCh. 6 - Prob. 46PCh. 6 - Prob. 47PCh. 6 - Prob. 48PCh. 6 - Prob. 49PCh. 6 - Prob. 50PCh. 6 - Prob. 51PCh. 6 - Prob. 52PCh. 6 - Prob. 53PCh. 6 - Prob. 54PCh. 6 - Prob. 55PCh. 6 - Prob. 56PCh. 6 - Prob. 57PCh. 6 - Prob. 58PCh. 6 - Prob. 59PCh. 6 - Prob. 60PCh. 6 - Prob. 61PCh. 6 - Prob. 62PCh. 6 - Prob. 63PCh. 6 - Prob. 64PCh. 6 - Prob. 65PCh. 6 - Prob. 66PCh. 6 - Prob. 67PCh. 6 - Prob. 68PCh. 6 - Prob. 69PCh. 6 - Prob. 70PCh. 6 - Prob. 71PCh. 6 - Prob. 72PCh. 6 - Prob. 73PCh. 6 - Prob. 74P
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- =V.V.) A stone with a mass of 4.00 kg is moving with velocity (6.20î - 1.40ĵ) m/s. (HINT: v² = v (a) What is the stone's kinetic energy (in J) at this velocity? J (b) Find the net work (in J) on the stone if its velocity changes to (8.001 + 4.00ĵ) m/s. Jarrow_forwardA spring needs a force of 7 N to compress it 38 cm. How much work is required to stretch the spring 35 cm? (Work is also equal to elastic potential energy.) ROUND OFF ANSWER UP TO 2 DECIMAL PLACES. INPUT BOTH THE NUMBER AND THE UNIT (ABBREVIATION OF UNIT ONLY).arrow_forwardIn physics, the work done on an object is equal to the integral of the force on that object dotted with its displacent. This looks like W = |(F-ds) (W is work, F is force, and ds is the infinitesimally small displacement vector). For a force whose direction is the line of motion, the equation becomes W = /(Fdz). If the force on an object as a function of displacement is F(z) = 3z² + z, what is the work as a function of displacement W(z)?Assume W(0) = 0 and the force is in the direction of the object's motion.arrow_forward
- If 6 J of work are needed to stretch a spring from 6 cm to 8 cm and 10 J are needed to stretch it from 8 cm to 10 cm, what is the natural length of the spring? cmarrow_forwardPlease answer the following question(s): 1. (a) What is the average useful power output of a person who does 7.0000 x10 J of useful work in 7.0000 hr? P= (b) Working at this rate, how long will it take this person to lift 2100.0000 kg of bricks up a 1.5000-m platform? Hint: Work done to lift his body can be omitted because it is not considered useful output here. t= Search Submit Answer see other options - If you don't want to answer the question right now View Forum Activities (0 new of 0) Powered by CogBooks f6 1- W f7 ♫+ fg Answering the question(s) helps us recommend your next activity. 99+ O fg বিব f10 f11 DDI f12 {9} harrow_forwardIf a particle is moving, it has kinetic energy. Kinetic energy is the energy of motion, and it depends on the speed and mass of the particle. It is given by the formula Ek = 1/2*mv2, where Ek is the kinetic energy, m is the mass, and v is the speed of the particle. The formula for kinetic energy has some important features to keep in mind. Kinetic energy, and every other type of energy as well, is a scalar quantity, given by only a single number. Energy does not have a "direction", unlike a vector quantity. (This is in contrast to the vector quantity momentum, which you might have already studied.) Kinetic energy, in particular, is always a positive number. (Note the speed v is the magnitude of the vector velocity, and therefore is positive. But even if it were a negative number, squaring it would always lead to a positive result.) Kinetic energy depends on the square of the speed. (This is in contrast to the magnitude of momentum, mv, a quantity you may have already studied, which…arrow_forward
- Asaparrow_forwardA chain 63 meters long whose mass is 28 kilograms is hanging over te edge of a tall building and does not touch the ground. How much work is required to lift the top 10 meters of the chain to the top of the building? Use that the acceleration due to gravity is 9.8 meters per second squared. Please include the correct units.arrow_forwardA weight lifter raises a 963 N weight a vertical distance of 1.87 m. Compute the work done by the force exerted on the weight by the weight lifter.arrow_forward
- Suppose that 6 J of work is needed to stretch a spring from its natural length of 28 cm to a length of 46 cm. (a) How much work (in J) is needed to stretch the spring from 36 cm to 44 cm? (Round your answer to two decimal places.) J (b) How far beyond its natural length (in cm) will a force of 35 N keep the spring stretched? (Round your answer one decimal place.) cm Need Help? Read It Watch Itarrow_forwardAccording to the law of conservation energy, total mechanical energy of an isolated system is a constant. For example, if an object of mass 'm' falls down from a height 'h', it's gravitational potential energy (PE) at the top equals it's kinetic energy (KE) as it reaches the ground. mgh = mv² Here 'v' is the final velocity of the object. Use the dimensional analysis to check the correctness of this equation. (Please submit your answer on paper and no need to submit it in Moodle). Answer:arrow_forwardThe work done on an object is equal to the integral of the force on that object dotted with its displacent. This looks like W=∫(F.ds) (W is work, F is force, and ds is the infinitesimally small displacement vector). For a force whose direction is the line of motion, the equation becomes W=∫(Fdx). If the force on an object as a function of displacement is F(x)=3x2+x, what is the work as a function of displacement (using calculus application) W(x)? Assume W(0)=0 and the force is in the direction of the object's motion.arrow_forward
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