To determine (a) The tension in the cable (b)The net workdone on the load (c) The work done by the cable on the load (d) The work done by gravity on the load (e) The final speed of the load if it started from rest. Explanation Free body diagram for given problem is Given : Acceleration a = 0.160 g = ( 0.160 ) ( 9 .8 m/ s 2 ) = 1.568 m/s 2 Mass, m = 265 kg Distance, d = 18 m a) To calculate the tension in the cable, we must use Newton's second law here. We have the force of gravity downward and force due to acceleration upward is F = m a F = m × ( g + a ) F = 265 × ( 9.8 + 1.568 ) F = 3012.5 N The tension in the cable is 3012.5 N b) The net force and the distance that the load has traveled because of that force to find the net work done. F n e t = m a F n e t = 265 × 1.568 N F n e t = 415.52 N Now net work done is W n e t = F n e t × d W n e t = 415.52 × 18 J W n e t = 7479.36 J The net work done on the load is 7479.36 J c) To find the work done by the cable only, we need to use the force that the cable applied on the load. This is the force of tension on the cable. W = F × d W = 3012.5 × 18 W = 54 , 225 J To find the work done by the cable is 54225 J d) The work done by gravity is W = − F g × d W = − m × g × d W = − 265 × 9

7th Edition

ISBN: 9780321625922

Author: Douglas C. Giancoli

Publisher: Addison-Wesley

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Chapter 6, Problem 25P

To determine

(a) The tension in the cable

(b)The net workdone on the load

(c) The work done by the cable on the load

(d) The work done by gravity on the load

(e) The final speed of the load if it started from rest.

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Chapter 6, Problem 24P

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