In recent years, scientists have discovered hundreds of planets orbiting other stars. Some of these planets are in orbits that are similar to that of earth, which orbits the sun ( M sun = 1.99 × 10 30 kg) at a distance of 1.50 × 10 11 m, called 1 astronomical unit (1 au). Others have extreme orbits that are much different from anything in our solar system. Problems 47–49 relate to some of these planets that follow circular orbits around other stars. 49. Kepler-42c orbits at a very close 0.0058 au from a small star with a mass that is 0.13 that of the sun. How long is a “year” on this world?
In recent years, scientists have discovered hundreds of planets orbiting other stars. Some of these planets are in orbits that are similar to that of earth, which orbits the sun ( M sun = 1.99 × 10 30 kg) at a distance of 1.50 × 10 11 m, called 1 astronomical unit (1 au). Others have extreme orbits that are much different from anything in our solar system. Problems 47–49 relate to some of these planets that follow circular orbits around other stars. 49. Kepler-42c orbits at a very close 0.0058 au from a small star with a mass that is 0.13 that of the sun. How long is a “year” on this world?
In recent years, scientists have discovered hundreds of planets orbiting other stars. Some of these planets are in orbits that are similar to that of earth, which orbits the sun (Msun = 1.99 × 1030 kg) at a distance of 1.50 × 1011 m, called 1 astronomical unit (1 au). Others have extreme orbits that are much different from anything in our solar system. Problems 47–49 relate to some of these planets that follow circular orbits around other stars.
49. Kepler-42c orbits at a very close 0.0058 au from a small star with a mass that is 0.13 that of the sun. How long is a “year” on this world?
What is the resistance (in (2) of a 27.5 m long piece of 17 gauge copper wire having a 1.150 mm diameter?
0.445
ΧΩ
Find the ratio of the diameter of silver to iron wire, if they have the same resistance per unit length (as they might in household wiring).
d.
Ag
dFe
= 2.47
×
Find the ratio of the diameter of silver to iron wire, if they have the same resistance per unit length (as they might in household wiring).
d
Ag
= 2.51
dFe
×
Genetic Analysis: An Integrated Approach (3rd Edition)
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