Explanation Given data: The speed ( v ) of the sports car is 75 mph . The radius ( r ) of curvature is 525 m . Formula used: Formula to calculate the apparent weight at the top of the hill is given by, w app = w − m v 2 r (1) Here, w is the true weight or the normal weight, r is the radius of curvature, v is the speed of the sports car, and m is the mass of the vehicle. Formula to calculate the true weight or the normal weight is given by, w = m g (2) Here, g is the gravitational acceleration, and m is the mass of the vehicle. Explanation: Find the fraction of your normal weight is your apparent weight as you crest the hill. Substitute 9.8 m s 2 for g in equation (2), w = m ( 9.8 m s 2 ) (3) Substitute m g for w in equation (1), w app = m g − m v 2 r = m ( g − v 2 r ) (4) Substitute 9.8 m s 2 for g , 75 mph for v and 525 m for r in equation (4), w app = m ( ( 9.8 m s 2 ) − ( 75 mph ) 2 525 m ) (5) Take the unit conversion for mph, 1 mph = 0

4th Edition

ISBN: 8220106755235

Author: Field

Publisher: PEARSON

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Question

Chapter 6, Problem 29P

To determine

The fraction of your normal weight is your apparent weight as you crest the hill.

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Chapter 6, Problem 28P

Chapter 6, Problem 30P

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* Coulomb's Law Example Three charges are positioned as seen below. Charge 1 is +2.0 μC and charge 2 is +8.0μC, and charge 3 is - 6.0MC. What is the magnitude and the direction of the force on charge 2 due to charges 1 and 3? 93 kq92 F == 2 r13 = 0.090m 91 r12 = 0.12m 92 Coulomb's Constant: k = 8.99x10+9 Nm²/C² ✓

Make sure to draw a Free Body Diagram as well

Chapter 6 Solutions

EBK COLLEGE PHYSICS

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